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system
what is the derivative of x^2 + 2x + 8?
user
the derivative of x^2 + 2x + 8 is 2x + 2. 
 this is because the derivative of x^n is nx^(n-1), and the derivative of a constant is 0. applying these rules to the given function, we get: 
d/dx (x^2 + 2x + 8) = d/dx (x^2) + d/dx (2x) + d/dx (8) 
= 2x + 2(1) + 0 
= 2x + 2 
therefore, the derivative of x^2 + 2x + 8 with respect to x is 2x + 2.
assistant