# find the x-intercept and y-intercept of a line

3x-2y=6 ; can someone show me step by step how to solve this equation.

Givenline equation 3x-2y = 6

To find x-intercept substitute y = 0 in equation.

3x = 6

Divide to each side by 3.

x = 2

To find y-intercept substitute x = 0 in equation.

-2y = 6

Divide to each side by negitive 2.

y = -3

x-intercept is 2 and y-intercept is -3.

The intercept form of a line equation is x/a + y/b = 1, where, a is x - intercept,  and b is y - intercept.

The equation is 3x - 2y = 6.

Write the equation in intercept - form.

3x/( 6) - 2y/(6) = 1

x/(6/3) - y/(6/2) = 1

x/2 + y/(- 3) = 1.

Compare the above equation with, intercept form of a line equation.

x - intercept is 2, and y - intercept is - 3.
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