# math

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How would you solve for x in this equation:
(x^2-9)(2x-1)=0

• math -

For the problem, a value of x which makes a factor 0 is a solution.
(x^2-9)(2x-1) = 0
factoring (x^2-9) further
(x+3)(x-3)(2x-1) = 0
For each factor, what value of x will make the term 0?
The first term, (x+3), will be 0 for x=-3.
The second term is 0 for x=?
The third term is 0 for x=?
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