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5^m×5^-2=5^3. Find the value of "m"

Posted by: Navjot s. on 06.02.2020

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Answer:

We hve to use law of exponents which states that a^m* a^n=a^(m+n)

So if we use this law then a=5 and n=-2 as bases are same so

we can write m-2=3

m=5

Answer:

Please see the attachment below

Answer:
5^m-2=5^3 m=3+2=5
Answer:

Given, 5^m x 5^-2 = 5^3

thus, 5^m x 1/5^2 = 5^3

or, 5^m = 5^3 x 5^2

or, 5^m = 5^5

thus, m = 5

Answer:
M= 5
Answer:
From the law of exponents as the base is same powers are also same Ans. is 5
Answer:

Ans. m = 5

Solution: 5^m*5^(-2) = 5^3

So, 5^m = 5^(3+2)

=> 5^m = 5^5 .

=> m = 5

Answer:

5^m*5^-2=5^3

asthe base is same ie 5 on LHS powers will get added

so we get

5^(m-2)=5^3

as base is common on LHS and RHS we can remove the base and equate the powers so we get

m-2=3

m=3+2

m=5

Answer:

Ans:  LHS=   5^m* 5^(-)2=  5^(m-2) (as per laws of indices)

RHS = 5^3

Therfore  5^(m-2)=  5^3

The two expressions are equal and their bases are also equal.Hence the indices must also be equal.

Hence  m-2= 3 or m=5

Answer is m=5

Answer:
5
Answer:

question 5^m*5^-2=5^3 find value of m?

answer:

as we know that m^a*m^b=m^(a+b) formula

similerly 5^m*5^-2=5^(m-2)

so 5^(m-2)=5^3

from herer m-2=3

so m=3+2;

answer m=5

Answer:
5^mÃ—5^-2=5^3where m value is 5
Answer:
5^m*5^-2=5^3 5^m=5^3/5^-2 5^m=5^(3-(-2)) 5^m=5^5 m=5
Answer:
According to exponential law of powers and indices, when base is the same and in multiplication, powers will be added. So, 5^m+(-2)=5^3 when base is the same powers can b compared. So, m+(-2)=3 m-2=3 m=3+2 m=5
Answer:
We know that a^m X a^n = a^m+n Here a= 5, n= -2 There fore m should be 5 to get 5^3 So the value of m is 5

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