Sure, here is a beginner's problem to solve for somebody who wants to learn pre-calculus:

* **Solve for the roots of the quadratic equation:**

```
x^2 - 2x + 1 = 0
```

This equation can be solved using the quadratic formula:

```
x = (-b ± √(b^2 - 4ac)) / 2a
```

In this case, a = 1, b = -2, and c = 1. Substituting these values into the quadratic formula, we get:

```
x = (2 ± √((-2)^2 - 4 * 1 * 1)) / 2 * 1
```

Simplifying the expression under the radical, we get:

```
x = (2 ± √(4 - 4)) / 2
```

The square root of 4 - 4 is 0, so we have:

```
x = (2 ± 0) / 2
```

This gives us two possible solutions:

```
x = 1, 1
```

Therefore, the roots of the quadratic equation are 1 and 1.

This is just a simple example of a beginner's problem in pre-calculus. As you progress in your studies, you will encounter more challenging problems that involve trigonometry, logarithms, and other topics. But by starting with simple problems like this, you can build a solid foundation for your understanding of pre-calculus.

Here are some other beginner's problems in pre-calculus:

* Find the slope of the line that passes through the points (2, 3) and (4, 5).
* Find the equation of the circle that has a center at (3, 4) and a radius of 5.
* Solve for the area of the triangle that has vertices (1, 2), (3, 4), and (5, 6).
* Find the value of sin 30°.
* Find the derivative of the function f(x) = x^2.

These are just a few examples, and there are many other beginner's problems in pre-calculus. The best way to find problems that are appropriate for your level of understanding is to talk to your teacher or tutor. They can help you find problems that will challenge you without being too difficult.
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