# Ch-9 : Midband Analysis of Small Signal Amplifiers¶

## Page No. 221 Example 9.1.¶

In [1]:
print "  Exact analysis :"
AI=(-50)/(1+((25*10**-6)*(10**3)))
print "Current gain,  AI = -hfe / 1+hoe*RL = %0.2f"%AI
Ri=1000-((50*2*10**-4)/((25*10**-6)+(1/1000)))  #in ohm
print "Input resistance,  Ri = hie - (hfe*hre / hoe+(1/RL)) = %0.2f ohm"%Ri
Av=(-48.78)*(1000/990.24)
print "Voltage gain,    Av = AI*(RL/Ri) = %0.2f "%Av
Yo=(25*10**-6)-((100*10**-4)/(1000+800))  #in mho
print "      Yo = hoe - (hfe*hre / hie+Rs) = %0.2f mho"%Yo
Ro=1/Yo #in ohm
x1=Ro*10**-3
print "      Ro(k-ohm) = 1/Yo = %0.2f kohm"%x1
print "  Approximate analysis"
print "        AI = -hfe = -50"
print "        Ri = hie = 1 k-ohm"
Av=-(50.*1000)/1000
print "        Av = - hfe*RL / hie = %0.2f"%Av
print "        Ro = infinity"
Exact analysis :
Current gain,  AI = -hfe / 1+hoe*RL = -48.78
Input resistance,  Ri = hie - (hfe*hre / hoe+(1/RL)) = 600.00 ohm
Voltage gain,    Av = AI*(RL/Ri) = -49.26
Yo = hoe - (hfe*hre / hie+Rs) = 0.00 mho
Ro(k-ohm) = 1/Yo = 51.43 kohm
Approximate analysis
AI = -hfe = -50
Ri = hie = 1 k-ohm
Av = - hfe*RL / hie = -50.00
Ro = infinity

## Page No. 223 Example 9.2.¶

In [1]:
RC=2*10**3
hie=1300
hre=2*10**-4
hfe=55
hoe=22*10**-6
print "(i) For RE = 200 ohm,"
RE=200
x=hoe*(RE+RC)
print "      hoe*(RE + RC) = %0.2f "%x
print "Since hoe*(RE+RC) < 0.1, the approximate model is permissible."
AI=-hfe
print "      AI = -hfe = -55"
Ri=hie+((1+hfe)*RE)
x1=Ri*10**-3
print "      Ri = hie + (1+hfe)*RE = %0.2f kohm"%x1
Av=AI*(RC/Ri)
print "      Av = AI * (RC/Ri) = %0.2f "%Av
print "Output resistance, Ro = infinity"
print "Output terminal resistance, RoT = Ro || RC = 2 k-ohm"
print "(ii) For RE = 400 ohm"
RE=400.
x2=hoe*(RE+RC)
print "      hoe*(RE + RC) = %0.2f "%x2
print "Since hoe*(RE+RC) < 0.1, the approximate model is permissible."
AI=-hfe
print "      AI = -hfe = -55"
Ri=hie+((1+hfe)*RE)
x3=Ri*10**-3
print "      Ri(k-ohm) = hie + (1+hfe)*RE = %0.2f kohm"%x3
Av=AI*(RC/Ri)
print "      Av = AI * (RC/Ri) = %0.2f"%Av
print "Output resistance, Ro = infinity"
print "Output terminal resistance, RoT = Ro || RC = 2 k-ohm"
print "(iii) For RE = 1000 ohm"
print "Since hoe*(RE+RC) < 0.1, the approximate model is permissible."
AI=-hfe
print "      AI = -hfe = -55"
Ri=1300+((1+55)*1000)
x3=Ri*10**-3
print "      Ri(k-ohm) = hie + (1+hfe)*RE = %0.2f kohm"%x3
Av=AI*(RC/Ri)
print "      Av = AI * (RC/Ri) = %0.2f "%Av
print "Output resistance, Ro = infinity"
print "Output terminal resistance, RoT = Ro || RC = 2 k-ohm"
(i) For RE = 200 ohm,
hoe*(RE + RC) = 0.05
Since hoe*(RE+RC) < 0.1, the approximate model is permissible.
AI = -hfe = -55
Ri = hie + (1+hfe)*RE = 12.50 kohm
Av = AI * (RC/Ri) = 0.00
Output resistance, Ro = infinity
Output terminal resistance, RoT = Ro || RC = 2 k-ohm
(ii) For RE = 400 ohm
hoe*(RE + RC) = 0.05
Since hoe*(RE+RC) < 0.1, the approximate model is permissible.
AI = -hfe = -55
Ri(k-ohm) = hie + (1+hfe)*RE = 23.70 kohm
Av = AI * (RC/Ri) = -4.64
Output resistance, Ro = infinity
Output terminal resistance, RoT = Ro || RC = 2 k-ohm
(iii) For RE = 1000 ohm
Since hoe*(RE+RC) < 0.1, the approximate model is permissible.
AI = -hfe = -55
Ri(k-ohm) = hie + (1+hfe)*RE = 57.30 kohm
Av = AI * (RC/Ri) = 0.00
Output resistance, Ro = infinity
Output terminal resistance, RoT = Ro || RC = 2 k-ohm

