# SOLUTION: My question is...solve for x, y, z. 2x+5y+z=22 3x-3y-z=-22 5x+y+2z=-3 I have... 2x+5y+z=22 -4x-10y-2z=44 45x+18y=0 3x-3y-z=-22 5x+ y+ 2z=-3 10x-18y=-4

Algebra ->  Algebra  -> Systems-of-equations -> SOLUTION: My question is...solve for x, y, z. 2x+5y+z=22 3x-3y-z=-22 5x+y+2z=-3 I have... 2x+5y+z=22 -4x-10y-2z=44 45x+18y=0 3x-3y-z=-22 5x+ y+ 2z=-3 10x-18y=-4      Log On

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 Algebra: Systems of equations that are not linear Solvers Lessons Answers archive Quiz In Depth

 Question 406673: My question is...solve for x, y, z. 2x+5y+z=22 3x-3y-z=-22 5x+y+2z=-3 I have... 2x+5y+z=22 -4x-10y-2z=44 45x+18y=0 3x-3y-z=-22 5x+ y+ 2z=-3 10x-18y=-41 ___________ ____________ __________ 5x+2y =0 5x-9y =41 I keep coming up with a fractionfor the last step.Found 3 solutions by Alan3354, MathLover1, ewatrrr:Answer by Alan3354(30959)   (Show Source): You can put this solution on YOUR website!2x+5y+z=22 3x-3y-z=-22 5x+y+2z=-3 --------------- x = -2 y = 5 z = 1 Sometimes the answers are fractions. Not this time, tho. ================ I have... -4x-10y-2z=44 45x+18y=0 5x+ y+ 2z=-3 10x-18y=-41 --------------- 1x -9y = 41 ******************* Answer by MathLover1(6614)   (Show Source): You can put this solution on YOUR website!.................1.........solve for and substitute in 2 ..................2 ..................3 .................1 ..................2 ................solve for and substitute in 3 substitute in ..................3 ..substitute and ..................3...calculate now find and so, your answer is: check: .................1. Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi 2x+5y+z=22 3x-3y-z=-22 5x+y+2z=-3 Solving by elimination 2x+5y+z=22 3x-3y-z=-22 5x + 2y = 0 6x-6y+2z=-44 5x+y+2z=-3 11x - 5y = -47 5x + 2y = 0 11x - 5y = -47 25x + 10y = 0 22x - 10y = -94 47x = -94 x = -2 and y = 5 ( 5x + 2y = 0, y = -5x/2= 10/2) AND z = 22-2x-5y = 1 ```
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