## Algebra 2 (1st Edition)

$$s=3,\:s=-1$$
Solving the equation using the quadratic formula, we find: $$s_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\left(-3\right)}}{2\cdot \:1} \\ s=3,\:s=-1$$ Checking by factoring the expression, we find: $$s\left(s+1\right)-3\left(s+1\right)\\ \left(s+1\right)\left(s-3\right)$$
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 1, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}