## Page No. 225 Example 9.3.¶

In [2]:
RS=900.
RL=2000.
hie=1200.
hre=2*10**-4
hfe=60.
hoe=25*10**-6
print "Conversion formulae :"
hic=hie
print "      hic = hie = 1200 ohm,"
hfc=-(1+hfe)
print "      hfc = -(1+hfe) = %0.2f "%hfc
print "hre = 1, hoc = hoe = 25 uA/V"
hoc=hoe
hre=1
print "Exact analysis :"
format(7)
AI=-hfc/(1+(hoc*RL))
print "Current gain,      AI = -hfe / (1 + (hoc*RL)) = %0.2f "%AI
Ri=hic + (hre*AI*RL)
x1=Ri*10**-3
print "Input impedance,      Ri(k-ohm) = hic + hrc*AI*RL = %0.2f kohm"%x1
Av=(AI*RL)/Ri
print "Voltage gain,      Av = AI*RL / Ri = %0.2f "%Av
Yo=hoc-((hfc*hre)/(hic+RS))
print "Output resistance, Ro :"
print "      Yo = 1/Ro = hoc - (hfc*hrc/hic+Rs) =%0.2f  mho"%Yo
Ro=1./Yo
print "      Ro  = %0.2f ohm"%Ro
print "Approximate analysis :"
AI=1+hfe
print "Current gain,      AI = 1 + hfe = %0.2f "%AI
Ri=hie+((1+hfe)*RL)
x2=Ri*10**-3
print "Input impedance,      Ri = hie + (1+hfe)RL = %0.2f kohm"%x2
Av=1-(hie/Ri)
print "Voltage gain,      Av = 1 - hie/Ri = %0.2f "%Av
print "Output resistance,      Ro:"
Yo=(1+hfe)/(hie+RS)
print "      Yo(mho) = (1+hfe) / (hie+RS) = %0.2f mho"%Yo
Ro=1./Yo
print "      Ro = %0.2f ohm "%Ro
Conversion formulae :
hic = hie = 1200 ohm,
hfc = -(1+hfe) = -61.00
hre = 1, hoc = hoe = 25 uA/V
Exact analysis :
Current gain,      AI = -hfe / (1 + (hoc*RL)) = 58.10
Input impedance,      Ri(k-ohm) = hic + hrc*AI*RL = 117.39 kohm
Voltage gain,      Av = AI*RL / Ri = 0.99
Output resistance, Ro :
Yo = 1/Ro = hoc - (hfc*hrc/hic+Rs) =0.03  mho
Ro  = 34.40 ohm
Approximate analysis :
Current gain,      AI = 1 + hfe = 61.00
Input impedance,      Ri = hie + (1+hfe)RL = 123.20 kohm
Voltage gain,      Av = 1 - hie/Ri = 0.99
Output resistance,      Ro:
Yo(mho) = (1+hfe) / (hie+RS) = 0.03 mho
Ro = 34.43 ohm

## Page No. 228 Example 9.4.¶

In [3]:
hic=1.4*10**3
hfc=-100
hrc=1
hoc=20*10**-6
R1=20*10**3
RS=1*10**3
R2=20*10**3
RE=10*10**3
RL=40*10**3
print "Current gain,        AI = -hfc / 1+hoc*RL''"
RLd=(RE*RL)/(RE+RL)
x1=RLd*10**-3
print "where,        RL'' = RE || RL = %0.2f kohm"%x
AI = -hfc / (1+(hoc*RLd))
print "Therefore,  AI = %0.2f "%AI
Ri=hic+(hrc*AI*RLd)
x2=Ri*10**-3
print "Input resistance,        Ri = hic + hrc*AI*RL'' = %0.2f kohm"%x2
Av=(AI*RLd)/Ri
print "Voltage gain,        Av = AI*RL'' / Ri = %0.2f "%Av
print "Output resistance,        Ro = 1 / Yo"
print "        Yo = hoc - (hfc*hrc)/(hic+RS'')"
RSd=(RS*R1*R2)/((R1*R2)+(RS*R2)+(RS*R1))
x3=RSd*10**-3
print "where,        RS'' = RS || R1 || R2 = %0.2f kohm"%x3
Yo = hoc - ((hfc*hrc)/(hic+RSd))
print "        Yo = %0.2f "%Yo
# answer in textbook is wrong
Ro=1/0.0435
print "        Ro = %0.2f ohm"%Ro
Rod=(Ro*RLd)/(Ro+RLd)
print "        Ro'' = Ro || RLdash = %0.2f ohm"%Rod
Current gain,        AI = -hfc / 1+hoc*RL''
where,        RL'' = RE || RL = 0.05 kohm
Therefore,  AI = 86.21
Input resistance,        Ri = hic + hrc*AI*RL'' = 691.06 kohm
Voltage gain,        Av = AI*RL'' / Ri = 1.00
Output resistance,        Ro = 1 / Yo
Yo = hoc - (hfc*hrc)/(hic+RS'')
where,        RS'' = RS || R1 || R2 = 0.91 kohm
Yo = 0.04
Ro = 22.99 ohm
Ro'' = Ro || RLdash = 22.92 ohm

