I am thinking of a five digit number such that: First and last digits are same.............What number I am thinking of?

–1 vote
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I am thinking of a five digit number such that:
First and last digits are same, their submission is an even number and multiplication is an odd number and is equal to the fourth number. Subtract five from it and we obtain the second number. Then divide into exact half nd we get 3rd number.

What number I am thinking of?

posted Dec 8, 2015

1st digit =3
5th digit=3
4th digit =3*3=9
2nd digit =9-5=4
3rd digit =4/2=2

so ans is 34293

answer Dec 8, 2015

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+1 vote

I'm a 5 digit number,
the first and last digits are the same and add up to an even number.
Multiply that number by its self and the number is under 10 and odd.
That will be the fourth number.
Subtract five from it and it will be the second number.
Divide it in half and that is my third number.

What am I?

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The product of the first and last digits is less than 49.
The sum of the first two digits is less than 16.
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The sum of the digits is greater than 6.
The difference of the last two digits is equal to 2.
The sum of the last two digits is equal to 6.
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