## Algebra 1

$\frac{2}{3} *(x - 4) = \frac{1}{3} *(2x - 6)$ $\frac{2x}{3} -\frac{8}{3} = \frac{2x}{3} - \frac{6}{3}$ $\frac{2x}{3} -\frac{8}{3} (+\frac{2x}{3})= \frac{2x}{3} - \frac{6}{3} (+\frac{2x}{3})$ $\frac{-8}{3} = \frac{6}{3}$ This last statement is false, thus, there is no solution.
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