## Page No. 229 Example 9.5.¶

In [4]:
Rs=1200.
RL=1000.
hib=22.
hrb=3*10**-4
hfb=-0.98
hob=0.5*10**-6
print "      Exact analysis"
AI=-hfb/(1+(hob*RL))
print "Current gain,      AI = -hfb / (1 + hob*RL) = %0.2f "%AI
Ri=hib+(hrb*AI*RL)
print "Input impedance,      Ri(ohm) = hib + hrb*AI*RL = %0.2f ohm"%Ri
Av=(AI*RL)/Ri
print "Voltage gain,      Av = AI*RL / Ri = %0.2f "%Av
Avs=(Av*Ri)/(Ri+Rs)
print "Overall current gain,      Avc = Av*Ri / Ri+Rs = %0.2f "%Avs
AIS=(AI*Rs)/(Ri+Rs)
print "Overall current gain,      AIS = AI*Rs / Ri+Rs = %0.2f "%AIS
Yo=hob-((hfb*hrb)/(hib+Rs))
x1=Yo*10**6
print "Output admittance,      Yo(u-mho) = hob * (hfb*hrb / hib+Rs) = %0.2f "%x1
Ro=1/Yo
x2=Ro*10**-6
print "      Ro(M-ohm) = 1 / Yo = %0.2f"%x2
AP=Av*AI
print "Power gain,      AP = Av*AI = %0.2f "%AP
print "Approximate analysis"
AI=-hfb
print "Current gain,      AI = -hfb = %0.2f "%AI
Ri=hib
print "Input impedance,      Ri = hib = %0.2f ohm"%Ri
hfe = -hfb / (1+hfb)
print "Reaaranging this equation,      hfe = -hfb / 1+hfb = %0.2f"%hfe
print "From Table 9.3,      hib = hie / 1+hfe"
hie=hib*(1+hfe)
print "      hie = hib(1+hfe) = %0.2f ohm"%hie
Av=hfe*RL / hie
print "      Av = %0.2f"%Av
print "Output impedance,      Ro = infinity"
Avs=(Av*Ri)/(Ri+Rs)
print "Overall voltage gain,      Avs = Av*Ri / Ri+Rs = %0.2f "%Avs
AIS=(AI*Rs)/(Ri+Rs)
print "Overall current gain,      AIS = AI*Rs / Ri+Rs = %0.2f "%AIS
AP=Av*AI
print "Power gain,      AP = Av*AI = %0.2f"%AP
Exact analysis
Current gain,      AI = -hfb / (1 + hob*RL) = 0.98
Input impedance,      Ri(ohm) = hib + hrb*AI*RL = 22.29 ohm
Voltage gain,      Av = AI*RL / Ri = 43.94
Overall current gain,      Avc = Av*Ri / Ri+Rs = 0.80
Overall current gain,      AIS = AI*Rs / Ri+Rs = 0.96
Output admittance,      Yo(u-mho) = hob * (hfb*hrb / hib+Rs) = 0.74
Ro(M-ohm) = 1 / Yo = 1.35
Power gain,      AP = Av*AI = 43.04
Approximate analysis
Current gain,      AI = -hfb = 0.98
Input impedance,      Ri = hib = 22.00 ohm
Reaaranging this equation,      hfe = -hfb / 1+hfb = 49.00
From Table 9.3,      hib = hie / 1+hfe
hie = hib(1+hfe) = 1100.00 ohm
Av = 44.55
Output impedance,      Ro = infinity
Overall voltage gain,      Avs = Av*Ri / Ri+Rs = 0.80
Overall current gain,      AIS = AI*Rs / Ri+Rs = 0.96
Power gain,      AP = Av*AI = 43.65

## Page No. 230 Example 9.6.¶

In [5]:
hib=24.
hfb=-0.98
hob=0.49*10**-6
hrb=2.9*10**-4
RS=600.
RE=6*10**3
RC=12*10**3
RL=14*10**3
print "Current gain,      AI = -hfb / 1+hob*RL''"
RLd=(RC*RL)/(RC+RL)
x1=RLd*10**-3
print "where,      RL'' = RC || RL = %0.2f kohm"%x1
AI=-hfb / (1+hob*RLd)
print "      AI = %0.2f "%AI
print "Input impedance Ri :"
Ri=hib+(hrb*AI*RLd)
print "      Ri = hib + hrb*AI*RL'' = %0.2f ohm"%Ri
print "Voltage gain Av :"
Av=(AI*RLd)/Ri
print "      Av = (AI*RL'') / Ri = %0.2f "%Av
print "Output Resistance Ro :"
RSd=(RS*RE)/(RS+RE)
Yo=hob-((hfb*hrb)/(hib+RSd))
x4=Yo*10**6
print "      Yo(u-mho) = 1 / Ro = hob - (hfb*hrb / hib+RS'') =       where RS'' = RS || RE = %0.2f u-mho"%x4
Ro=1./Yo
x2=Ro*10**-6
print "      Ro = 1 / Yo = %0.2f M-ohm "%x2
RSd=(Ro*RLd)/(Ro+RLd)
x3=RSd*10**-3
print "      RS'' = Ro || RL'' = %0.2f kohm"%x3
Current gain,      AI = -hfb / 1+hob*RL''
where,      RL'' = RC || RL = 6.46 kohm
AI = 0.98
Input impedance Ri :
Ri = hib + hrb*AI*RL'' = 25.83 ohm
Voltage gain Av :
Av = (AI*RL'') / Ri = 244.36
Output Resistance Ro :
Yo(u-mho) = 1 / Ro = hob - (hfb*hrb / hib+RS'') =       where RS'' = RS || RE = 0.99 u-mho
Ro = 1 / Yo = 1.01 M-ohm
RS'' = Ro || RL'' = 6.42 kohm

