# What is the trigonometric form of  e^( ( 5 pi)/12 i ) ?

Mar 23, 2016

${e}^{\frac{5 \pi}{12} i} = \cos \left(\frac{5 \pi}{12}\right) + i \sin \left(\frac{5 \pi}{12}\right)$

#### Explanation:

${e}^{i \theta} = \cos \theta + i \sin \theta$
$\theta = \frac{5 \pi}{12}$
${e}^{\frac{5 \pi}{12} i} = \cos \left(\frac{5 \pi}{12}\right) + i \sin \left(\frac{5 \pi}{12}\right)$
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