## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$y=1$
The solution to the given expression, $8(5-y)=32$, is \begin{array}{l}\require{cancel} 8(5)+8(-y)=32 \\\\ 40-8y=32 \\\\ -8y=32-40 \\\\ -8y=-8 \\\\ y=\dfrac{-8}{-8} \\\\ y=1 .\end{array}
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