## Page No. 232 Example 9.7.¶

In [6]:
hfe=60.
hie=500.
IC=3*10**-3
RB=220*10**3
RC=5.1*10**3
VCC=12.
VBE=0.6
print "From h-parameter model"
beta=hfe
Zo=RC
Av=(-hfe*RC)/hie
print "      Zi = hie = 500 ohm"
print "      Zo = RC = 5.1 k-ohm"
print "      Av = (-hfe*RC) / hie = %0.2f "%Av
print "      AI = -hfe = -60"
print "From re model"
print "      Zi = beta*re      where re = 26mV / Ie"
Ib=(VCC - VBE)/RB
x1=Ib*10**6
print "From the circuit,      Ib = (VCC - VBE) / RB = %0.2f uA"%x1
Ie=beta*(51.8*10**-6)
x2=Ie*10**3
print "      Ie = Ic = beta*Ib = %0.2f mA"%x2
re = (26) / (3.108)
print "      re = 26mV / Ie = %0.2f ohm"%re
Zi = beta*8.37
print "      Zi = beta*re = %0.2f ohm"%Zi
print "      Zo = RC = 5.1 k-ohm"
Av=int(-RC/re)
print "      Av = -RC / re = %0.2f "%Av
print "      AI = -beta = -60"
From h-parameter model
Zi = hie = 500 ohm
Zo = RC = 5.1 k-ohm
Av = (-hfe*RC) / hie = -612.00
AI = -hfe = -60
From re model
Zi = beta*re      where re = 26mV / Ie
From the circuit,      Ib = (VCC - VBE) / RB = 51.82 uA
Ie = Ic = beta*Ib = 3.11 mA
re = 26mV / Ie = 8.37 ohm
Zi = beta*re = 502.20 ohm
Zo = RC = 5.1 k-ohm
Av = -RC / re = -609.00
AI = -beta = -60

## Page No. 233 Example 9.8.¶

In [7]:
hie=3.2*10**3
hfe=100.
R1=40*10**3
R2=4.7*10**3
RC=4*10**3
VCC=16.
VBE=0.6
RE=1.2*10**3
beta=100.
print "h-parameter analysis :"
print "Zi = RB || hie"
RB=(R1*R2)/(R1+R2)
x1=RB*10**-3
print "      RB = R1 || R2 = 40 k-ohm || 4.7 k-ohm = %0.2f "%x1
Zi=(RB*hie)/(RB+hie)
x2=Zi*10**-3
print "      Zi = 4.2 k-ohm || 3.2 k-ohm = %0.2f"%x2
print "      Zo = RC = 4 k-ohm"
Av=(-hfe*RC)/hie
print "      Av = -hfe*RC / hie = %0.2f "%Av
AI=(-hfe*RB)/(RB+hie)
print "      AI = -hfe*RB / RB+hie = %0.2f "%AI
print "Using r model :"
print "To find IB,"
VB=(R2*VCC)/(R1+R2)
print "      VB = R2*VCC / R1+R2 = %0.2f "%VB
print "Using Thevenin equivalent for input part,"
IB=1.082/(125.4*10**3)
x3=IB*10**6
print "IB = (VB-VBE) / (RB+((1+beta)*RE)) = %0.2f uA"%x3
IC=beta*IB
x4=IC*10**3
print "      IC = beta*IB = %0.2f mA"%x4
print "      IE ~ IC = %0.2f mA"%x4
IE = IC
re=(26*10**-3)/(0.86*10**-3)
print re,"      re = 26mV / IE = %0.2f ohm"%re
Zi=(RB*beta*re)/(RB+(beta*re))
x5=Zi*10**-3
print "    Zi = RB || beta*re = %0.2f kohm"%x5
print " Zo = RC = 4 k-ohm"
Av=-RC/re
print "      Av = -RC / re = %0.2f"%Av
AI=(-100*(4.2*10**3))/((4.2*10**3)+(100*30.23))
print "      AI = (-beta*RB) / (RB+(beta*re)) = %0.2f"%AI
h-parameter analysis :
Zi = RB || hie
RB = R1 || R2 = 40 k-ohm || 4.7 k-ohm = 4.21
Zi = 4.2 k-ohm || 3.2 k-ohm = 1.82
Zo = RC = 4 k-ohm
Av = -hfe*RC / hie = -125.00
AI = -hfe*RB / RB+hie = -56.79
Using r model :
To find IB,
VB = R2*VCC / R1+R2 = 1.68
Using Thevenin equivalent for input part,
IB = (VB-VBE) / (RB+((1+beta)*RE)) = 8.63 uA
IC = beta*IB = 0.86 mA
IE ~ IC = 0.86 mA
30.2325581395       re = 26mV / IE = 30.23 ohm
Zi = RB || beta*re = 1.76 kohm
Zo = RC = 4 k-ohm
Av = -RC / re = -132.31
AI = (-beta*RB) / (RB+(beta*re)) = -58.15

## Page No. 235 Example 9.9.¶

In [8]:
VBE=0.6
VEE=8.
VCC=10.
RE=4*10**3
RC=3*10**3
IE=(VEE-VBE)/RE
x1=IE*10**3
print "      |IE| = VEE-VBE / RE = %0.2f mA"%x1
re=(26*10**-3)/IE
print "      re(ohm) = 26mV / IE = %0.2f ohm"%re
Zi=(RE*re)/(RE+re)
print "      Zi = RE || re = %0.2f ohm"%Zi
Zo=RC*10**-3
print "      Zo = RC = %0.2f kohm"%Zo
Av=3000/14.05
print "      Av = RC / re = %0.2f "%Av
print "      AI = 1"
|IE| = VEE-VBE / RE = 1.85 mA
re(ohm) = 26mV / IE = 14.05 ohm
Zi = RE || re = 14.00 ohm
Zo = RC = 3.00 kohm
Av = RC / re = 213.52
AI = 1

