## Calculus: Early Transcendentals (2nd Edition)

$x =\frac{\ln 29}{3\ln5}$
$5^{3x} = 29$ $\ln5^{3x} =\ln 29$ $3x\ln5 =\ln 29$ $3x =\frac{\ln 29}{\ln5}$ $x =\frac{\ln 29}{3\ln5}$
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