posted by on .

State the period and phase shift of the function y=-4tan(1/2x + 3pi/8)

a) 2pi, -3pi/4
b) pi, 3pi/8
c) 2pi, 3pi/8
d) pi, -3pi/8

2) What is the equation for the inverse of y=cos x+3:
a) y=Arccos(x+3)
b) y=Arccos x-3
c) y=Arccos x+3
d) y=Arccos(x-3)

in y=-4tan(1/2x + 3pi/8)
y = -4 tan (1/2)[x + 3pi/4]

so the period is 2pi/(1/2) = 4pi which is none of your choices.

the phase shift would be 3pi/4 radians to the left.

2)
the inverse of y = cos x+3 is x = cos y+3

then cos y = x-3
and y = arccos(x-3)

I double checked my typing on the first problem and everything was entered correctly.

then the book is wrong

I am not surprised as I have found many errors thus far.

Thanks for helping
{"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}