# 1979 AHSME Problems/Problem 2

## Solution

Moving all variables to one side of the equation, we can use Simon's Favorite Factoring Trick to factor the equation into $$(x+1)(y-1) = -1$$ Plugging in $-1$ and $1$ as the $x$ and $y$ sides respectively, we get $x = -2$ and $y = 2$. Plugging this in to $\frac{1}{x}-\frac{1}{y}$ gives us $\boxed{-1}$ as our final answer.
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