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Question

# The base of an isosceles triangle measure 24 cm and the area in 60 cm2 find its perimeter.

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Solution

## Let the the triangle be ABC in which D is mid-point of AC AC=24 , therefore AD=12cmArea =60cm2and we know that area of triangle =12×AC×BDthen, 60=12×24×BDBD=5cmNow, by Pythagoras theorem AB2=AD2+BD2AB=13Now perimeter of ΔABC=AB+BC+AC=2AB+AC (two sides of isosceles triangle are equal)Perimeter =26+24=50cm

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