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This page contains Cheats for NHL 13 organized by sections for Xbox 360. This game has "Sports" as genre, made by Electronic Arts, released on Sep 11, 2012. If you can't find a hint or secret in our list, then please check this page periodically for the latest updates.
- Developer: Electronic Arts
- Publisher: Electronic Arts
- Genre: Sports
- Release: Sep 11, 2012
- ESRB: Everyone 10+
Complete one of the following achievements to collect their Xbox Live Gamerscore points:..From: biz333
If you know cheats, secrets, hints, glitches or other level guides for this game that can help others leveling up, then please Submit Your Cheats and share your insights and experience with other gamers.
Stuck in this game? Set a specific, clearly defined question and let other gamers answer your question or view answers to previously asked questions. If you think you are an expert then please try to help others with their questions.
When i create my guy i go to edit players but how do i change the guys name i can change his look etc but not his name...
Posted on: 10-14-2014
How do I become team captain in be a pro mode?...
Posted on: 10-11-2014
In league play can i overide game and make a trade happen even if it is not of equal value?...
Posted on: 12-13-2013
My cousin and i play nhl 13 he has boosts for his be a pro when we play ultimate team he adds these boosts to them and his players are basically unstoppable he says you can add them at the menu before...
Posted on: 08-17-2013
When playing an opponent, how do you find out their level?...
Posted on: 07-28-2013
How do you get your glove, skates, and stick green?...
Posted on: 06-26-2013
For online how do you edit your guy's attributes....
Posted on: 04-05-2013
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Video: U.K. postal strike delays mail
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Trump the barbarian
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Philadelphia police confirm a man, carrying a seven-inch butcher knife, was shot and killed following a struggle with officers.
Police say officers responded to a call of a person with a knife at about 7 a.m. Saturday at the intersection of Castor and Robbins Streets in the Oxford Circle section of the city.
According to officials, when police arrived they knocked the unidentified suspect to the ground using the push bumper of their police cruiser after seeing him standing in the middle of the street with the knife.
Investigators say the officers then exited their vehicles and used pepper spray on the 23-year-old suspect after he refused to drop the knife.
Read more: philadelphia.cbslocal.com
Exclusive: Sid Roth interviews Richard Roberts, son of famous father Oral
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The Chronicle of Higher Education had this to say about Answering Auschwitz: Primo Levi's Science and Humanism After the Fall:
One triumph of scholarship, however, is that it can ride the force of established reputation like a wave, and take us into new dimensions of a writer or subject. At first glance, Answering Auschwitz: Primo Levi's Science and Humanism After the Fall, a new collection of essays edited by Stanislao G. Pugliese (Fordham University Press, 2011), looks to be more of the same—another deserved monument to 20th-century literature's most disciplined witness to the Holocaust, that flinty, unsentimental voice like no other. But Pugliese, a professor of modern European history and Italian studies at Hofstra University, offers us a fuller portrait.
The book was published in March by Fordham University Press.
Donald Trump is really going to be the nominee. This is actually happening. - Vox - A fundamental part of the disorder that is the GOP. Republicans actually beliwev that discrimiantion against whites is a bigger problem than discriminati...
7 hours ago


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ORG XMIT: AZMS101 Los Angeles Angels' Albert Pujols signals to teammates in the dugout as he warms up before a spring training baseball game against the San Francisco Giants on Tuesday, March 27, 2012, in Scottsdale, Ariz. (AP Photo/Marcio Jose Sanchez)
NBA 13m ago
Phil Jackson sent some weird tweets while on vacation again
Phil Jackson is back on vacation! Let's see where he is this week: "Curly"moment. pic.twitter.com/xKgKl5SYt4 — (…)
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Sports world reacts to Donald Trump's 'taco bowl' tweet
Kris Humphries just laughed.
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Evans is also a member of the Seattle Sounders.


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blueberry [ˈbluːbərɪ]
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In many parts of the Spanish-speaking world, the word "arándano" may refer either to a cranberry or a blueberry.
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Everything Eclipse
Who Does the Best Bella Impression?
As every Twihard knows, the saga's heroine's got lots of bite! Fans mimic Kristen Stewart's signature lip schtick on Twitter – vote for your fave!
Updated: Wednesday Jun 09, 2010 | 03:00 PM EDT
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New answers tagged norm
Write $\|x\|_\infty = \max |x_i|$. Clearly $\|x\|_\infty \le \|x\|_p$ for any $p$. Then for $p < q$ you have $$ \|x\|_q^q = \sum_{k=1}^n |x_i|^q \le \|x\|_\infty^{q-p} \sum_{k=1}^n |x_i|^p \le \|x\|_\infty^{q-p} \|x||_p^p \le \|x\|_p^q.$$ Thus $\|x\|_q \le \|x\|_p$.
