text: 
  # Day 2: More Dice
  In a single toss of 2 fair (evenly-weighted) six-sided dice, find the probability that the values rolled by each die will be different and the two dice have a sum of 6.
  = P(1,5) + P(2,4) + P(4,2) + P(5,1)
  = (1/6*1/6) + (1/6*1/6) + (1/6*1/6) + (1/6*1/6)
  = 4/36
  = 1/9
  Answer: 1/9
  