# How do you graph the point P(-0.5, -(11pi)/6)?

Plot point $\left(- \setminus \frac{\sqrt{3}}{4} , \frac{1}{4}\right)$

#### Explanation:

The Cartesian coordinates $\left(x , y\right)$ of the point $\left(r , \setminus \theta\right) \setminus \equiv \left(- 0.5 , - \frac{11 \setminus \pi}{6}\right)$ are given as follows

$x = r \setminus \cos \setminus \theta = \left(- 0.5\right) \setminus \cos \left(- \frac{11 \setminus \pi}{6}\right) = - \setminus \frac{\sqrt{3}}{4}$

$y = r \setminus \cos \setminus \theta = \left(- 0.5\right) \setminus \sin \left(- \frac{11 \setminus \pi}{6}\right) = \frac{1}{4}$

Now, plot the point $\left(- \setminus \frac{\sqrt{3}}{4} , \frac{1}{4}\right)$ on XY plane
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