Yes, the dual-norm is that one! Furthermore, you should consider following: First: The embedding $$ H^1(\Omega)\hookrightarrow L^2(\Omega). $$ This is because $$ \| \cdot \|_{_{H^1(\Omega)}}^{^2} := \| D^1\cdot \|_{_{L^2(\Omega)}}^{^2} +\| \cdot \|_{_{L^2(\Omega)}}^{^2} $$ is a "stronger" norm than $ \|\cdot\|_{_{L²(\Omega)}}$. Second: it follows from the ...
As stated, this is false, since even $A$ itself could be singular under the given assumptions. To conclude that $A-B$ is nonsingular when $B$ is "small", one needs: $A$ to be nonsingular $\|B\| < \|A^{-1}\|^{-1}$ The reason this works is that $\|A^{-1}\|^{-1} = \min_{\|x\|=1}\|Ax\|$. Hence, assumption 2 implies $\|Bx\|<\|Ax\|$ for all $x$, making ...
The first inequality is clear by the definition of the matrix norm. The second is clear by the definition and $\frac{|ABx|}{|x|}=\frac{|ABx|}{|Bx|}\frac{|Bx|}{|x|}$.
The first inequality is immediate, since $$ \|A\| = \sup_{x \in \mathbb{R}^n \setminus \{0\}} \frac{|Ax|}{|x|}\ge \frac{|Ax|}{|x|}. $$ For the second note that for $x\ne0$ with $Bx\ne0$, we have $$ \|AB\| = \sup_{x\ne0} \frac{|ABx|}{|x|}=\sup_{Bx\ne0}\left( ...
I assume you want this $\forall K>0$, not all $t$. Since $f(t)^Tf(t)\geq0$, you can take $\beta=(\int_0^{\infty}f(t)^Tf(t)\,dt)^{1/2}.$
Just note that $\|f\|_K^2=\int_0^K f(t)^Tf(t) \, dt\leq \int_0^\infty f(t)^Tf(t) \, dt$ for all $K$, since $f(t)^Tf(t)$ is always nonnegative.
Note that $$ \left(\frac{x}{e^x}\right)'=\frac{e^x(1-x)}{e^{2x}} $$ vanishes at $x=1$ (which is a maximum of the function). Hence, $$ p(f)=\frac1e\sup_{\|v\|=1}f(v)=\frac1e\|f\|^*. $$
It is not. In general, for $a_i \in \mathbb{C}$, we have $$ |a_1+a_1+\cdots+a_n|^2\neq|a_1|^2+|a_2|^2+\cdots+|a_n|^2. $$
$A$ and $B$ are positive matrices and $\|A+B\| = \|A\|+\|B\|$, then A and B have a common eigenvector
Suppose $A$ and $B$ are positive operators on a finite-dimensional inner product space $V$ and $\|A + B\| = \|A\| + \|B\|$. Because $A$ and $B$ are positive, $A+B$ is also a positive operator. Thus there exists $x \in V$ such that$$\|x\| = 1 \quad \text{and} \quad\|A+B\| = \langle (A+B)x, x \rangle. $$ Now \begin{align*} \|A+B\| &= \langle (A+B)x, x ...
Let $v$ be an eigenvector of $A$ corresponding to the eigenvalue $\lambda$, i.e. $Av=\lambda v$. Then $(\lambda I-B)^{-1}(A-B)v=(\lambda I-B)^{-1}(\lambda I -B)v=v $. Hence by definition of the operator norm, $\left\|(\lambda I-B)^{-1}(A-B)\right\|\geq 1$. Question: Where did we use that $\lambda$ is not an eigenvalue for $B$?
If $x$ is a unit eigenvector of $A$ associated with $\lambda$, we have $$ (\lambda I-B)^{-1}(A-B)x=(\lambda I-B)^{-1}(\lambda I-B)x=x $$ and hence $$ 1=\|x\|=\|(\lambda I-B)^{-1}(A-B)x\|\leq\|(\lambda I-B)^{-1}(A-B)\|. $$
Frobenius norm of matrix $A^{T}A$ is $trace(A^{T}A)$? Where all of the values in the matrix $A$ are real
Let $A=\left( \begin{array}{cc} 2 & 0 \\ 0 & 1 \end{array} \right)$. $\left\| A^TA \right\|_F=\sqrt{trace(A^TAA^TA)}=\sqrt{17}$ However, $trace(A^TA)=5$. Hence the equality doesn't hold.
Notice that for each vector $x$, one has $$\|T^* T^2(x)\|^2 = \langle T^* T^2(x),T^* T^2(x) \rangle = \langle TT^*T^2(x), T^2(x)\rangle = \langle T^*T^3(x),T^2(x) \rangle = \langle T^3(x),T^3(x) \rangle = \|T^3(x)\|^2.$$ Thus $$\|T^3\| = \sup_{\|x\|=1} \|T^3(x)\| = \sup_{\|x\|=1}\|T^*T^2(x)\| = \|T^*T^2\|.$$
Diagonalization will help here. (When in doubt and working with normal matrices, try utilizing diagonalization!) Write $T = UDU^*$, then $T^* = UD^* U^*$, giving that $T^*T^2 = UD^*D^2U^*$. However $T^3 = UD^3 U^*$. Since unitary conjugation does not change the operator norm, this boils down to considering $D^*D^2$ and $D^3$. Here $Dg(x) = f(x)g(x)$ for ...
