text: -- 181. Employees Earning More Than Their Managers 
  
  --  The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.
  
  -- +----+-------+--------+-----------+
  -- | Id | Name  | Salary | ManagerId |
  -- +----+-------+--------+-----------+
  -- | 1  | Joe   | 70000  | 3         |
  -- | 2  | Henry | 80000  | 4         |
  -- | 3  | Sam   | 60000  | NULL      |
  -- | 4  | Max   | 90000  | NULL      |
  -- +----+-------+--------+-----------+
  
  -- Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.
  
  -- +----------+
  -- | Employee |
  -- +----------+
  -- | Joe      |
  -- +----------+
  
  --  SQL Schema
  
  -- Create table If Not Exists Employee (Id int, Name varchar(255), Salary int, ManagerId int);
  -- Truncate table Employee;
  -- insert into Employee (Id, Name, Salary, ManagerId) values ('1', 'Joe', '70000', '3');
  -- insert into Employee (Id, Name, Salary, ManagerId) values ('2', 'Henry', '80000', '4');
  -- insert into Employee (Id, Name, Salary, ManagerId) values ('3', 'Sam', '60000', 'None');
  -- insert into Employee (Id, Name, Salary, ManagerId) values ('4', 'Max', '90000', 'None');
  
  # Write your MySQL query statement below
  
  SELECT Name as Employee
  FROM Employee e
  WHERE e.ManagerId IS NOT NULL
      AND e.Salary > (
          SELECT Salary FROM Employee m
          WHERE e.ManagerId = m.Id
      )