## Algebra: A Combined Approach (4th Edition)

$9x^{2}-\frac{1}{25}$
Step 1: $(3x-\frac{1}{5})(3x+\frac{1}{5})$ Step 2: $3x(3x+\frac{1}{5})-\frac{1}{5}(3x+\frac{1}{5})$ Step 3: $9x^{2}+\frac{3x}{5}-\frac{3x}{5}-\frac{1}{5}(\frac{1}{5})$ Step 4: $9x^{2}-\frac{1}{25}$
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}