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 Chemistry Tutor: None Selected Time limit: 1 Day

what is the mass of 202.6 ml sample of hydrogen chloride gas at -12.4 c and 184 kpa

Apr 5th, 2015

Ok, so we have to convert ml to L

202.6 ml = 0.2026 L

and convert celsius to kelvin

-12.4C = 260.75 K

Then we use PV = nRT to find out how many moles there will be

n = PV / RT

= (184)(0.2026) / (8.314)(260.75)

= 0.01725 moles

One mole of HCL = 36.4609 grams

So,

(0.01725)(36.4609) = 0.6288 grams

Apr 5th, 2015

Oh, one other thing I forgot. We have to convert kPa to atm

1 atm = 101.3 kPa

So, 184 kPa = 1.8164 atm

So, we have to divide the previous answer by 101.3 to get

.06288 / 101.3 = 6.2 x 10^-4 grams.

Apr 5th, 2015

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Apr 5th, 2015
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Apr 5th, 2015
Dec 10th, 2016
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