text: /*
  International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so on.
  
  For convenience, the full table for the 26 letters of the English alphabet is given below:
  
  [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
  Now, given a list of words, each word can be written as a concatenation of the Morse code of each letter. For example, "cba" can be written as "-.-..--...", (which is the concatenation "-.-." + "-..." + ".-"). We'll call such a concatenation, the transformation of a word.
  
  Return the number of different transformations among all words we have.
  
  Example:
  Input: words = ["gin", "zen", "gig", "msg"]
  Output: 2
  Explanation:
  The transformation of each word is:
  "gin" -> "--...-."
  "zen" -> "--...-."
  "gig" -> "--...--."
  "msg" -> "--...--."
  
  There are 2 different transformations, "--...-." and "--...--.".
  Note:
  
  The length of words will be at most 100.
  Each words[i] will have length in range [1, 12].
  words[i] will only consist of lowercase letters.
  */
  
  var uniqueMorseRepresentations = function (words) {
    let transformations = {};
    const alphabet = "abcdefghijklmnopqrstuvwxyz";
    const morse = [".-", "-...", "-.-.", "-..", ".", "..-.", "--.", "....", "..", ".---", "-.-", ".-..", "--", "-.", "---", ".--.", "--.-", ".-.", "...", "-", "..-", "...-", ".--", "-..-", "-.--", "--.."]
    for (let j = 0; j < words.length; j++) {
      let currWord = [];
      for (let i = 0; i < words[j].length; i++) {
        let alphaIdx = alphabet.indexOf(words[j][i]);
        currWord.push(morse[alphaIdx])
      }
      console.log(currWord.join(""))
      if (!transformations[currWord.join("")]) {
        transformations[currWord.join("")] = 1
      } else {
        transformations[currWord.join("")] += 1
      }
    }
    return Object.keys(transformations).length;
  };