## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$a^{10}|a|$
Using $\sqrt{x^2}=|x|$, the given expression, $\sqrt{a^{22}} ,$ simplifies to \begin{array}{l} \sqrt{(a^{11})^2} \\\\= |a^{11}| \\\\= |a^{10}\cdot a| \\\\= a^{10}|a| .\end{array}
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