## Intermediate Algebra (12th Edition)

$\dfrac{3}{2k}+\dfrac{7}{2h}-\dfrac{7}{4hk}$
Dividing the denominator to each of the terms of the numerator, the given expression, $\dfrac{24h^2k+56hk^2-28hk}{16h^2k^2} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{24h^2k}{16h^2k^2}+\dfrac{56hk^2}{16h^2k^2}-\dfrac{28hk}{16h^2k^2} \\\\= \dfrac{3}{2k}+\dfrac{7}{2h}-\dfrac{7}{4hk} .\end{array}
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