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Question

# A body weight W Newton at the surface of the earth. Its weight at a height equal to half the radius of the earth will be :W22W34W9W4

A
4W9
B
W2
C
2W3
D
W4
Solution
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#### Given, R=6400km,w=mg⇒g=wmNow the weight of the body at the height is 12Rg′=g(1−dR)So the weight of the body at the 12RW′=W(1−R2R)=WR2R)=W2

12
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