## A rigid metal tank containing a sample of argon kept at 4.5atm is moved from room temperature (298K) to an oven that raises its temperature

Question

A rigid metal tank containing a sample of argon kept at 4.5atm is moved from room temperature (298K) to an oven that raises its temperature to 377K.

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3 years 2021-08-11T04:42:57+00:00 1 Answers 10 views 0

## Answers ( )

5.7 atm

Explanation:

The question is missing, but I think it must be about the new pressure of the argon gas.

Step 1: Given data

• Initial pressure (P₁): 4.5 atm
• Initial temperature (T₁): 298 K
• Final pressure (P₂): ?
• Final temperature (T₂): 377 K

Step 2: Calculate the final pressure of the argon gas

There is a direct relationship between pressure and temperature. Assuming ideal behavior and constant volume (rigid tank), we can calculate the final pressure of the gas using Gay-Lussac’s law.

P₁/T₁ = P₂/T₂

P₂ = P₁ × T₂/T₁

P₂ = 4.5 atm × 377 K/298 K = 5.7 atm
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