instruction: Number of questions per tag, for a given location of the user:.
response: SELECT t.TagName, u.Location, COUNT(*) AS "#_posts_per_tag/location" FROM Posts AS p INNER JOIN PostTags AS pt ON p.Id = pt.PostId INNER JOIN Tags AS t ON t.Id = pt.TagId INNER JOIN Users AS u ON u.Id = p.OwnerUserId WHERE Location LIKE '%' + '##country:string##' + '%' COLLATE latin1_general_ci_ai GROUP BY t.TagName, u.Location ORDER BY COUNT(*) DESC