## Page No. 238 Example 9.10.¶

In [9]:
print "We know that IB = VCC-VBE / RB+(1+beta)*RE"
IB=((15-0.7)/((75*10**3)+(101*910)))*10**6
print "Therefore,  IB = %0.2f uA"%IB  # in uA
print "IE = (1+beta)*IB = 8.57 mA"
print "The dynamic resistance is"
re=0.026/(8.57*10**-3)
print "    re = %0.2f ohm"% re  # in ohm
print "The input impedance of the amplifier is"
zb=(101*(3.03+910))*10**-3  # in k-ohm
print "    Zb = (1+beta)(re+RE) =  %0.2f k-ohm "%zb
print "The input impedance of the amplifier stage is"
Zi=((75*92.2*10**6)/((75*10**3)+(92.2*10**3)))*10**-3  # in k-ohm
print "    Zi = RB || Zb = %0.2f kohm"%Zi
print "The voltage gain of the amplifier is"
av=910./(3.03+910)
print "Av = RE / re+RE = %0.2f "%av
We know that IB = VCC-VBE / RB+(1+beta)*RE
Therefore,  IB = 85.67 uA
IE = (1+beta)*IB = 8.57 mA
The dynamic resistance is
re = 3.03 ohm
The input impedance of the amplifier is
Zb = (1+beta)(re+RE) =  92.22 k-ohm
The input impedance of the amplifier stage is
Zi = RB || Zb = 41.36 kohm
The voltage gain of the amplifier is
Av = RE / re+RE = 1.00

## Page No. 240 Example 9.11.¶

In [10]:
VCC=10.
RB=470*10**3
RE=3.3*10**3
beta=100.
RS=1*10**3
RL=50.
re=22.4
VBE=0.7
IB = (VCC-VBE) / (RB + ((1+beta)*RE))
x1=IB*10**6
print "From fig.9.55, IB = (VCC-VBE) / (RB + (1+beta)*RE) = %0.2f uA"%x1
IE=(1+beta)*IB
x2=IE*10**3
print "  IE = (1+beta)*IB = %0.2f mA"%x2
rL=(RE*RL)/(RE+RL)
print "The load resistance of the emitter follower is rL = RE || RL = %0.2f ohm "%rL                            # answer in textbook is wrong
x=(1+beta)*(re+rL)
Zi=(RB*x)/(RB+x)
x3=Zi*10**-3
print "  Zi = RB || (1+beta)(re+rL) = %0.2f kohm"%x3
y=(50/(22.4+50))*((7.13*10**3)/((1*10**3)+(7.3*10**3)))  # answer in textbook is wrong
print "  VL / VS = (rL/re+rL)(Zi/Rs+Zi) = %0.2f "%y
From fig.9.55, IB = (VCC-VBE) / (RB + (1+beta)*RE) = 11.58 uA
IE = (1+beta)*IB = 1.17 mA
The load resistance of the emitter follower is rL = RE || RL = 49.25 ohm
Zi = RB || (1+beta)(re+rL) = 7.13 kohm
VL / VS = (rL/re+rL)(Zi/Rs+Zi) = 0.59

## Page No. 241 Example 9.12.¶

In [11]:
RS=50.
RE=2*10**3
Ro=1*10**3
RL=4*10**3
VEE=6.
VBE=0.7
RC=1000.
VS=10*10**-3
IE=(VEE-VBE)/RE
x1=IE*10**3
print "We know that,  IE = VEE-VBE / RE"
print "Therefore,  IE = %0.2f mA"%x1
re=0.026/IE
print "      Zb = re(ohm) = %0.2f ohm"%re
Zi=(re*RE)/(re+RE)
print "      Zi(ohm) = re || RE = %0.2f ohm"%Zi
Av=RC/re
print "      Av = RC / re = %0.2f "%Av
x=Av*(re/(re+RS))*(RL/(RL+RC))
print "      VL / VS = Av*(re/re+RS)*(RL/RL+RS) = %0.2f"%x
VL=x*VS
x2=VL*10**3
print "      VL(in mV (rms)) = Av*VS = %0.2f "%x2
iL=VL/RL
x3=iL*10**6
print "      iL( in uA (rms)) = VL / RL = %0.2f "%x3
alpha=1.
y=alpha*(RS/(RS+re))*(RC/(RC+RL))
print "      iL / iS = alpha*(RS/RS+re)*(RC/RC+RL) = %0.2f "%y
We know that,  IE = VEE-VBE / RE
Therefore,  IE = 2.65 mA
Zb = re(ohm) = 9.81 ohm
Zi(ohm) = re || RE = 9.76 ohm
Av = RC / re = 101.92
VL / VS = Av*(re/re+RS)*(RL/RL+RS) = 13.38
VL(in mV (rms)) = Av*VS = 133.75
iL( in uA (rms)) = VL / RL = 33.44
iL / iS = alpha*(RS/RS+re)*(RC/RC+RL) = 0.17

## Page No. 243 Example 9.13.¶

In [12]:
from __future__ import division
RC=12*10**3
RL=15*10**3
RS=10.
RE=22*10**3
VEE=24.
VBE=0.3
print "The emitter current of the common base amplifier is"
IE=(VEE-VBE)/RE
print "      IE = VEE-VBE / RE = %0.2f A"%IE
re=0.026/IE
print "      re = 0.026 / IE = %0.2f ohm"%re
Av=RC/re
print "      Av = RC /re = %0.2f "%Av
x=497*(24.14/(24.14+10))*((15*10**3)/((12*10**3)+(15*10**3)))
print "      VL/VS = Av*(re/re+RS)*(RL/RL+RC) = %0.2f "%x
Ai=3.413
y=Ai*(RS/(RS+re))*(RC/(RC+RL))
print "      iL/iS = Ai*(RS/RS+re)*(RC/RC+RL) = %0.2f"%y
The emitter current of the common base amplifier is
IE = VEE-VBE / RE = 0.00 A
re = 0.026 / IE = 24.14 ohm
Av = RC /re = 497.20
VL/VS = Av*(re/re+RS)*(RL/RL+RC) = 195.23
iL/iS = Ai*(RS/RS+re)*(RC/RC+RL) = 0.44

