# Find a number whose double is 84 more than its half

find a number whose double is 84 more than its half

find a number whose double is 84 more than its half

Answer: Let’s assume the number is “x”.

According to the problem, “its double is 84 more than its half” can be written as:

2x = (1/2)x + 84

Multiplying both sides by 2 to eliminate the fraction, we get:

4x = x + 168

Subtracting x from both sides, we get:

3x = 168

Dividing both sides by 3, we get:

x = 56

Therefore, the number we are looking for is 56.
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