+0

A town has a population of 12000 and grows at 3.5% every year. What will be the population after 7 years, to the nearest whole number?

0
553
6

A town has a population of 12000 and grows at 3.5% every year. What will be the population after 7 years, to the nearest whole number?

Feb 7, 2021

#1
0

A town has a population of 12000 and grows at 3.5% every year. What will be the population after 7 years, to the nearest whole number?

When you start with 12,000 and add 3.5%, after the 1st year you have (12,000) • (1.035)

Then you start with that new amount and add 3.5%, so after the 2nd year you have [(12,000) • (1.035)] • (1.035)

You can continue that progression to demonstrate that after "n" years, you will have (12,000) • (1.035)n

So after 7 years, the population will be (12,000) • (1.035)7

You can multiply that out by hand or use a scientific calculator to get the answer 15,267.

.

Feb 7, 2021
#2
+268
+4

Nice!!! 👍

IhaveOBJD  Feb 7, 2021
#5
0

Thank you.

Guest Feb 7, 2021
#3
0

= 12000 (1 + .035)= ~ 15 267

Feb 7, 2021
#4
0

To be sure, 15,267.35 ...  what is .35 of a person? ... maybe there's an expectant mother about 3 months along ....

Guest Feb 7, 2021
#6
0

Question said to round to the nearest whole number, Silly !

Guest Feb 7, 2021
{"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}