instruction: Percent of my answers accepted.
response: SELECT (CAST(COUNT(a.Id) AS FLOAT) / (SELECT COUNT(*) FROM Posts WHERE OwnerUserId = 681865 AND PostTypeId = 2) * 100) AS AcceptedPercentage FROM Posts AS q INNER JOIN Posts AS a ON q.AcceptedAnswerId = a.Id WHERE a.OwnerUserId = 1179880 AND a.PostTypeId = 2