instruction: Top Answerers by Accepted Percentage.
response: SELECT A.OwnerUserId AS "user_link", (CAST(COUNT(A.Id) AS FLOAT) / (SELECT COUNT(*) FROM Posts WHERE OwnerUserId = A.OwnerUserId AND PostTypeId = 2) * 100) AS AcceptedPercent FROM Posts AS A INNER JOIN Posts AS Q ON Q.AcceptedAnswerId = A.Id WHERE A.PostTypeId = 2 AND (SELECT COUNT(*) FROM Posts WHERE PostTypeId = 2 AND OwnerUserId = A.OwnerUserId) > 100 GROUP BY A.OwnerUserId ORDER BY 'acceptedpercent' DESC LIMIT @N