Zol Tun Kul
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 May29 accepted Isolating $x$ from $y = (x-1)^2$ May29 comment Isolating $x$ from $y = (x-1)^2$ @HenningMakholm: If I had $\int_{0}^{1}(x)dy$, I would need to isolate the $x$ from my $y = (x-1)^2$ - if I did that, $x$ could be either $-\sqrt{y}+1$ or $\sqrt{y}+1$ and I'd have to do both cases? May29 comment Isolating $x$ from $y = (x-1)^2$ Thanks, I ask because if I have $\int_{0}^{1}(-5y+1)$, I would have to do it twice (one in which $y$ is positive and another when it is negative), right? May29 asked Isolating $x$ from $y = (x-1)^2$ May28 comment If two planes in $\mathbb{R}^3$ pass by the origin, do they necessarily intersect at multiple points? @user3001408: Nice, my entire life was a lie. May28 accepted If two planes in $\mathbb{R}^3$ pass by the origin, do they necessarily intersect at multiple points? May28 asked If two planes in $\mathbb{R}^3$ pass by the origin, do they necessarily intersect at multiple points? May28 accepted Calculating a basis in $\mathbb{R}^4$. May28 asked Calculating a basis in $\mathbb{R}^4$. May28 comment Calculating a basis given some constraints. @David: When I multiplied by $s$, the third term should've been $1$, not the fourth. Ack....... By the way, for this specific method, my basis should always be identical to the solution in the book, right? Or can they differ? May28 asked Calculating a basis given some constraints. May28 accepted Does linear dependency have anything to do when determining a span? May28 comment Does linear dependency have anything to do when determining a span? Thanks! Yeah I couldn't find the right word. What would you have said? May28 comment Does linear dependency have anything to do when determining a span? Ok so, the dimension of $\mathbb{R}^2$ is 2, therefore its basis must have $2$ vectors. Since a basis contains the minimum number of vectors needed to span $\mathbb{R}^2$, any set of vectors that supposedly span $\mathbb{R}^2$ must have, as a minimum, 2 vectors. Then $\{(1,1),(2,2)\}$ can't be a span because it has only one significant vector, whereas it needs at least 2, right? So a set of 3 vectors can span $\mathbb{R}^2$, as long as two of its vectors are linearly independent, yes? May28 asked Does linear dependency have anything to do when determining a span? May27 asked Proving that a subset is a subspace by showing a scalar combination. May27 accepted When proving if a subset is a subspace, can I prove closure under addition and multiplication in a single proof? May27 comment When proving if a subset is a subspace, can I prove closure under addition and multiplication in a single proof? Reckon this would apply to any problem of this kind, or only certain ones? May27 asked When proving if a subset is a subspace, can I prove closure under addition and multiplication in a single proof? May27 accepted Proving $||\vec{a}+\vec{b}|| = ||\vec{a}-\vec{b}|| \iff \vec{a} \perp \vec{b}$
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