According to the Master Theorem, for the recurrence T(n) = aT(n/b) + f(n), if f(n) is equal to O(n^c), where c > log_b(a), then T(n) is equal to O(n^c).

In this case, a=4, b=3, and f(n)=n^2, which means that c=2. Since 2 > log_3(4), it follows that T(n) is equal to O(n^2).
spam fails_task lang_mismatch pii not_appropriate hate_speech sexual_content quality toxicity humor helpfulness creativity violence