It is currently 21 Feb 2018, 21:10

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Steve has 4 pens. The values of the pens are \$2, \$4, \$7, and

Author Message
Manager
Joined: 21 Sep 2008
Posts: 78
Location: Atlanta, Georgia
Schools: Georgetown, UNC, Emory, GeorgiaTech
WE 1: Product Engineering
WE 2: Logistics & Inventory
WE 3: Product Information & Pricing Manager
Steve has 4 pens. The values of the pens are \$2, \$4, \$7, and [#permalink]

### Show Tags

15 Nov 2008, 13:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Steve has 4 pens. The values of the pens are \$2, \$4, \$7, and \$12. Which of the following could NOT be the total value of any collection of these pens?

\$14
\$16
\$17
\$21
\$23
I just can't understand the answer. My answer was D because with four given prices, you can't make 21 dollars.

hoice (A): \$14 = \$12 + \$2. Discard choice (A).

Choice (B): \$16 = \$12 + \$4. Discard choice (B).

Choice (C): \$17. There does not appear any way to obtain a total of \$17. Let's look at the remaining choices to be sure that this choice is the value that cannot be obtained.

Choice (D): \$21 = \$12 + \$7 + \$2. Discard choice (D).

Choice (E): \$23 = \$12 + \$7 + \$4. Discard choice (E).Now that all 4 incorrect answer choices have been eliminated, we know that choice (C) must be correct.

Am I just not thinking hard enough?
 Kaplan GMAT Prep Discount Codes Math Revolution Discount Codes e-GMAT Discount Codes
VP
Joined: 05 Jul 2008
Posts: 1401
Re: Quantative: Kaplan practice question [#permalink]

### Show Tags

15 Nov 2008, 13:57
hwiya320 wrote:
Steve has 4 pens. The values of the pens are \$2, \$4, \$7, and \$12. Which of the following could NOT be the total value of any collection of these pens?

\$14
\$16
\$17
\$21
\$23
I just can't understand the answer. My answer was D because with four given prices, you can't make 21 dollars.

hoice (A): \$14 = \$12 + \$2. Discard choice (A).

Choice (B): \$16 = \$12 + \$4. Discard choice (B).

Choice (C): \$17. There does not appear any way to obtain a total of \$17. Let's look at the remaining choices to be sure that this choice is the value that cannot be obtained.

Choice (D): \$21 = \$12 + \$7 + \$2. Discard choice (D).

Choice (E): \$23 = \$12 + \$7 + \$4. Discard choice (E).Now that all 4 incorrect answer choices have been eliminated, we know that choice (C) must be correct.

Am I just not thinking hard enough?

Please do not post answers and your doubts as they cut into the thoughts of others. You can start asking Q's once others show their approach. Most of the times, such doubts will be addressed in the responses. If not you are more than welcome to have a discussion.

17 can be obtained if steve had 7 + 2 + 4 +4 So discard C

B T W, the way I understood the Q is Steve has to have 4 pens of some value. He just cannot have all the value in 1 pen or 2 pens with value of 3rd and 4th equal to 0.

16 = 4 X 4

12 = 3 X4 + 2

17 = 2 X4 + 2 + 7

21

23 = 12 + 7 + 2 +2

21 remains
Current Student
Joined: 28 Dec 2004
Posts: 3342
Location: New York City
Schools: Wharton'11 HBS'12
Re: Quantative: Kaplan practice question [#permalink]

### Show Tags

15 Nov 2008, 17:11
kaplan got it wrong it has to be 21..otherwise the question doesnt make sense if he has 4 pens..
SVP
Joined: 29 Aug 2007
Posts: 2467
Re: Quantative: Kaplan practice question [#permalink]

### Show Tags

15 Nov 2008, 17:37
icandy wrote:
hwiya320 wrote:
Steve has 4 pens. The values of the pens are \$2, \$4, \$7, and \$12. Which of the following could NOT be the total value of any collection of these pens?

\$14
\$16
\$17
\$21
\$23
I just can't understand the answer. My answer was D because with four given prices, you can't make 21 dollars.

hoice (A): \$14 = \$12 + \$2. Discard choice (A).

Choice (B): \$16 = \$12 + \$4. Discard choice (B).

Choice (C): \$17. There does not appear any way to obtain a total of \$17. Let's look at the remaining choices to be sure that this choice is the value that cannot be obtained.

Choice (D): \$21 = \$12 + \$7 + \$2. Discard choice (D).

Choice (E): \$23 = \$12 + \$7 + \$4. Discard choice (E).Now that all 4 incorrect answer choices have been eliminated, we know that choice (C) must be correct.

Am I just not thinking hard enough?

Please do not post answers and your doubts as they cut into the thoughts of others. You can start asking Q's once others show their approach. Most of the times, such doubts will be addressed in the responses. If not you are more than welcome to have a discussion.

17 can be obtained if steve had 7 + 2 + 4 +4 So discard C

B T W, the way I understood the Q is Steve has to have 4 pens of some value. He just cannot have all the value in 1 pen or 2 pens with value of 3rd and 4th equal to 0.

16 = 4 X 4

12 = 3 X4 + 2

17 = 2 X4 + 2 + 7

21

23 = 12 + 7 + 2 +2

21 remains

D. 21 is convincing...

I was understanding the problem differently as the question is ambigious........
_________________

Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html

GT

Manager
Joined: 21 Sep 2008
Posts: 78
Location: Atlanta, Georgia
Schools: Georgetown, UNC, Emory, GeorgiaTech
WE 1: Product Engineering
WE 2: Logistics & Inventory
WE 3: Product Information & Pricing Manager
Re: Quantative: Kaplan practice question [#permalink]

### Show Tags

16 Nov 2008, 18:48
icandy wrote:

Please do not post answers and your doubts as they cut into the thoughts of others. You can start asking Q's once others show their approach. Most of the times, such doubts will be addressed in the responses. If not you are more than welcome to have a discussion.

I'll remember to do that next time. I was just so frustrated after getting problems wrong.
Manager
Joined: 30 Sep 2008
Posts: 111
Re: Quantative: Kaplan practice question [#permalink]

### Show Tags

17 Nov 2008, 01:40
Choice C is correct and the explanation is very clear

17 = 7 + 2 + 4 +4

Steve has 4 pens and these pens have different prices, 2, 4, 7, 12. There are no 2 pens which have the same price \$4.

21 = 12 + 7 + 2 <==correct
Re: Quantative: Kaplan practice question   [#permalink] 17 Nov 2008, 01:40
Display posts from previous: Sort by

# Steve has 4 pens. The values of the pens are \$2, \$4, \$7, and

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.
{"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}