## Basic College Mathematics (9th Edition)

$a = 2$ ft $b = 6$ ft
1. Solve for $a$ $\frac{a}{6} = \frac{3}{9}$ $a = \frac{3 \times 6}{9}$ $a = \frac{18}{9}$ $a = 2$ ft 2. Solve for $b$ $\frac{b}{2} = \frac{9}{3}$ $b = \frac{9 \times 2}{3}$ $b = \frac{18}{3}$ $b = 6$ ft
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