## Page No. 244 Example 9.14.¶

In [1]:
rc=1.5*10**6
RE=4.7*10**3
Ro=2.2*10**3
RS=20
RL=10*10**3
VS=20*10**-3
VEE=9
VBE=0.7
IE=(VEE-VBE)/RE
x1=IE*10**3
print "We know that,  IE(mA) = VEE-VBE / RE = %0.2f mA"%x1
re=0.026/IE
print "      re = 0.026 / IE = %0.2f ohm"%re
Zi=(RE*re)/(RE+re)
print "      Zi = RE || re = %0.2f ohm"%Zi
Zo=(Ro*rc)/(Ro+rc)
x2=Zo*10**-3
print "      Zo = RC || re = %0.2f kohm"%x2
Av=Zo/Zi
print "      Av = Zo/Zi = RC||rc/RE||re = %0.2f "%Av
x=Av*(Zi/(RS+Zi))*(RL/(RL+Zo))
print "      VL/VS = Av*(Zi/RS+Zi)*(RL/RL+Zo) = %0.2f "%x
y=x*VS
print "      VL = Av*VS = %0.2f rms"%Av
We know that,  IE(mA) = VEE-VBE / RE = 1.77 mA
re = 0.026 / IE = 14.72 ohm
Zi = RE || re = 14.68 ohm
Zo = RC || re = 2.20 kohm
Av = Zo/Zi = RC||rc/RE||re = 149.68
VL/VS = Av*(Zi/RS+Zi)*(RL/RL+Zo) = 51.94
VL = Av*VS = 149.68 rms

## Page No. 245 Example 9.15.¶

In [2]:
beta=100.
VCC=10.
R2=4.7*10**3
R1=27*10**3
RE=680.
RC=3.3*10**3
RS=600.
RL=15*10**3
VB=(10*4.7*10**3)/((27*10**3)+(4.7*10**3))
print "      VB = (R2 / R1+R2)*VCC = %0.2f V"%VB
# answer in textbook is wrong
VE=1.39-0.7
print "      VE = 1.39 - 0.7 = %0.2f V"%VE
IE=VE/RE
x1=IE*10**3
print "      IE(mA) = VE / RE = %0.2f mA"%x1
re=0.026/IE
print "      re = 0.026/IE = %0.2f ohm"%re
x=beta*(re+RE)
Zi=(R1*R2*x)/((R2*x)+(R1*x)+(R1+R2))  # answer in textbook is wrong
x2=Zi*10**-3
print "      Zi = R1 || R2 || beta*(re+RE) = %0.2f kohm"%x2
y=(-RC/(RE+re))*(Zi/(RS+Zi))*(RL/(RC+RL))
print "The overall voltage gain is VL/VS = (-RC/RE+re)*(Zi/RS+Zi)*(RL/RC+RL) = %0.2f "%y
u=beta*re
Zi=(R1*R2*u)/((R2*u)+(R1*u)+(R1*R2))
x3=Zi*10**-3
print "      Zi = R1 || R2 || betare = %0.2f kohm"%x3
z=(-RC/re)*(Zi/(RS+Zi))*(RL/(RC+RL))  # answer in textbook is wrong
print "      VL/VS = (-RC/re)*(Zi/RS+Zi)*(RL/RC+RL) = %0.2f"%z
VB = (R2 / R1+R2)*VCC = 1.48 V
VE = 1.39 - 0.7 = 0.69 V
IE(mA) = VE / RE = 1.01 mA
re = 0.026/IE = 25.62 ohm
Zi = R1 || R2 || beta*(re+RE) = 4.00 kohm
The overall voltage gain is VL/VS = (-RC/RE+re)*(Zi/RS+Zi)*(RL/RC+RL) = -3.33
Zi = R1 || R2 || betare = 1.56 kohm
VL/VS = (-RC/re)*(Zi/RS+Zi)*(RL/RC+RL) = -76.27

## Page No. 246 Example 9.16.¶

In [3]:
RB1=7.5*10**3
RB2=6.8*10**3
RB3=3.3*10**3
RE=1.3*10**3
RC=2.2*10**3
beta1=120.
beta2=120.
VCC=18.
VBE1=0.7
VB1=(RB3*VCC)/(RB3+RB2+RB1)
print "      VB1 = (RB3*VCC)/(RB3+RB2+RB1) = %0.2f V"%VB1
IE1=(VB1-VBE1)/RE
x1=IE1*10**3
print "      IE1 = VE1/RE = (VB1-VBE1)/RE = %0.2f mA"%x1
re1=(26*10**-3)/IE1
print "      re1 = 26mV/IE1 = %0.2f ohm"%re1
re2=re1
print "      re2 = %0.2f ohm                (since IE2 = IE1)"%re2
print "Voltage gain of the second stage,"
Av2=RC/re2
print "      Av2 = RC / re2 = %0.2f"%Av2
print "Overall voltage gain,"
Av1=-1
Av=Av1*Av2
print "      Av = Av1*Av2 = %0.2f"%Av
VB1 = (RB3*VCC)/(RB3+RB2+RB1) = 3.38 V
IE1 = VE1/RE = (VB1-VBE1)/RE = 2.06 mA
re1 = 26mV/IE1 = 12.64 ohm
re2 = 12.64 ohm                (since IE2 = IE1)
Voltage gain of the second stage,
Av2 = RC / re2 = 174.11
Overall voltage gain,
Av = Av1*Av2 = -174.11

