## Calculus (3rd Edition)

$4 \lt x \lt 5$
a. $|x - 3| \lt 2$ $-2 \lt x-3 \lt 2$ $1 \lt x \lt 5$ b. $|x-5| \lt 1$ $-1 \lt x-5 \lt 1$ $4 \lt x \lt 6$ By finding the overlap of both equations, $4 \lt x \lt 5$
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