• Nov 22nd 2009, 11:15 PM
m0nkeysensei
Quote:

A rectangle has a length 2 meters less than twice its width. When 5 meters is added to the width, the result is a square with an area of 144 square meters. Find the dimensions of the original rectangle.

(w+5)*(2w-2)=144?
• Nov 22nd 2009, 11:27 PM
acc100jt
original width : $w$
original length : $2w-2$
New width: $w+5$
New area = 144

So $(w+5)(2w-2)=144$
• Nov 22nd 2009, 11:32 PM
m0nkeysensei
Quote:

Originally Posted by acc100jt
original width : $w$
original length : $w-2$
New width: $w+5$
New area = 144

[Note that the length is not changed]

So $(w+5)(w-2)=144$

Wouldnt it be (w+5)(2w-2)=144?
• Nov 23rd 2009, 12:16 AM
acc100jt
LOL, my bad, i didn't see the "twice"

(w+5)(2w-2)=144 is correct :)
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