remove nth element from list haskell
Removing the nth element from a list in Haskell
To remove the nth element from a list in Haskell, you can use the
delete function from the
Data.List module. Here's an example:
import Data.List (delete)
removeNth :: Int -> [a] -> [a]
removeNth n xs = delete (xs !! (n-1)) xs
In this example, the
removeNth function takes an index
n and a list
xs as input. It uses the
!! operator to access the nth element of the list (subtracting 1 from the index since lists are zero-indexed), and then uses the
delete function to remove that element from the list.
Note that this implementation assumes that the index
n is within the bounds of the list. If the index is out of bounds, an error will occur. If you need to handle out-of-bounds indices, you can add appropriate error handling to the function.
I hope this helps! Let me know if you have any further questions.
Kuondoa nth kipengele kutoka orodha ya haskell Kuondoa nth kipengele kutoka orodha katika Haskell Kuondoa nth kipengele kutoka orodha katika Haskell, unaweza kutumia kazi kufuta kutoka Data.List moduli. Hapa ni mfano: kuagiza Data.List (kufuta) kuondoaNth :: Int -> [a] -> [a] kuondoaNth n xs = kufuta (xs! ! (n-1)) xs Katika mfano huu, kuondoaNth kazi inachukua index n na orodha xs kama pembejeo. Inatumia! ! Opereta ni kazi ya kuunganisha n-th kipengele cha orodha (kuondoa 1 kutoka index tangu orodha ni zero-indexed), na kisha kutumia kazi ya kufuta kuondoa kipengele hicho kutoka orodha. Kumbuka kwamba utekelezaji huu inachukua kwamba index n ni ndani ya mipaka ya orodha. Kama index ni nje ya mipaka, kosa itatokea. Kama unahitaji kushughulikia nje ya mipaka ya viashiria, unaweza kuongeza sahihi makosa ya kushughulikia kwa kazi. Natumaini hii husaidia! Napenda kujua kama una maswali yoyote zaidi.