text: # Write a program that will calculate the number of trailing zeros in a factorial of a given number.
  # N! = 1 * 2 * 3 * ... * N
  # Be careful 1000! has 2568 digits...
  # For more info, see: http://mathworld.wolfram.com/Factorial.html
  
  import math
  def zeros(n):
      if n == 0: return 0
  
      kmax = math.floor(math.log(n, 5))
      zeroDigits = 0
  
      for k in range(1, kmax + 1):
          zeroDigits += (n // 5**k)
  
      return zeroDigits
  
  
  
  print(zeros(0), 0, "Testing with n = 0")
  print(zeros(6), 1, "Testing with n = 6")
  print(zeros(30), 7, "Testing with n = 30")