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# Determine whether the expression $ir^2x\sqrt{y}$ is rational

Go!
Go!
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true

## Step-by-step Solution

Problem to solve:

$rational\left(i r^2\cdot x\sqrt{y}\right)$
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Apply the formula: $\mathrm{rational}\left(a\right)$=true, where $a=ir^2x\sqrt{y}$

true

$rational\left(i r^2\cdot x\sqrt{y}\right)$
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