## Intermediate Algebra (12th Edition)

a) $x=\dfrac{C-B}{A}$ b) $A=\dfrac{C-B}{x}$
a) Using the properties of equality, in terms of $x ,$ the given formula, $Ax+B=C ,$ is equivalent to \begin{array}{l}\require{cancel} Ax=C-B \\\\ x=\dfrac{C-B}{A} .\end{array} b) Using the properties of equality, in terms of $A ,$ the given formula, $Ax+B=C ,$ is equivalent to \begin{array}{l}\require{cancel} Ax=C-B \\\\ A=\dfrac{C-B}{x} .\end{array}
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