## Algebra and Trigonometry 10th Edition

$\dfrac{4}{9}$
Need to solve $12(-x)^3$ Plug the value of $x=-\dfrac{1}{3}$ in $12(-x)^3$ $12(-x)^3=12[-(-\dfrac{1}{3})]^3$ and $(12) \cdot (\dfrac{1}{27})=\dfrac{4}{9}$
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