How do you find the derivative of 1/(x^3-x^2)?

Jan 29, 2017

$\frac{2 - 3 x}{{x}^{3} {\left(x - 1\right)}^{2}}$

Explanation:

$f ' \left(x\right) = - \frac{3 {x}^{2} - 2 x}{{x}^{3} - {x}^{2}} ^ 2$

$= - \frac{\cancel{x} \left(3 x - 2\right)}{{x}^{{\cancel{4}}^{3}} {\left(x - 1\right)}^{2}}$

$= \frac{2 - 3 x}{{x}^{3} {\left(x - 1\right)}^{2}}$
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