instruction: For all employees who have the letters D or S in their first name, a bar chart shows the distribution of job_id and the sum of manager_id , and group by attribute job_id, show from high to low by the total number of manager id.
response: SELECT JOB_ID, SUM(MANAGER_ID) FROM employees WHERE FIRST_NAME LIKE '%D%' OR FIRST_NAME LIKE '%S%' GROUP BY JOB_ID ORDER BY SUM(MANAGER_ID) DESC