message: Use a constant to replace 100M
  Summary: Hard to read, and Starlark lacks exponents on int, so define a constant at the top.
diff: # Python: python benchmark.py
  # Rust: starlark benchmark.py
  +REPEAT_100M = 100000000
  +
  +
  # Python = 4.35s, Rust = 0.72s
  def benchmark1():
  - for _x in range(100000000):
  + for _x in range(REPEAT_100M):
  pass
  # Python = 6.08s, Rust = 2.35s
  def benchmark2():
  y = 3
  - for _x in range(100000000):
  + for _x in range(REPEAT_100M):
  y = y * 1
  return y
  @@ -34,7 +37,7 @@ def benchmark2():
  def benchmark3():
  y = 0
  xs = []
  - for _x in range(100000000):
  + for _x in range(REPEAT_100M):
  y = len(xs)
  return y
  @@ -46,7 +49,7 @@ def op4(_x):
  # Python = 9.85s, Rust = 8.4s
  def benchmark4():
  y = 0
  - for x in range(100000000):
  + for x in range(REPEAT_100M):
  op4(x)
  return y
  @@ -58,7 +61,7 @@ def op5(_a, _b, _c, _d, _e, _f, _g, _h):
  # Python = 12.2s, Rust = 13.0s
  def benchmark5():
  y = 0
  - for x in range(100000000):
  + for x in range(REPEAT_100M):
  op5(x, x, x, x, x, x, x, x)
  return y
  @@ -70,7 +73,7 @@ def op6(a, b, c, d, e, f, g, h):
  # Python = 17.1s, Rust = 19.2s
  def benchmark6():
  y = 0
  - for x in range(100000000):
  + for x in range(REPEAT_100M):
  op6(a=x, b=x, c=x, d=x, e=x, f=x, g=x, h=x)
  return y
  