instruction: tell me the average yearly number of patients diagnosed with external ear injury - right since 2105?
response: SELECT AVG(t1.c1) FROM (SELECT COUNT(DISTINCT diagnosis.patientunitstayid) AS c1 FROM diagnosis WHERE diagnosis.diagnosisname = 'external ear injury - right' AND STRFTIME('%y', diagnosis.diagnosistime) >= '2105' GROUP BY STRFTIME('%y', diagnosis.diagnosistime)) AS t1