# Graphing Linear Equations

## Graphing Linear Equations which are neither in slope-intercept form nor in point-slope form

Often equations are neither in slope-intercept form nor point-slope form. In this case, we can substitute any two different x values, and solve to find the corresponding y values.

Example

Graph 4x + 3y = 24.

Solution

Choose two x values, say x = 0 and x = 2. (We could have chosen any two different x values.) Use substitution to find the corresponding y values.

 4x + 3y = 24 4(0) + 3y = 24 Replace x with 0. 3y = 24 y = 8 Divide each side by 3.

The point at (0, 8) is on the line.

 4x + 3y = 24 4(2) + 3y = 24 Replace x with 2. 8 + 3y = 24 3y = 16 Subtract 8 from each side. y Divide each side by 3.

The point at is also on the line.

Graph the line as shown.
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