instruction: what was the average daily number of patients diagnosed with acq pyloric stenosis in this year?
response: SELECT AVG(t1.c1) FROM (SELECT COUNT(DISTINCT diagnoses_icd.hadm_id) AS c1 FROM diagnoses_icd WHERE diagnoses_icd.icd9_code = (SELECT d_icd_diagnoses.icd9_code FROM d_icd_diagnoses WHERE d_icd_diagnoses.short_title = 'acq pyloric stenosis') AND DATETIME(diagnoses_icd.charttime, 'start of year') = DATETIME(CURRENT_TIME(), 'start of year', '-0 year') GROUP BY STRFTIME('%y-%m-%d', diagnoses_icd.charttime)) AS t1