## College Algebra 7th Edition

$131p+140$
Number of pennies: $p$ Number of nickels: $2p$ Number of dimes: 4 + # of nickels = $4+2p$ Number of quarters: # of dimes + # of nickels = $2p+(4+2p)=4+4p$ Total change in cents : # of pennies + 5* # of nickels + 10 * # of dimes + 25 * # of quarters: $p+5(2p)+10(4+2p)+25(4+4p)=p+10p+40+20p+100+100p=131p+140$
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