## Example

A window with height equal to 2 m and width equal to 8 m has an overhang with an extension equal to 0.5 m on both sides, gap 0.5 m, and the projection of 1.0 m. If Fw = 0.3, Rb = 0.81, IB = 3.05 MJ/m2, ID = 0.45 MJ/m2, and pG = 0.2, estimate area-average radiation received by the window.

Solution

First, the relative dimensions are estimated. Therefore, e = 0.5/2 = 0.25, w = 8/2 = 4, g = 0.5/2 = 0.25, p = 1.0/2 = 0.5

From what was said previously, Fw_g From Eq. (6.57),

3.05 X 0.81 X 0.3 + 0.45 X 0.40 + (3.05 + 0.45) X 0.2 X 0.5 1.27 MJ/m2
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