If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B) : GMAT Problem Solving (PS)
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# If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B)

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If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B) [#permalink]

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07 Apr 2006, 10:10
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49% (01:50) correct 51% (00:52) wrong based on 362 sessions

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If $$k\neq{0}$$ and $$k - \frac{3 -2k^2}{k} = \frac{x}{k}$$, then x =

(A) -3 - k^2
(B) k^2 -3
(C) 3k^2 - 3
(D) k - 3 - 2k^2
(E) k - 3 + 2k^2

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-k-0-and-k-3-2k-2-k-x-k-then-x-167913.html
[Reveal] Spoiler: OA

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Andre Crompton
andre.crompton@cit.com

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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B) [#permalink]

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07 Apr 2006, 10:20
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k - ( 3 - 2K^2)/k = x/k

k^2 - ( 3 - 2k^2) = x

k^2 - 3 + 2k^2 = x

x = (3k^2) - 3
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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B) [#permalink]

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07 Apr 2006, 12:23
I dont understand how the -2k^2 became +2k^2

k^2 - ( 3 - 2k^2) = x

k^2 - 3 + 2k^2 = x
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Andre Crompton
andre.crompton@cit.com

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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B) [#permalink]

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07 Apr 2006, 14:10
andrecrompton wrote:
I dont understand how the -2k^2 became +2k^2

k^2 - ( 3 - 2k^2) = x

k^2 - 3 + 2k^2 = x

The brackets open and negative negative make a positive
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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B) [#permalink]

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23 Oct 2014, 17:22
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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B) [#permalink]

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24 Oct 2014, 01:34
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andrecrompton wrote:
If $$k\neq{0}$$ and $$k - \frac{3 -2k^2}{k} = \frac{x}{k}$$, then x =

(A) -3 - k^2
(B) k^2 -3
(C) 3k^2 - 3
(D) k - 3 - 2k^2
(E) k - 3 + 2k^2

$$k - \frac{3 -2k^2}{k} = \frac{x}{k}$$;

Multiply by k: $$k^2 - (3 -2k^2) = x$$;

$$x=3k^2-3$$.

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-k-0-and-k-3-2k-2-k-x-k-then-x-167913.html

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Re: If k≠0 and k-(3-2k^2)/k =x/k, then x= (A) -3-k^2 (B)   [#permalink] 24 Oct 2014, 01:34
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