text: // Common approach using a loop and conditionals
  // This one uses modulus 15 as a shortcut for
  // checking for factors of 3 and 5 at the same time.
  
  const fizzBuzz = (max) => {
    for (let i = 1; i <= max; i++) {
      if (i % 15 === 0) {
        console.log("fizzbuzz")
      } else if (i % 3 === 0) {
        console.log("fizz")
      } else if (i % 5 === 0) {
        console.log("buzz")
      } else {
        console.log(i)
      }
    }
  }
  