In the paragraph above Lemma 2.6, the authors explicitly state "[we write] $\mathcal L^\infty$ for the space of measurable bounded functions"
Theorem 2.1 in the paper A Singular Value Thresholding Algorithm for Matrix Completion
Assuming continuity and differentiability of $f$: This comes from the Mean Value Theorem: If $f$ is continuous on $[a,b] \in \mathbb{R}$: $$\exists c \in [a,b]: f'(c)=\frac{f(b)-f(a)}{b-a}$$ Now: $||f'||_{L^{\infty}}$ is the infinity norm, which is the supremum value of $|f'|$ on some interval. So, your formula is saying that the absolute value of the ...
The homogenous solutions constitute a subspace. Choose $x_p$ to be in its orthogonal complement (this is always possible). Then the cross terms on the right side of your equation vanish.
Note, that $\|\cdot\|$ is somehow the composition of the $2$-norm and the $3$-norm on $\mathbb R^2$. We have $$\|x\| = \|(\|(x_1,x_2)\|_2,x_3)\|_3$$ and with this at hand the proof is easy (but a bit ugly). We have by the triangle inequality for the $2$-norm $$a:= \|(x_1+y_1,x_2+y_2)\|_2 \leq \|(x_1,x_2)\|_2 + \|(y_1,y_2)\|_2 =:b$$ and since for all ...
Yes, the inequalities hold. Let $B$ be the closed unit ball for the norm $\|\cdot \|$. The assumptions imply that $\pm e_j$, the standard basis vectors, are in $B$. Hence, their convex hull is contained in $B$. This convex hull is the unit ball for the $\ell^1$-norm, which implies $\|\cdot \|\le \|\cdot \|_1$. Similarly, we need to prove that $B$ is ...
No. You have to look at a set of arbritray matrices in a neighbourhood of a given $P$ and show that any matrix in that set is orthogonal. You won't succeed with this, though, since that set is actually not open but compact. (It's bounded and closed as the counterimage of a point under a continuous map) (Edit: Actually it is a closed smooth submanifold of ...
Some inequalities between 1- norm, 2- norm and infinity-norm: $\|x\|_2\leq\sqrt{\|x\|_1\| x\|_\infty}\leq\frac{1+\sqrt{n}}{2}\|x\|_2$
You correctly observed that $\|x\|_2\le \sqrt{\|x\|_1\|x\|_\infty}$ is a special (easy) case of Hölder's inequality, which essentially amounts to $|x_i|^2\le \|x\|_\infty |x_i|$. To prove the second part, first use the arithmetic-geometric means inequality. After that, use Hölder's inequality again: $$\|x\|_1\le \sqrt{n}\|x\|_2$$ and observe that ...
When you say $K$ is continuous I assume it is with respect the norm on $C([0,1])$, that is, $|f\|_\infty$. The two norms are not comparable. Let $K$ be the identity. Then $$\sup_{\|f\|_\infty\leq 1} \|Kf\|_\infty=1$$ but $$\sup_{\|f\|_2\leq 1} \|Kf\|_\infty=\infty.$$ To see it consider a sequence $\{f_n\}$ of functions such that $f_n$ is supported on ...
This is the Holder inequality with $p=1$ and $q=\infty$. In addition, we can prove this inequality using the following way: $$\sum_{i=1}^n \vert x_i\vert^2=\sum_{i=1}^n \vert x_i\vert \vert x_i\vert\leq \max_{i}\vert x_i\vert\sum_{i=1}^n \vert x_i\vert=\Arrowvert x \Arrowvert_1 \Arrowvert x\Arrowvert_\infty.$$
Yes, you are right, the statement is not true. You can sketch the simple following example on $\mathbb{R}^2$. Let $x_0=(1,1)^T$ and $$A= \begin{pmatrix} 1 & 0 \\ \frac{2}{5}&\frac{1}{5} \end{pmatrix}. $$ Then it is easy to see for $p=1$, the minimum is attained at $(2,1)^T$, however for $p=2$, the minimum is attained at ...
\begin{equation} \begin{aligned} \parallel u \parallel_{*} & = \enspace \max\limits_{\parallel x \parallel \leq 1} <u, x>\\ \leq & \enspace \max\limits_{\parallel x \parallel \leq 1} \frac{<u, x>}{\parallel x \parallel}\\ \leq & \enspace \max\limits_{\parallel x \parallel \neq 0} \frac{<u, x>}{\parallel x \parallel}\\ = & ...
