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Formula
Solve the system of equations
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$x + 2 y = - 3$
$3 x + 6 y = - 9$
$x$Intercept
$\left ( - 3 , 0 \right )$
$y$Intercept
$\left ( 0 , - \dfrac { 3 } { 2 } \right )$
$x$Intercept
$\left ( - 3 , 0 \right )$
$y$Intercept
$\left ( 0 , - \dfrac { 3 } { 2 } \right )$
$\begin{cases} x+2y = -3 \\3x+6y = -9 \end{cases}$
 There are countless solutions 
Solve quadratic equations using the square root
$\begin{cases} x + 2 y = - 3 \\ 3 x + 6 y = - 9 \end{cases}$
 Solve a solution to $x$
$\begin{cases} \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \\ 3 x + 6 y = - 9 \end{cases}$
$\begin{cases} \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \\ \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 6 } \color{#FF6800}{ y } = \color{#FF6800}{ - } \color{#FF6800}{ 9 } \end{cases}$
 Substitute the given $x$ value into the equation $3 x + 6 y = - 9$
$\color{#FF6800}{ 3 } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right ) \color{#FF6800}{ + } \color{#FF6800}{ 6 } \color{#FF6800}{ y } = \color{#FF6800}{ - } \color{#FF6800}{ 9 }$
$\color{#FF6800}{ 3 } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right ) \color{#FF6800}{ + } \color{#FF6800}{ 6 } \color{#FF6800}{ y } = \color{#FF6800}{ - } \color{#FF6800}{ 9 }$
 Solve the equation 
 There are countless solutions 
$\begin{cases} \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \color{#FF6800}{ y } = \color{#FF6800}{ - } \color{#FF6800}{ 3 } \\ \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 6 } \color{#FF6800}{ y } = \color{#FF6800}{ - } \color{#FF6800}{ 9 } \end{cases}$
 Since it is satisfied with all the variables, there are a myriad of solutions to this system of equations 
 There are countless solutions 
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