## Trigonometry 7th Edition

Published by Cengage Learning

# Chapter 2 - Section 2.1 - Definition II: Right Triangle Trigonometry - 2.1 Problem Set - Page 63: 55

#### Answer

$\frac{2}{\sqrt 3}$

#### Work Step by Step

To find out exact value of $\csc 60^{\circ}$, considering special triangle- $30^{\circ} - 60^{\circ} - 90^{\circ}$ $\csc 60^{\circ}$ = $\frac{hypotenuse}{side - opposite - 60^{\circ}}$ $\csc 60^{\circ}$ = $\frac{2}{\sqrt 3}$ = $\frac{2}{\sqrt 3}$

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