I think I found the solution. Continuing with my reasoning, applying the Cauchy formula, we have: $$1 = a_n = {1 \over 2\pi i}\oint_{|z| = 1} {P(t) \over t^{n+1}} dt$$ Therefore, we have: $$1 = |a_n| = |{1 \over 2\pi i}\oint_{|z| = 1} {P(t) \over t^{n+1}} dt| \le {1 \over 2\pi}\max_{|z| = 1}|P(z)| l(|z| = 1) = \max_{|z| = 1}|P(z)|$$ Here $l(\gamma)$ is the ...
Your method is probably having difficulty since a function like $z^n$ is in fact bounded by $1$ on the interior of the disk. Thus, choosing any "special" values on the interior - or any set of special values - cannot suffice as proof. It's perhaps possible that this exercise could be completed purely algebraically, as you are trying to do, but I wouldn't say ...
Couple of Tips: $||Ax||^2=x^T(A^TA)x$. Try to see yourself how this comes out. Now see the wiki for the derivative you are looking for. If you are not particular on the lagrangian route for this problem, be informed that $$\min_{||x||_2=1}x^TBx\,=\,\lambda_{min}(B)$$ for all symmetric matrices $B$ and $\lambda_{min}(.)$ is the least eigenvalue. This ...
Normally we talk about normal matrices in a space with inner product, and we consider the norm induced by the inner product (unless explicitly said that another norm should be considered). So I will assume we are supposed to use the norm induced by the inner product. Your proof for the case where $A$ is normal is correct. The result is not valid is $A$ is ...
You know that a norm is completely described by its unit ball. Seeing the way unit balls of $||.||_p$ converge, help to have a precise understanding of the why and how of the limit. See (classical) pictures below of the unit balls of $||.||_1, ||.||_2, ||.||_3$ and $||.||_9$ in $\mathbb{R}^2$. It is clear that these balls are getting more and more square ...
Hint: For the upper bound, observe that $$ \left(\sum_{i=1}^n |v_i|^p\right)^{1/p}\leq\left(\sum_{i=1}^n \max|v_i|^p\right)^{1/p}=n^{1/p}\max|v_i|. $$ For the lower bound, observe that $$ \left(\sum_{i=1}^n |v_i|^p\right)^{1/p}\geq\left( \max|v_i|^p\right)^{1/p}=\max|v_i|. $$ Now, take limits.
Let's define for $a\in A$ the left multiplication operator and the right multiplication operator $$ L_a : A \rightarrow A, L_a(x)=ax \quad \text{and} \quad R_a: A \rightarrow A, R_a(x)=xa.$$ As multiplication is assumed to be continuous we get that $L_a$ and $R_a$ are both continuous for all $a\in A$. Let $B=B_1(0,A)$ denote the unit ball in $A$. Then ...
$y=(1,\frac{1}{2},\frac{1}{3},\frac{1}{4},...) \notin c_{00}$, $y_1=(1,0,0,...)$, $y_2=(1,\frac{1}{2},0,0,...)$ and so on. $y_n \in c_{00}$ and $\|y_n -y \|_{\infty}=\frac{1}{n+1}$ which tends to $0$ when $n$ tends to $\infty$.
Your estimate holds only in a neighborhood of $x$. Hence, you need can not control whether you may choose such a $C$ independent of $x$. You need to rely on the linearity of your operator in the following way: By continuity of $f$ in $0$, there exists $\delta>0$ such that for all $x\in X$ with $\Vert x \Vert_X <\delta$ holds $$\vert f(x) - f(0) \vert ...
Since $f$ is continuous (at $0$), there is a neighbourhood $U$ of $0$ such that $f(U)\subset(-1,1)$. Choose $\delta>0$ such that $\{x\in X|\|x\|\leq\delta\}\subseteq U$. Then, if $x\in X$ is such that $\|x\|\leq \delta$, we have $x\in U$, and hence, $|f(x)|\leq 1$. Since $\|\frac{\delta x}{\|x\|}\|=\delta$, it follows that for all $x\in X$ we have $$ ...
The $\ell^p$ spaces are a special case of the $L^p$ spaces obtained by using the counting measure on the set of natural numbers. If you squint closely at the integral it looks like a sum or indeed as Forever Mozart points out: summation is just integration with the trivial measure on $\mathbb{N}$.
A fancy approach to Lagrange's identity: differentiation. $$\frac{\partial}{\partial a}(a^2+b^2)(c^2+d^2) = 2a(c^2+d^2),$$ $$\frac{\partial}{\partial a}\left((ac-bd)^2+(ad+bc)^2\right)=2c(ac-bd)+2d(ad+bc) $$ they match, and the same happens for $\frac{\partial}{\partial b},\frac{\partial}{\partial c},\frac{\partial}{\partial d}$, so $(a^2+b^2)(c^2+d^2)$ and ...
