## BrainsNThings 2 years ago Solve for x, Show your work

1. BrainsNThings

$\sqrt{x+2}+4=x$

2. ajprincess

The first step u have to do in problems like this is to get rid of the sqrt. this can be done by squaring both sides. $$\sqrt{x+2}+4=x$$ $$\sqrt{x+2}=x-4$$ $$(\sqrt{x+2})^2=(x-4)^2$$ $$x+2=x^2-8x+16$$ $$x^2-8x-x+16-2=0$$ $$x^2-9x+14=0$$ Use quadratic formula to find x. $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ the values of a, b nd c can be found by comparing the equation $$x^2-9x+14=0$$ with the general equation $$ax62+bx+c=0$$. Does that help? @BrainsNThings

3. ajprincess

*$$ax^2+bx+c=0$$
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 1, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}