# Find the Laplace transform

#### Alexmahone

##### Active member
Find the Laplace transform of $\displaystyle f(t)=1$ if $\displaystyle 1\le t\le 4$; $\displaystyle f(t)=0$ if $\displaystyle t<1$ or if $\displaystyle t>4$.

#### CaptainBlack

##### Well-known member
Find the Laplace transform of $\displaystyle f(t)=1$ if $\displaystyle 1\le t\le 4$; $\displaystyle f(t)=0$ if $\displaystyle t<1$ or if $\displaystyle t>4$.
Straight forward application of the definition:

$F(s)=\int_0^{\infty}f(t)e^{-st}\; dt=\int_1^4e^{-st}\;dt$

CB

#### Alexmahone

##### Active member
Straight forward application of the definition:

$F(s)=\int_0^{\infty}f(t)e^{-st}\; dt=\int_1^4e^{-st}\;dt$

CB
Thanks. How would the answer differ if one of the endpoints 1 or 4 (or both) were excluded?

#### Ackbach

##### Indicium Physicus
Staff member
Thanks. How would the answer differ if one of the endpoints 1 or 4 (or both) were excluded?
Do you mean if your function were defined as, for example, $f(t)=1$ if $1<t\le 4$; $f(t)=0$ if $t\le 1$ or if $t>4$? It would make no difference. The reason is that the changing of one point in a function does not alter the integral of that function. In fact, changing the function at countably many points does not change the value of the integral.

#### Alexmahone

##### Active member
Do you mean if your function were defined as, for example, $f(t)=1$ if $1<t\le 4$; $f(t)=0$ if $t\le 1$ or if $t>4$? It would make no difference. The reason is that the changing of one point in a function does not alter the integral of that function. In fact, changing the function at countably many points does not change the value of the integral.
That's exactly what I meant. Thanks.

Staff member
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