# Find determinant

• Feb 19th 2010, 06:39 PM
DarK
Find determinant
$det(2A^8 B^{-1})$

I tried to break it up but I'm not sure where the 2 goes.

$det(2A^8) det(B^{-1})$ ?

Any help is appreciated!
• Feb 19th 2010, 08:17 PM
math2009
$
\det(2A^{8}B^{-1})=
2^{3}\det(A^{8})\det(B^{-1})=
8\frac{\det(A)^{8}}{\det(B)}=
8\frac{ (-1)^{8}}{-2} = -4
$
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