0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# 2x2 – x – 4 = 0

Open in App
Solution

## Given: 2x2 – x – 4 = 0 On comparing this equation with ax2 + bx + c = 0, we get: a = 2, b = –1 and c = –4 For the quadratic equation ax2 + bx + c = 0, we know that the quadratic formula is $x=\frac{-b±\sqrt{{b}^{2}-4ac}}{2a}$ On substituting a = 2, b = –1 and c = –4, we get: $x=\frac{-\left(-1\right)±\sqrt{{\left(-1\right)}^{2}-4×2×\left(-4\right)}}{2×2}\phantom{\rule{0ex}{0ex}}=\frac{1±\sqrt{33}}{4}$ Thus, the solution of the given quadratic equation is x = $\frac{1+\sqrt{33}}{4},\frac{1-\sqrt{33}}{4}$.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 3, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}