text: # 如果 a+b+c=1000 且 a^2+b^2=c^2（a,b,c 为自然数），如何求出所有a、b、c可能的组合?
  
  import time
  
  start_time = time.time()
  
  for a in range(0, 1001):
      for b in range(0, 1001):
          for c in range(0, 1001):
              print("a:%d, b:%d, c:%d" % (a, b, c))
              if a + b + c == 1000 and a ** 2 + b ** 2 == c ** 2:
                  print("fit---a:%d, b:%d, c:%d" % (a, b, c))
  
  end_time = time.time()
  
  print("cost_time:%d" % (end_time - start_time))
  print("finished")
  