# Pascals Triangle

Posted by Brian Roepke on Mon 27 January 2020 Updated on Mon 27 January 2020

One of the many beautiful things found in mathematics are Recurrence Relations, or an equation that recursively defines a sequence or multidimensional array of values, once one or more initial terms are given; each further term of the sequence or array is defined as a function of the preceding terms. My favorite one of these is Pascal's triangle.

Pascal's triangle is a triangular array of the binomial coefficients. In much of the Western world, it is named after the French mathematician Blaise Pascal,

In order to calculate this you can do it two different ways. You can sum the two numbers above or you can use Binomial Coefficients. The binomial coefficient appears as the kth entry in the nth row of Pascal's triangle (counting starts at 0).

$$\binom{n}{k}$$

Which can also be expressed as:

$$\binom{n}{k} = \frac{n!}{k! (n-k)!}$$

This code uses the method above to create the triangle by looping through each level and computing the binomial coefficient for each item based on it's row and column position.

from math import factorial

def binom(n,k):
'''calculate binomial coefficient'''

return factorial(n) / (factorial(k) * factorial(n-k))

triangle = []
n = 0 # Column Counter
row_counter = 0 # Row counter

for n in range(11):
row = []
for k in range(row_counter+1):
n_k = binom(n,k)
row.append(n_k)
triangle.append(row)
row_counter += 1

for tri in triangle:
print(tri)

# [1.0]
# [1.0, 1.0]
# [1.0, 2.0, 1.0]
# [1.0, 3.0, 3.0, 1.0]
# [1.0, 4.0, 6.0, 4.0, 1.0]
# [1.0, 5.0, 10.0, 10.0, 5.0, 1.0]
# [1.0, 6.0, 15.0, 20.0, 15.0, 6.0, 1.0]
# [1.0, 7.0, 21.0, 35.0, 35.0, 21.0, 7.0, 1.0]
# [1.0, 8.0, 28.0, 56.0, 70.0, 56.0, 28.0, 8.0, 1.0]
# [1.0, 9.0, 36.0, 84.0, 126.0, 126.0, 84.0, 36.0, 9.0, 1.0]
# [1.0, 10.0, 45.0, 120.0, 210.0, 252.0, 210.0, 120.0, 45.0, 10.0, 1.0]
# [1.0, 11.0, 55.0, 165.0, 330.0, 462.0, 462.0, 330.0, 165.0, 55.0, 11.0, 1.0]


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tags: math
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