def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list 
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
        
    Example solution:
    # line 1
    if k == 0:
        # line 2
        return []
    # line 3
    arr.sort()
    # line 4
    ans = arr[k:]
    # line 5
    return ans
    
    """
    # Please print out which line of the above program contains an error. E.g. if the bug is on line 4 then print 4
    # END OF CONTEXT
    print("4")
    # END OF SOLUTION

def check(candidate):

    import io
    from contextlib import redirect_stdout

    f = io.StringIO()
    with redirect_stdout(f):
        candidate([], 1)
    out = f.getvalue().strip('\n')

    assert "4" == out
    for i in range(0, 10):
        if i != 4:
            assert str(i) != out


if __name__ == '__main__':
    check(maximum)
