instruction: SO XPages - Question and Answer users.
response: SELECT DISTINCT Posts.OwnerUserId, Users.DisplayName, Users.DisplayName, Reputation, ProfileImageUrl, AccountId FROM Posts INNER JOIN PostTags ON Posts.ParentId = PostTags.PostId INNER JOIN Users ON Posts.OwnerUserId = Users.Id WHERE Posts.PostTypeId = 2 AND PostTags.TagId IN (66326, 80737, 80738)