#### Q: 4     In Fig. , P is a point in the interior of a parallelogram ABCD. Show that             (ii)              [Hint : Through P, draw a line parallel to AB.]

We have a ||gm ABCD and AB || CD, AD || BC.  Through P, draw a line parallel to AB
Now, APD and ||gm ADGHare on the same base AD and between the same parallels GH and AD.
Therefore, ar (APD) = 1/2 . ar(||gm ADGH).............(i)

Similarily, ar (PBC) = 1/2 . ar(||gm BCGH)............(ii)

By adding the equation i and eq (ii), we get

Hence proved.
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