text: # ---------------------------------------------------------------------------------------
  # -------------------Author : itsjaysuthar ----------------------------------------------
  # ---------------------------------------------------------------------------------------
  l=[] #paste given list here 
  dict = {
      "A": 1, "B": 2, "C": 3, "D": 4, "E": 5,
      "F": 6, "G": 7, "H": 8, "I": 9, "J": 10,
      "K": 11, "L": 12, "M": 13, "N": 14, "O": 15,
      "P": 16, "Q": 17, "R": 18, "S": 19, "T": 20,
      "U": 21, "V": 22, "W": 23, "X": 24, "Y": 25,
      "Z": 26
  }
  a=[]
  for n in range(1,2000):
      a.append((n*(n+1)//2))
  b=[]
  for i in range(0, len(l)):
      sum = 0
      for j in range(0, len(l[i])):
          m = l[i][j]
          k = dict[m]
          sum = sum + k
      b.append(sum)
  count=0
  for i in range(0,len(b)):
      if(b[i] in a):
          count+=1
  
  print(count)