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Question

# Moving at 50 kmph, a person reaches his office 10 min late. Next day, he increases his speed and moves at 60 kmph and reaches his office 5 min early. What is the distance from his home to his office?

A
75 km
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B
70 km
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C
80 km
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D
77 km
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Solution

## The correct option is A 75 kmWe can observe that difference in timings on both days is 15 min (and not 5 min, as one day he is late and on the other day he is early)Let the required distance =D km. As time taken at the speed of 50 kmph is more than time taken at 60 kmph, so equation can be formed as D50−D60=1560.Solving this equation,D50−D60=1560⇒60D−50D50×60=1560⇒10D50=15⇒D5=15⇒D=15×5=75∴Distance from his home to his office is 75 km

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