## Intermediate Algebra (6th Edition)

$\frac{x}{2}$
$\sqrt[4] (\frac{x^{4}}{16})=\frac{x}{2}$, because $(\frac{x}{2})^{4}=\frac{x}{2}\times\frac{x}{2}\times \frac{x}{2}\times \frac{x}{2}=\frac{x^{1+1+1+1}}{2\times2\times2\times2}=\frac{x^{4}}{16}$
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