## Page No. 248 Example 9.17.¶

In [4]:
RD=5*10**3
RG=10*10**6
u=50.
rd=35*10**3
print "The voltage gain,"
Av=(-u*RD)/(RD+rd)
print "      Av = Vo/Vi = -u*RD / RD+rd = %0.2f"%Av
print "The minus sign indicates a 180 degree phase shift between Vi and Vo"
Zi=RG*10**-6
print "Input impedance  Zi(M-ohm) = RG = %0.2f "%Zi
Zo=RD*10**-3
print "Output impedance  Zo(k-ohm) = RD = %0.2f "%Zo
The voltage gain,
Av = Vo/Vi = -u*RD / RD+rd = -6.25
The minus sign indicates a 180 degree phase shift between Vi and Vo
Input impedance  Zi(M-ohm) = RG = 10.00
Output impedance  Zo(k-ohm) = RD = 5.00

## Page No. 252 Example 9.18.¶

In [5]:
RS=4*10**3
RG=10*10**6
u=50.
rd=35*10**3
print "The voltage gain,"
Av=(u*RS)/(((1+u)*RS)+rd)
print "      Av = Vo/Vi = u*RS / (u+1)*RS+rd = %0.2f "%Av
x=rd/u
Zo=(x*RS)/(RS+x)
print "Output impedance,  Zo(ohm) = 1/gm || RS = (rd/u) || RS = %0.2f ohm"%Zo
The voltage gain,
Av = Vo/Vi = u*RS / (u+1)*RS+rd = 0.84
Output impedance,  Zo(ohm) = 1/gm || RS = (rd/u) || RS = 595.74 ohm

## Page No. 254 Example 9.19.¶

In [6]:
RD=2*10**3
RS=1*10**3
gm=1.43*10**-3
rd=35*10**3
print "The voltage gain,"
Av=(((gm*rd)+1)*RD)/(RD+rd)
print "   Av = Vo/Vi = (gm*rd + 1)*RD / (RD+rd) = %0.2f"%Av
x=1./gm
Zi=(RS*x)/(RS+x)
x1=Zi*10**-3
print "Input impedance,  Zi(k-ohm) = RS || 1/gm = %0.2f k0hm"%x1
print "Output impedance,  Zo ~ RD = 2 k-ohm"
The voltage gain,
Av = Vo/Vi = (gm*rd + 1)*RD / (RD+rd) = 2.76
Input impedance,  Zi(k-ohm) = RS || 1/gm = 0.41 k0hm
Output impedance,  Zo ~ RD = 2 k-ohm

## Page No. 256 Example 9.20.¶

In [7]:
print "  In the first set,"
Vid=100-(-100) #in uV
print "    Vid = Vd(uV) = V1 = V2 = %0.2f uV"%Vid
Vc=(1/2)*(100+(-100)) # in uV
print "      Vc(uV) = 1/2(V1+V2) = %0.2f"%Vc
print "  In the second set,"
Vd=1100-900 # in uV
print "    Vd = V1 = V2 = %0.2f uV"%Vd
Vc=(1./2)*(1100+900)
print "      Vc = 1/2(V1+V2) = %0.2f uV"%Vc
In the first set,
Vid = Vd(uV) = V1 = V2 = 200.00 uV
Vc(uV) = 1/2(V1+V2) = 0.00
In the second set,
Vd = V1 = V2 = 200.00 uV
Vc = 1/2(V1+V2) = 1000.00 uV

## Page No. 258 Example 9.21.¶

In [8]:
VEE=15.
VBE=0.7
REE=65*10**3
IE = (VEE - VBE)/(2*REE)
IE1=IE*10**6
print "     IE = (VEE - VBE)/2*REE = %0.2f uA"%IE1
alphaF=100./101.
IC=(alphaF*IE)
IC1=IC*10**6
print "    IC = alpha_F*IE = %0.2f uA"%IC1
betaF=100.
IB=IC/betaF
IB1=IB*10**6
print "    IB = IC / beta_F = %0.2f uA"%IB1
VCC=VEE
RC=REE
VC=VCC-(IC*RC)
print "    VC = VCC - IC*RC = %0.2f V"%VC
VE=-0.7
VCE=VC - VE
print "    VCE = VC - VE = %0.2f V"%VCE
IE=(VEE/(2*REE))*10**6
print "    IE = VEE / 2*REE = %0.2f uA"%IE
IE = (VEE - VBE)/2*REE = 110.00 uA
IC = alpha_F*IE = 108.91 uA
IB = IC / beta_F = 1.09 uA
VC = VCC - IC*RC = 7.92 V
VCE = VC - VE = 8.62 V
IE = VEE / 2*REE = 115.38 uA

