instruction: Histogram of question count vs. user in [identification].
response: WITH tagaskers AS (SELECT DISTINCT OwnerUserId AS "user_id", OwnerUserId AS "user_link", COUNT(OwnerUserId) AS "qcount" FROM Posts INNER JOIN PostTags ON Posts.Id = PostTags.PostId WHERE PostTypeId = 1 AND CommunityOwnedDate IS NULL AND ClosedDate IS NULL AND PostTags.TagId = @tagid GROUP BY OwnerUserId HAVING COUNT(OwnerUserId) > 0) SELECT DISTINCT QCount, COUNT('user_id') AS "askers" FROM tagaskers GROUP BY QCount