instruction: Top users by average answer score.
response: SELECT a.OwnerUserId AS "user_link", a.OwnerDisplayName, AVG(CAST(a.Score AS FLOAT)) AS "average_score", SUM(a.Score) AS "total_score", COUNT(a.Id) AS "num_answers" FROM Posts AS a WHERE a.PostTypeId = 2 GROUP BY a.OwnerUserId, a.OwnerDisplayName ORDER BY AVG(a.Score) DESC LIMIT 100