text: # Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).
  #
  # Return the running sum of nums.
  
  # Input: nums = [1,2,3,4]
  # Output: [1,3,6,10]
  # Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].
  #
  
  class Solution:
      def runningSum(self, nums):
          x = 0
          res = []
          for i in nums:
              x += i
              res.append(x)
          return res
  
  nums = [3,1,2,10,1]
  s = Solution().runningSum(nums)
  print(s)
  