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$\left[\begin{array}{cc} 1 & \frac{-1}{5} \\ 0 & 0 \end{array}\right]=\left[\begin{array}{cc} \frac{1}{10} & 0 \\ \frac{1}{2} & 1 \end{array}\right] \mathrm{P} \text { (applying } \mathrm{R}_{2} \rightarrow \mathrm{R}_{2}+5 \mathrm{R}_{1} \text { ) }$ We have all zeros in the second row of the left hand side matrix of the above equation. Therefore, P-1 does not exist EXERCISE 3.4 Using elementary transformations, find the inverse of each of the matrices, if it exists in Exencises 1 to 17. 1. 2. 3. 4. 5. 6. 7. 8. 11. 9. 10. 12. 13. 14. . 15. 16. 17. 18. Matrices and will be inverse of each other only if

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 Question Text $\left[\begin{array}{cc} 1 & \frac{-1}{5} \\ 0 & 0 \end{array}\right]=\left[\begin{array}{cc} \frac{1}{10} & 0 \\ \frac{1}{2} & 1 \end{array}\right] \mathrm{P} \text { (applying } \mathrm{R}_{2} \rightarrow \mathrm{R}_{2}+5 \mathrm{R}_{1} \text { ) }$ We have all zeros in the second row of the left hand side matrix of the above equation. Therefore, P-1 does not exist EXERCISE 3.4 Using elementary transformations, find the inverse of each of the matrices, if it exists in Exencises 1 to 17. 1. 2. 3. 4. 5. 6. 7. 8. 11. 9. 10. 12. 13. 14. . 15. 16. 17. 18. Matrices and will be inverse of each other only if Updated On Dec 22, 2022 Topic Calculus Subject Mathematics Class Class 12 Answer Type Video solution: 1 Upvotes 110 Avg. Video Duration 3 min
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