## Page No. 262 Example 9.22.¶

In [9]:
from math import sqrt
VDD=12.
VSS=VDD
ISS=175*10**-6
RD=65*10**3
Kn=3*10**-3
VTN=1.
IDS=ISS/2.
IDS1=IDS*10**6
print "    IDS = ISS / 2 = %0.2f uA"%IDS1
VGS=VTN+sqrt(ISS/Kn)
print "    VGS = VTH + sqrt(ISS/Kn) = %0.2f V"%VGS
VDS=VDD-(IDS*RD)+VGS
print "    VDS = VDD - (IDS*RD) + VGS = %0.2f V"%VDS
print "Checking for saturation,"
x=VGS-VTN
print "     VGS - VTN = %0.2f "%x
print "and VDS >= 0.2. Thus, both transistors in the differential amplifier are baised at Q-point of :"
print "%0.2f" %IDS1
print "%0.2f"%(VDS)
VIC = VDD - IDS*RD + VTN
print "    VIC= %0.2f V"%VIC
IDS = ISS / 2 = 87.50 uA
VGS = VTH + sqrt(ISS/Kn) = 1.24 V
VDS = VDD - (IDS*RD) + VGS = 7.55 V
Checking for saturation,
VGS - VTN = 0.24
and VDS >= 0.2. Thus, both transistors in the differential amplifier are baised at Q-point of :
87.50
7.55
VIC= 7.31 V

## Page No. 263 Example 9.23.¶

In [10]:
from math import log10
VS1=60*10**-3
VS2=40*10**-3
hie=3.2*10**3
hfe=100.
VEE=12.
VCC=VEE
VBE=0.7
beta=hfe
RE=5.6*10**3
RS=120.
RC=4.5*10**3
Rc=4.5*10**-5
IE=(VEE-VBE)/((2*RE)+(RS/beta))
IE1=IE*10**3
print "beta = hfe = 100"
print "    IE = (VEE-VBE) / ((2*RE)+(RS/beta)) = %0.2f mA"%IE1
IC=IE
print "IC ~ IE = 1.009 mA"
print "    Therefore       ICQ = %0.2f mA"%IE1
VCE=VCC+VBE-(IC*Rc)
print "    VCE = VCC + VBE - IC*RC = %0.2f V"%VCE
# answer in textbook is wrong
print "and      VCEQ = %0.2f V"%VCE  # answer in textbook is wrong
print "The differential gain is : "
print "Common mode gain is : "
AC=(hfe*RC)/(((2*RE)*(1+hfe))+RS+hie)
print "    AC = (hfe*Re) / (((2*RE)*(1+hfe)) + RS + hie) = %0.2f "%AC
print "CMRR = Ad / AC = %0.2f "%CMRR
CMRR1=20*log10(135.54/0.3966)
print "CMRR = 20log|Ad/AC| = %0.2f dB"%CMRR1
print "The output voltage is Vo = Ad*Vd + AC*VC. Here,"
Vd=VS1-VS2
Vd1=Vd*10**3
print "     Ad [mV(peak-peak)] = VS1 - VS2 = %0.2f "%Vd1
VC=(VS1+VS2)/2
VC1=VC*10**3
print "Then,      VC [mV(peak-peak)]= (VS1+VS2) / 2 = %0.2f "%VC1
print "Therefore,      Vo [V(peak-peak)] = %0.2f "%Vo
beta = hfe = 100
IE = (VEE-VBE) / ((2*RE)+(RS/beta)) = 1.01 mA
IC ~ IE = 1.009 mA
Therefore       ICQ = 1.01 mA
VCE = VCC + VBE - IC*RC = 12.70 V
and      VCEQ = 12.70 V
The differential gain is :
Ad = hfe*RC / RS+hie = 135.54
Common mode gain is :
AC = (hfe*Re) / (((2*RE)*(1+hfe)) + RS + hie) = 0.40
CMRR = Ad / AC = 341.72
CMRR = 20log|Ad/AC| = 50.67 dB
The output voltage is Vo = Ad*Vd + AC*VC. Here,
Ad [mV(peak-peak)] = VS1 - VS2 = 20.00
Then,      VC [mV(peak-peak)]= (VS1+VS2) / 2 = 50.00
Therefore,      Vo [V(peak-peak)] = 2.73

## Page No. 264 Example 9.24.¶

In [11]:
hie=400.
hre=2.1*10**-4
hfe=40.
hoe=25*10**-6
RL=5*10**3
RC=3*10**3
print "From the circuit 9.90(a),"
Rth=(RL*RC)/(RL+RC)
RLd=hoe*(Rth)
print "  RL = hoe*(RL || RC) = %0.2f "%RLd
print "For equivalent circuit refer fig.9.90(b)."
Ri=(hie*100*10**3)/(hie+(100*10**3))
print "  Input resistance,    Ri = hie || 100k = %0.2f "%Ri
R1=50.0*10**3
Ro=(R1*RC*RL)/((RC*RL)+(R1*RL)+(R1*RC))
print "  Output resistance,    Ro = 50k || 3k || 5k = %0.2f "%Ro
x=(-hfe*Ro)/hie
print "Therefore,    Vo/Vi = -hfe*Ro / hie = %0.2f "%x
RS=1*10**3
y=Ri/(Ri+RS)
print "    Vi/VS = Ri/(Ri+RS) = %0.2f "%y
Avs=abs(x*y)
print "Hence,    Avs = Vo/VS = (Vo/Vi)*(Vi/VS) = %0.2f "%Avs
From the circuit 9.90(a),
RL = hoe*(RL || RC) = 0.05
For equivalent circuit refer fig.9.90(b).
Input resistance,    Ri = hie || 100k = 398.41
Output resistance,    Ro = 50k || 3k || 5k = 1807.23
Therefore,    Vo/Vi = -hfe*Ro / hie = -180.72
Vi/VS = Ri/(Ri+RS) = 0.28
Hence,    Avs = Vo/VS = (Vo/Vi)*(Vi/VS) = 51.49
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