## Introductory Algebra for College Students (7th Edition)

$\frac{3y}{5}$+$\frac{y}{2}$=$\frac{5y}{4}$-3 20($\frac{3y}{5}$+$\frac{y}{2}$)=20($\frac{5y}{4}$-3) $\frac{60y}{5}$+$\frac{20y}{2}$=$\frac{100y}{4}$-20(3) 12y+10y=25y-60 22y=25y-60 22y-25y=-60 -3y=-60 y=$\frac{-60}{-3}$ y=20
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}