text: import os
  
  
  resource_path = os.path.dirname(__file__)
  
  
  def get_resource(*args):
      """ Serves to simple resources access
  
      :param \*args: should contain *subfolder* names and *filename* of
                    resource from resources folder
      :type \*args: list
      """
      return os.path.normpath(os.path.join(resource_path, *args))
  