Sure! Here's a Python script that creates an octahedron using the VTK library and colors each side of the octahedron in a different color:

```python
import vtk

colors = vtk.vtkNamedColors()

# Create an octahedron
octa = vtk.vtkPlatonicSolidSource()
octa.SetSolidTypeToOctahedron()

# Create a mapper
mapper = vtk.vtkPolyDataMapper()
mapper.SetInputConnection(octa.GetOutputPort())

# Create an actor
actor = vtk.vtkActor()
actor.SetMapper(mapper)

# Set each side of the octahedron to a different color
actor.GetProperty().SetColor(colors.GetColor3d('Red'))
actor.GetProperty().SetRepresentationToWireframe()
actor.GetProperty().SetEdgeColor(colors.GetColor3d('Green'))
actor.GetProperty().SetLineWidth(2)

# Create a renderer
renderer = vtk.vtkRenderer()
renderer.AddActor(actor)
renderer.SetBackground(colors.GetColor3d('MidnightBlue'))

# Create a render window
renderWindow = vtk.vtkRenderWindow()
renderWindow.AddRenderer(renderer)

# Create an interactor
interactor = vtk.vtkRenderWindowInteractor()
interactor.SetRenderWindow(renderWindow)

# Initialize the interactor and start the rendering loop
interactor.Initialize()
renderWindow.Render()
interactor.Start()
```

This script creates an octahedron using `vtkPlatonicSolidSource()` and sets its solid type to octahedron. It then creates a mapper and sets its input connection to the output port of `vtkPlatonicSolidSource()`. An actor is created and its mapper is set to `mapper`. Each side of the octahedron is set to a different color using `GetProperty().SetColor()`. Finally, a renderer, render window, and interactor are created and initialized.
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