## University Calculus: Early Transcendentals (3rd Edition)

$$\pi$$
We need to integrate the integral to compute the volume. $$Volume=\int_{0}^{\pi/2} \pi \cos (x) \\=(\pi) [(\sin (x)]_0^{\pi/2} \\=(\pi) [\sin (\dfrac{\pi}{2})-\sin (0)] \\= \pi(1-0) \\=\pi$$
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