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Calculate how many times more...

# Calculate how many times more intense is 90 dB sound compared to 40 dB sound?

Updated On: 27-06-2022

Text Solution

Solution : Given Data: L=log(I)/(I_(0))=logI-logI_(0) <br> We get 90 dB = 9B=logI_(1)-logI_(0) ...(1) <br> 40dB=4B=logI_(2)-logI_(0) ...(2) <br> Subtract (2) from (1) <br> -50dB=5B=logI_(1)-logI_(2) <br> 5=log_(10)((I_(1))/(I_(2))) <br> (I_(1))/(I_(2))=10^(5)
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