You can check this directly: $$(ac-bd)²+(ad+bc)²=(ac)²+(bd)²-2abcd+(ad)²+(bc)²+2abcd$$ $$=a²(c²+d²)+b²(c²+d²)=(a²+b²)(c²+d²).$$ $25988=2²\times 73\times 89=2²(8²+3²)(8²+5²)=2²[(8²-15)²+(40+24)²]=98²+128²$
The first part of the problem reduces the complexity of the second, by writing $AB$ as a sum of two squares if $A$ and $B$ are, but does not lead to a mechanical solution. To start the process one needs to find factors of 25988 that can be written as sums of two squares. There is a theorem of Fermat that only numbers with an even power of every prime of ...
The prime factorization of $25988$ is $2^2 \cdot 73 \cdot 89$. Observe that $73 = 3^2 + 8^2$ and $89 = 5^2 + 8^2$. Using the norm formula, we have \begin{equation*} \begin{aligned} 25988 &= 2^2(3^2 + 8^2)(5^2 + 8^2) \\ &= 2^2((3 \cdot 5 - 8 \cdot 8)^2 + (3 \cdot 8 + 8 \cdot 5)^2) \\ &= 2^2(49^2 + 64^2) \\ &= 98^2 + 128^2, \end{aligned} ...
You might note that $ac-bd$ and $ad+bc$ are the real and imaginary parts of $(a+ib)(c+id)$, so the formula says $|zw|^2 = |z|^2 |w|^2$ where $z= a+ib$ and $w=c+id$. For the second part, it might help that $25988 = 2^2 \times 73 \times 89$. Can you write $2$, $73$, $89$ each as the sum of two squares?
Hint valid for any inner product space: the norm is a composition of functions: $$x\longmapsto(x,x)\longmapsto\langle x,x\rangle\longmapsto\sqrt{\langle x,x\rangle} = \|x\|$$ and $\langle\cdot,\cdot\rangle$ is bilinear.
The differential is given by, $$Df(x_1,x_2) = \left( \frac{x_1}{\|x\|}, \frac{x_2}{\|x\|} \right)$$ which has defined for $x \in \mathbb{R}^2 \setminus \{0\}$
Let $\{a_n\}$ be a sequence of positive real numbers that increases to $1$, with the property that the sequence of products $$ a_1,\ a_1a_2,\ a_1a_2a_3,\ a_1a_2a_3a_4,\ \ldots$$ converges to a positive value. It's not hard to write down a specific example. Let $\cal H = \ell^2(\mathbf R)$ and define $T : \cal H \to \cal H$ by $$T(x_1,x_2,x_3,\ldots) = (0, ...
Explicit continuous functions that work on the unit interval (i.e. demonstrate the failure of the parallelogram law holding) are $f(x) = 1-x$ and $g(x) = x$. $2||f||^2_\infty = 2$ and $2||g||^2_\infty = 2$, while $||f+g||^2_\infty = 1$ and $||f-g||^2_\infty = 1$.
$\kappa_2(A) = |\sigma_{\max}|/|\sigma_{\min}|$, your formula only holds if $A$ is normal. In this case we have that $\sigma_{\max} = 1.9896$ and $\sigma_{\min} = 0.4974$ and $$\dfrac{1.9896}{0.4974} \approx 4$$
There is a simple reason why you can't. Take two opposite vectors with arbitrary little norm. The difference between the two can be as small as you wish but the difference between their normalized counterparts will always be of norm 2. For instance in $\mathbb R^2$ : $x1=(\frac 1 n,0),x_2=(-\frac 1 n,0),n\in \mathbb N$, the difference has norm $\vert\vert ...
Note that $\langle Tw, Tw\rangle=\langle w, w\rangle$. Taking $w=u-v$ gives $\langle T(u-v),T(u-v)\rangle=\langle(u-v),(u-v)\rangle\implies \left| u-v\right|^2=\left|Tu-Tv\right|^2$
Top 50 recent answers are included


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Solution Brief: Intel and SAP are using HTML5 to efficiently bring SAP Business ByDesign* apps to multiple platforms. By using HTML5, SAP was able to reduce the time to port apps between platforms from weeks to just days.
A smart health vehicle developed at the University of Kansas uses Intel® technology-based tablets and the Intel® IoT Gateway to help nurse practitioners address the critical shortage of primary care providers in rural America.
Princess Cruise Lines uses Intel® Core™ vPro™ processors to remotely manage 6,000 enterprise PCs, helping Princess IT leaders to reduce downtime and costs, streamline management, and improve productivity.
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Find a better way to work and achieve greater productivity, mobility, and collaboration with 5th generation Intel® Core™ vPro™ processors.
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IDC Executive Brief: Enabling the Full Potential of Windows 10 for Business
This brief by global market intelligence leader IDC outlines how Windows 10 may address challenges faced by client computing, security, and compliance teams, and examines how well current hardware takes advantage of these core functions and features.
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From the walls of the Bhimbetka cave shelters to the illustrated pages of Mughal manuscripts like Baburnama to the paintings of the colonial era, the tiger has occupied pride of place in our cultural and artistic consciousness. 53 more words
Tags » Ecosphere
Lessons from Paravur: Ban them. Ban them quick.
