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# In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then AB =

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Joined: 02 Sep 2009
Posts: 53066
In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then AB =  [#permalink]

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09 Oct 2018, 22:45
00:00

Difficulty:

15% (low)

Question Stats:

100% (00:47) correct 0% (00:00) wrong based on 18 sessions

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In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then AB =

(A) $$20$$

(B) $$10 \sqrt{2}$$

(C) $$10 \sqrt{3}$$

(D) $$20 \sqrt{2}$$

(E) $$20 \sqrt{3}$$

Attachment:

triangle.jpg [ 12.53 KiB | Viewed 261 times ]

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Concentration: General Management, Operations
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Re: In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then AB =  [#permalink]

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09 Oct 2018, 23:01
Since A =60 degree
And B = C
i.e. it's an equilateral triangle
Means all sides are equal of ∆ABC

Hence AB =BC=20
OPTION:A

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Director
Joined: 19 Oct 2013
Posts: 508
Location: Kuwait
GPA: 3.2
WE: Engineering (Real Estate)
Re: In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then AB =  [#permalink]

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09 Oct 2018, 23:03
Bunuel wrote:

In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then AB =

(A) $$20$$

(B) $$10 \sqrt{2}$$

(C) $$10 \sqrt{3}$$

(D) $$20 \sqrt{2}$$

(E) $$20 \sqrt{3}$$

Attachment:
triangle.jpg

Angle B = Angle C = x

60 + 2x = 180
2x = 120
x = 60

Equal angles correspond to equal lengths.

Since BC = 20 and angle A = 60

Then AB = 20

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Joined: 31 Oct 2013
Posts: 1162
Concentration: Accounting, Finance
GPA: 3.68
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Re: In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then AB =  [#permalink]

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10 Oct 2018, 00:44
Bunuel wrote:

In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then AB =

(A) $$20$$

(B) $$10 \sqrt{2}$$

(C) $$10 \sqrt{3}$$

(D) $$20 \sqrt{2}$$

(E) $$20 \sqrt{3}$$

Attachment:
triangle.jpg

A = 60

B = C.

A + B + C = 180

60 + B + B = 180

B = 60

60-60-60 Triangle.

It means all the legs of the triangle must be equal.

BC = 20

AB = 20.

Re: In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then AB =   [#permalink] 10 Oct 2018, 00:44
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# In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then AB =

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