# Thread: Determining slope and y-intercept.

1. ## Determining slope and y-intercept.

So, the equation that I'm given is this:

7y + 12x -2 = 0

and I'm told to determine the y-intercept and the slope of this line, but I'm not entirely sure how to go about doing that.

Any help would be appreciated!

2. Originally Posted by Rumor
So, the equation that I'm given is this:

7y + 12x -2 = 0

and I'm told to determine the y-intercept and the slope of this line, but I'm not entirely sure how to go about doing that.

Any help would be appreciated!
Manipulate into the form y=mx+c. m is the slope and c is the y-intercept

3. Originally Posted by Rumor
So, the equation that I'm given is this:

7y + 12x -2 = 0

and I'm told to determine the y-intercept and the slope of this line, but I'm not entirely sure how to go about doing that.

Any help would be appreciated!

If you solve the equation for y in terms of x you will get the equation in slope intercept form.

4. Originally Posted by Rumor
So, the equation that I'm given is this:

7y + 12x -2 = 0

and I'm told to determine the y-intercept and the slope of this line, but I'm not entirely sure how to go about doing that.

Any help would be appreciated!
$
7y+12x-2=0

Rearrange into y=mx+b:

7y=-12x+2

Simplify:

7y/7= 12/7x +2/7

y=12/7x + 2/7(0.28)

The slope is 12/7 and the y intercept is 0.28.$

5. $\begin{array}{rcrcrc}
7y + 12x - 2 = 0\\
7y = -12x + 2\\
y = \frac{-12x}{7} + \frac{2}{7}
\end{array}$

The gradient ( $m$) is $\frac{-12x}{7}$, and the y-intercept ( $c$) is $\frac{2}{7}$.
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