HomeEnglishClass 12PhysicsChapterTest 4

Two discs A and B have same ma...

# Two discs A and B have same mass and same thickness. If d_1 and d_2 are the densities of the materials of the discs A and B respectively, then the ratio of the moment of inertia of the discs A and B about their geometrical axis is

Updated On: 17-04-2022

Get Answer to any question, just click a photo and upload the photo
and get the answer completely free,

Text Solution

frac{d_1^2}{d_2^2}frac{d_2^2}{d_1^2}frac{d_1}{d_2}frac{d_2}{d_1}

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

Transcript

hello students question 2 days A and B have same mass and thickness if D1 and D2 are the densities of the materials of the disc A and B respectively in the ratio of the moment of inertia of the disc A and B about the geometrical axis is ok so here it is given that we have to this ok this is Disc a injustice disc be ok given that these two disc have same mass so latest take their mass is equals to am ok the radius of this disk is equals to R1 interest is equal to or to rent cities of this given HD 122 ok now we have to find the ratio of moment of inertia of disc and about the

geometrical access so the geometrical axis of a disk is the axis which is passing through the centre of the disc and perpendicular to the plane of the distal end we know the moment of inertia of a disc about its geometrical axis is equals to 1 by 2 and that is its mass into its radius square ok so it is the formula for moment of inertia of disc about its geometrical access ok so we can ratio of moment of inertia of these two days by using this formula ok but we don't have the relation between their radius ok so first of all we will find the relation between their radii is ok so here it is given that these two disc have same mass ok so much of this a is equals to mass of this be ok and we know the mass is given by

density into volume ok so we will write the densities for Disc a and the volume for Disc a and compared with that of B ok the density of this is given T1 ok into the volume of this disk is equals to area into its thickness ok so area for this test will be given by Y into our Square X latest take the thickness of this is equal and in question it is given that both these have security to the thickness of this is also it comes to T ok so I will be area into thickness now this is the mass of this way and it should be equal to mass of disc be ok show the density of disc

psd2 into its area will be fired to square into thickness is same that is T ok now spy interest I will get cancel out this tea industry will get cancel out and we have urban square divided by 8 square is equals to DT upon this is the relation between these two now we have to find the moment of inertia of a to that of B ok that means we have to find the ratio of the formula for moment of inertia about geometrical Axis OK it is half M R square ideas for Disc is equals to R1 square divided by half mr2 spyder ok this is the moment of inertia of disc be now both have same mass

that is why this will get cancel out ok bye have the ratio of moment of inertia is equal to square divided by 8 to square A and B have calculated this above sd2 by the 12 the ratio of moment of inertia about geometrical axis is given by De to Gai even so this is our answer this question thank you
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 1, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}