text: 
  # compare_versions.py
  # software library for question B
  
  def compare_versions(string1, string2):
      seperator = "."
      # first load the strings and then seperate the individual numbers into a list by
      # using the split function
      string1 = string1.split(seperator)
      string2 = string2.split(seperator)
  
      # loop through all the version levels
      for level in range(0, len(string1)):
          # if the current two levels are equal, then continue in the loop
          if string1[level] == string2[level]:
              continue
              # if all the levels are the same, then return that the versions are equal
              return print("Version %s is equal to version %s. " %(seperator.join(string1), seperator.join(string2)))
  
  
          # if the current level of string1 one is higher than string 2, return
          # string 1
          elif string1[level] > string2[level]:
              return print("Version %s is greater than %s. " %(seperator.join(string1), seperator.join(string2)))
              break
          # else, return string2
          else:
              return print("Version %s is greater than %s. " %(seperator.join(string2), seperator.join(string1)))
              break
  
  
  # Another cool way to answer this question:
  # Use python tuples! There is built in logic when comparing them
  
  def compare_tuples(string1, string2):
      seperator = "."
      # convert the strings to tuples
      string1 = tuple(string1.split(seperator))
      string2 = tuple(string2.split(seperator))
  
      # compare the tuples to each other and return whichever one is greater
      if (string1 == string2):
          return print("Version %s is equal to version %s. " %(seperator.join(string1), seperator.join(string2)))
      elif string1 > string2:
          return print("Version %s is greater than %s. " %(seperator.join(string1), seperator.join(string2)))
      else:
          return print("Version %s is greater than %s. " %(seperator.join(string2), seperator.join(string1)))
  