Question

# Find the remainder using remainder theorem, when:3x3+4x2−5x+8 is divided by x−1

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Solution

## According to remainder theorem, when f(x) is divided by (x−1), Remainder =f(1)f(x)=3x3+4x2−5x+8f(1)=3(1)3+4(1)2−5(1)+8=3+4−5+8=10∴ Remainder=10

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