## Intermediate Algebra (6th Edition)

$11x+y=-52$
Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the Two-Point Form, the equation of the line passing through $( -5,3 )$ and $( -4,-8 )$ is \begin{array}{l} y-3=\dfrac{3-(-8)}{-5-(-4)}(x-(-5)) \\\\ y-3=\dfrac{3+8}{-5+4}(x+5) \\\\ y-3=\dfrac{11}{-1}(x+5) \\\\ y-3=-11(x+5) \\\\ y-3=-11x-55 \\\\ 11x+y=-55+3 \\\\ 11x+y=-52 .\end{array}
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0}