The Paravur firework tragedy which took place in my home district (Kollam) in Kerala spelt out three distinct emotions in me—grief, anger and ignominy. Grief at the death of a hundred people, anger at the little regard temple authorities had for instructions and ignominy at the inability of our institutions to enforce bans. 248 more words
India's carbon strategy to counter climate change
Indian government is now looking to retrofit existing national action plans on climate change while building new ones. With the date of signing of the historic Paris climate change agreement in April approaching fast, and its ratification to follow soon, that's good to hear. 37 more words
The unlivable lake
'Live fish swim against the stream, while dead ones float with it'
When hundreds of fish washed ashore on Bengaluru's Ulsoor Lake yesterday, the words of Rt. 47 more words
The only way is up, baby - Agriculture meets architecture in France's urban farm tower
Built like a staircase, ABF-lab's urban farming structure aims to raise awareness and encourage better living and social responsibility.
Source: Agriculture meets architecture in France's urban farm tower
Number 1. The attractions of the great outdoors- hill walking – what could possibly be relaxing about tramping up a hill in the middle of a Queensland summer, surrounded by…..wild things…? 416 more words
Ecosphere Technologies Receives 14th U.S. Patent for OZONIX(R) Advanced Oxidation Process
STUART, FL ESPH, (Marketwired March 08, 2016) Ecosphere Technologies, Inc. (OTCQB: ESPH), a technology development and intellectual property licensing company, today announced that the United States Patent and Trademark Office (USPTO) has approved a 14th United States Patent for Ecosphere s multi-patented OZONIX® Advanced Oxidation Process (AOP) technology. 99 more words


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...I am also prepared to suggest additional materials that might be helpful for a particular student in a specific subject area. I am familiar with a number of very helpful resources. Before working at the tutoring center, I was actively involved in the homeschooling community.
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Retractions are on the rise. But reams of flawed research papers persist in the scientific literature. Is it time to change the way papers are published?
Incubator Boom
March 1, 2014|
From San Francisco to St. Louis, biotech incubators are proliferating across North America. Can they deliver on their promise of fueling the economy?


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Sample Apology Letter to Bank for Cheque Bounce
Dear sir/ madam,
Subject: requesting to accept my apology for the check bounce – regarding.
This is the letter to convey my apology for the check bounce that was been issued by me to a company. First of all I should regret for my behaviour and I regret for it in a very precise manner. The check I have been provided as the final settlement for the product has been bounced since there in no money in the account. The reason for that situation is at that instance of time I could not able to maintain the balance due to some personal reasons. This is the worst thing and I knew it. Though I don't have any other way to convey my sorry I take this opportunity to ask for apology and retain my cheque. I promise I'll not behave worse / do the mistake again.
Thank you
Points to remember : Apology Letter to Bank for Cheque Bounce
Regret for your behaviour.
Promise that this will not happen again.
Request to accept your apology.
Other Sample example letter format are
- apology letter to bank for cheque bounce
- cheque bounced letter to bank
- apologising for cheque return
- to the lic manager for apologise cheque bouncing
- sorry for the return cheque
- sample letter to bank for cheque return
- reply letter against cheque bouncing
- letter to bank manager for cheque return
- How to write a letter to bank my check is bounced
- how to write a letter to bank for bounce my cheque


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Keywords: Sam King, UR4, character, making of
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"If it didn't cost more to print the book, we shouldn't have to pay more. It's not that the materials are better, it's just better information."
Related quotes
"If all printers were determined not to print anything till they were sure it would offend nobody, there would be very little printed"
"I haven't deteriorated or gone insane. Suddenly, I just can't get anything into print. And apparently I'm not alone in this. There are people of very high standing, authors who are having problems. So I have been told."
"Some said, `John, print it'; others said, `Not so.' / Some said, `It might do good'; others said, `No'."
"I feel so bad about that. That's not enough, but I couldn't convince the publisher to print a 500-page children's book."
