+0

# card probability

0
77
1

there are two packs of cards each contain 52cards. one card is drawn from each pack. find the probability that at least one of them will be the ace of hearts.​

Feb 19, 2021

#1
+909
0

We should use complemetary counting to solve this.

So what's the probability that neither will be the ace of hearts.

51/52*50/51 = 50/52 = 25/26

1-25/26 = 1/26

So the probability that at least one if the ace of hearts is 1/26.

=^._.^=

Feb 19, 2021
{"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}