# Homework Help: Rotation matrix

1. Mar 30, 2012

### dirk_mec1

1. The problem statement, all variables and given/known data

The rotation matrix below describes a beam element which is rotated around three axes x,y and z. Derive the rotation matrix.

http://img194.imageshack.us/img194/3351/60039512.png [Broken]

http://img808.imageshack.us/img808/159/64794596.png [Broken]

2. Relevant equations
-

3. The attempt at a solution
I can see where the x-values (CXx CYx CZx) come from. They're just the projections of the rotated x-axes (the one with rotation alpha and beta). But I don't understand how the rest is derived can somebody help me?

Last edited by a moderator: May 5, 2017
2. Mar 30, 2012

### HallsofIvy

Rotation about the x-axis through angle $\alpha$ is given by the matrix
$$\begin{bmatrix}1 & 0 & 0 \\ 0 & cos(\alpha) & -sin(\alpha) \\ 0 & sin(\alpha) & cos(\alpha)\end{bmatrix}$$

Rotation about the y-axis through angle $\beta$ is given by the matrix
$$\begin{bmatrix}cos(\beta) & 0 & -sin(\beta) \\ 0 & 1 & 0 \\ sin(\beta) & 0 & cos(\beta)\end{bmatrix}$$

Rotation about the z-axis through angle $\gamma$ is given by the matrix
$$\begin{bmatrix} cos(\gamma) & -sin(\gamma) & 0 \\ sin(\gamma) & cos(\gamma) & 0 \\ 0 & 0 & 1\end{bmatrix}$$

The result of all those rotations is the product of those matrices. Be sure to multiply in the correct order.

3. Mar 30, 2012

### dirk_mec1

I suspect that there's a minus sign somewhere wrongly placed in your matrices Halls, am I correct? I moved the minus sign in your second matrix to the lower sine but there's still something wrong for this is my result:

Code (Text):

[                        cos(a)cos(b),               -sin(b),                           cos(b)sin(a)                ]
[ sin(a)sin(c) + cos(a)cos(c)sin(b)         cos(b)cos(c)         cos(c)*sin(a)sin(b) - cos(a)sin(c) ]
[ cos(a)sin(b)sin(c) - cos(c)sin(a)        cos(b)*sin(c)     cos(a)cos(c) + sin(a)sin(b)sin(c)       ]

Last edited: Mar 30, 2012
4. Mar 30, 2012

### HallsofIvy

No, all of the minus signs are correctly placed. I am, of course, assuming that a positive angle gives a rotation "counterclockwise" looking at the plane from "above"- from the positive axis of rotation.

5. Mar 30, 2012

### dirk_mec1

6. Mar 30, 2012

### D H

Staff Emeritus
Look at your diagram. Are all of those rotations positive by the right hand thumb rule? (Hint: The answer is no.)

Last edited by a moderator: May 5, 2017
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 1, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}