sure! here is one possible solution:

// A function that converts Fahrenheit to Celsius
function fahrenheitToCelsius(fahrenheit) {
  // Formula: (F - 32) * 5/9 = C
  return (fahrenheit - 32) * 5 / 9;
}

// A function that converts Celsius to Fahrenheit
function celsiusToFahrenheit(celsius) {
  // Formula: (C * 9/5) + 32 = F
  return (celsius * 9 / 5) + 32;
}
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