text: '''
  The stock span problem is a financial problem where we have a series of n daily 
  price quotes for a stock and we need to calculate span of stock's price for all n days.
  
  The span Si of the stock's price on a given day i is defined as the maximum 
  number of consecutive days just before the given day, for which the price of the stock 
  on the current day is less than or equal to its price on the given day.
  '''
  from __future__ import print_function
  def calculateSpan(price, S): 
        
      n = len(price) 
      # Create a stack and push index of fist element to it 
      st = []  
      st.append(0) 
    
      # Span value of first element is always 1 
      S[0] = 1 
    
      # Calculate span values for rest of the elements 
      for i in range(1, n): 
            
          # Pop elements from stack whlie stack is not 
          # empty and top of stack is smaller than price[i] 
          while( len(st) > 0 and price[st[0]] <= price[i]): 
              st.pop() 
    
          # If stack becomes empty, then price[i] is greater 
          # than all elements on left of it, i.e. price[0], 
          # price[1], ..price[i-1]. Else the price[i]  is 
          # greater than elements after top of stack 
          S[i] = i+1 if len(st) <= 0 else (i - st[0]) 
    
          # Push this element to stack 
          st.append(i) 
    
    
  # A utility function to print elements of array 
  def printArray(arr, n): 
      for i in range(0,n): 
          print (arr[i],end =" ") 
    
    
  # Driver program to test above function 
  price = [10, 4, 5, 90, 120, 80] 
  S = [0 for i in range(len(price)+1)] 
    
  # Fill the span values in array S[] 
  calculateSpan(price, S) 
    
  # Print the calculated span values 
  printArray(S, len(price)) 
  