"Sir, I have two cogent reasons for not printing any list of subscribers; - one, that I have lost all the names, - the other, that I have spent all the money"


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Big Cat Rescue > Big Cat Totes & Bags > Snow Leopard Totes & Bags > Snow Leopard Beach Tote
In this section your will find many totes and bags made from many different photos of snow leopards. Your purchases help to provide for the care of the 100+ big cats at Big Cat Rescue in Tampa, Flori
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some howtos:Submitted by srlinuxx on Thursday 23rd of October 2008 04:57:24 AM Filed under
- Hands-on Hadoop for cluster computing
- How to Convert .FLAC to .MP3 In Ubuntu
- Awesome-menu in Awesome Window Manager
- Multiple keyboard layouts in XFCE... and outside it
- Performance tuning with System Control (sysctl) in Ubuntu
- Adjust the fan speed on you NVida graphics card
- Using bootchart to capture your boot process openSUSE 11
- HOWTO : Penguinzilla (DRBL) on Ubuntu 8.04.1
- Kubuntu Intrepid Dual Monitor Blinking
- Changing Default OS On Dual-Boot System (Ubuntu)
some howtos:Submitted by srlinuxx on Monday 20th of October 2008 09:47:53 PM Filed under
- Quickly Convert Ogg Theora to Flash Video
- Linux: Find and remove matching files
- Take Screenshots in Xfce
- Configure LVM in Mandriva Linux Free 2009
- Resizing Logical Volume (LVM) on ext3
- Emacs - Getting Paragraphs to Wrap Lines
- Bash Script To Access Wikipedia
- Linux setup default gateway with route command
- Converting 2.35 Aspect Video to DVD
How To Install OpenOffice.org 3.0.0 On Ubuntu 8.04Submitted by falko on Sunday 19th of October 2008 08:32:37 PM Filed under
This guide shows how you can install the new OpenOffice 3.0.0 office suite on your Ubuntu 8.04 desktop. Your current OpenOffice installation will not be removed unless you uninstall it with Synaptic or on the command line, so you can run both versions in parallel if you like.
few howtos:Submitted by srlinuxx on Sunday 19th of October 2008 08:52:37 AM Filed under
- How to network Vista, XP, Linux and OS X
- Some tips for correcting UUIDs in Ubuntu
- memstat: Identify what is using up virtual memory
some howtos:Submitted by srlinuxx on Saturday 18th of October 2008 06:30:03 PM Filed under
- Customizing PCLinuxOS 2008 Minime
- bashrun on opensuse
- How to Backup Evolution
- Mastering IPTables, Part 2
- How To Install Free42 in Ubuntu
- Advanced Tips For The ps Command
- Commands you should never run
some howtos:Submitted by srlinuxx on Saturday 18th of October 2008 04:12:50 AM Filed under
- Four top tips for installing software on to Linux PCs
- Connect to a wireless network with the command line
- Command Line Bookmarks
- Fun with Commands-I
- Short Tip: GNU Screen with proper scroll, session management support
- How to use samba on the command line
- Sabayon - Sipie for Sirius Radio
- Howto: Burn Audio Cd's From mp3 in ubuntu
- Building ffmpeg on Ubuntu Linux
- Suspend on Dell D820 openSUSE 11.1 (Beta 2) Nvidia Driver
- Automatically process new files with fsniper
The Perfect Server - Mandriva 2009.0 Free (i386)Submitted by falko on Thursday 16th of October 2008 11:08:37 AM Filed under
This is a detailed description about how to set up a Mandriva 2009.0 Free server that offers all services needed by ISPs and hosters: Apache web server (SSL-capable), Postfix mail server with SMTP-AUTH and TLS, BIND DNS server, Proftpd FTP server, MySQL server, Dovecot POP3/IMAP, Quota, Firewall, etc.
some howtos:Submitted by srlinuxx on Wednesday 15th of October 2008 09:00:56 PM Filed under
- Tweak Your Font Rendering for Better Appearance
- Float irregular images on your Web pages with pngslice
- Bash Command Line Shortcuts
- Why do the BSD's use slices? What are they?
- How to import PDFs into OpenOffice.org 3.0
- How to install Adobe Flash Player 10 in Ubuntu 8.04
- /proc explained
- Mandriva Linux 2009 Firewall
The Perfect Desktop - Mandriva One 2009.0 With GNOMESubmitted by falko on Wednesday 15th of October 2008 10:47:49 AM Filed under
This tutorial shows how you can set up a Mandriva One 2009.0 desktop (with the GNOME desktop environment) that is a full-fledged replacement for a Windows desktop, i.e. that has all the software that people need to do the things they do on their Windows desktops.
