To implement error handling in the provided pseudo code, I have added try-catch blocks around the entire loop and the print statements. This will prevent the code from crashing if an error occurs. The updated code is as follows:

try: a = 3

while a < 7:
    a = a + 1
    
    try:
        print("The current value of a is:", a)
        
        if a == 5:
            print("a is now 5")
    except Exception as e:
        print("Error occurred while printing:", e)
except Exception as e: print("Error occurred while executing the code:", e)

This code will gracefully handle any errors that occur while executing the loop and printing the statements. It will print the error message if any error occurs and continue executing the remaining code.

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