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Lv 6

# 流體力學Fluid mechanics

12abs洗吾洗轉做Gauge 計?

### 1 個解答

• 天同
Lv 7
6 年前
最愛解答

On the level between x and y, consider the left tube of the manometer (i.e. the closed end one).

Pressure at this level = pressure on oil surface of tank = 35k Pa

But from the manometer tube, pressure = [12k + (900)gx] Pa

where 900 kg/m^3 is the density of oil

g is the acceleration due to gravity

Hence, 35k = 12k + (900)gx

i.e. 23 = 0.9gx

x = 23/[(0.9).(9.81)] m = 2.605 m

On the level marked by the lower horizontal line,

pressure on the left manometer tube

= [35k + (y+1.2).(900).g] Pa

Pressure on the right manometer tube

= [100k + (1.2).(13600)g] Pa

Hence, [35k + (y+1.2).(900).g] = [100k + (1.2).(13600)g]

(0.9).(9.81)y + (1.2).(9.81).(0.9) = 65 + (1.2).(13.6).(9.81)

y = 24.3 m

2014-06-23 07:34:17 補充：
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