some howtos:Submitted by srlinuxx on Tuesday 14th of October 2008 05:23:20 PM Filed under
- Run your virtual OS directly from GDM in Ubuntu
- Using EasyUbuntu
- One Linux Formatting Tip I Bet You Didn't Know
- How to add Ubuntu 8.04 to win server 2003 Active Directory Domain
- Let PAM take care of GNU/Linux security for you
- Turning off automatic gnome-session
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Devuan Beta, Stumbling Tumbleweed, Ubuntu Too
Today in Linux news Debian-fork Devuan is forging ahead with its plans to create a distribution offering init freedom by releasing a beta for testers. Douglas DeMaio posted today that openSUSE Tumbleweed snapshots have halted due to glibc upgrade rebuilds. Dedoimedo reviewed the BQ Aquaris M10 and liliputing.com posted of another Ubuntu laptop for sale. And finally, the Hectic Geek reviewed Ubuntu 16.04 and Neil Rickert reviewed Kubuntu 16.04. Also: Devuan releases beta Devuan Jessie - beta release announcement
Devuan Jessie beta released
dear Init Freedom Lovers, once again the Veteran Unix Admins salute you. As promised two years ago with the first declaration of Exodus from Debian, today we can proudly state: we do not go gentle into that good night. Now has come the time to announce the Beta release of Devuan. Debian GNU+Linux is a fork of Debian without systemd, on its way to become much more than that. This Beta release marks an important milestone towards the sustainability and the continuation of Devuan as an universal base distribution. Also: Beta Released Of Devuan, The Systemd-Free Version Of Debian
GNOME News
Today in Techrights


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Southend Airport is a journey in itself. A far off mystical place that was the start of our journey. For some reason, we had chosen to fly out of there, early to make the most of a full day off work. 945 more words
Tags » Normandie
13 July 2100, 3Bn 330 IR, Moves into Position in Rear between Sainteny, Culot, and Hottot
By evening of 13 July 3rd Bn, 330 IR has moved back behind the line, closer to 2nd Bn, close to Sainteny. We are actually given the very precise positions of I Co., K Co., and M Co.; nice. 25 more words
13 July 2000, 2Bn 330 IR, Moves into Reserve near Sainteny
Another 13 July overlay. This is fairly straight forward. 2 Bn, 330 IR moves back into reserve between Sainteny and Culot. It will be left behind as the rest of 330 IR moves toward les Champs-de-Losque, to the right of 1 Bn, 60 IR, 9 ID. 8 more words
#Travel #500px : Chateau fort de Pirou by alf2525 by alf2525 #photography#IFTTT
The Pirou (france. Chateau de Pirou) Castle is not far from Lessay on the Cotentin peninsula in Normandy in France. According to legend, the middle of an artificial lake lowland castle should be a fixture from the 12th century. 6 more words
I love weekend trips, and in France, taking a weekend trip is being in some kind of other big historical endroit. I have done a few weekend trips to Normandy, a region in northern France. 461 more words
New on 500px : what a night by StefanieBaars by StefanieBaars
Nach einem leicht bewölkten Tag zog sich pünktlich zur goldenen Stunde eine dicke wolkendecke über dem Mont Saint Michel zusammen und es gab tatsächlich nur einen kurzen Moment, an dem die Sonne sich blicken ließ aber dieser Moment war so intensiv …. 8 more words


text:
This item is currently
HN-OB008 Otis Bed
Futon Grip StripsItem # HN-OB008
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- Foam grip strips keep mattress from sliding
- Adhere to back and seat of futon frame
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Full Description
Guarantee & Returns
Recommended Accessories
Otis Bed
Futon Grip Strips
Here's an idea that's sure to stick: the Futon Grip Strips keep your futon mattress in place and prevent it from sliding down in the frame. The strips are designed so that the bottom of the strip adheres to the slats of the frame, and the strip's foam top holds the mattress by the friction that's created between the foam strip and the fabric. No more slipping and sliding, just a perfectly snug mattress.About Otis Bed ManufacturingIn business for more than 125 years, Otis Bed Manufacturing Compan


text:
Does olanzapine make you sleepy, and gain weight?
- Posted:
- 13 Dec 2009 by pili
- Topics:
- insomnia, olanzapine, weight
Answers (1)
13 Dec 2009
This medication can make you sleepy. But I did not see anything on weight gain. For a list of other side effects check this web site out.
Yes, olanzapine is well known to cause weight gain by slowng down glucose and lipid metabolism, its a very effective drug though.
Olanzapine is both very sedating and can cause extreme weight gain. I have been on the maximum dosage for it for about 2 years now. I gained 3 stone in weight from the drug but I was too skinny for my height so I welcomed the weight gain. I like the sleep it gives me as I used to suffer insomnia, I find after about an hour of taking it I fall into a very deep sleep.
i found olanzapine to be really good at controlling my manic episodes, but i had other side effects including disturbed sleep, bad itching of the skin on my neck and cleavage and large rapid gain of weight approximately 80 pounds. However i would not go off it as it has been the only thing that controls my mania.
Further Information
- Olanzapine Information for Consumers
- Olanzapine Information for Healthcare Professionals (includes dosage details)
- Side Effects of Olanzapine (detailed)
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Foursquare © 2016 Lovingly made in NYC & SF
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Alisyn Camerota Celebrity Watchlist
Alisyn Camerota
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Marco Rubio's campaign trail playlist00:50 — In an interview with CNN's Alisyn Camerota Marco Rubio spoke about his love of music and what he's listening to on the campaign trail.
Rubio responds to criticism from his ...00:57 — In an interview with CNN's Alisyn Camerota, presidential candidate Marco Rubio spoke about uniting the Republican party and dismissed criticism from h (more…)
Fox News Anchor Jokes Female Co-Hosts Picked from Victoria's Secret Catalogues'Fox and Friends' host Brian Kilmeade is taking flack for saying on his radio show that his female colleagues on Fox News are selected by searching th (more…)
Obama, Holder talk Ferguson03:38 — Alisyn Camerota talks to two men who were at the administration's discussions about Ferguson on Monday.
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Twelve Longmire short stories available for the first time in a single volume—featuring an introduction by Lou Diamond Phillips of the hit drama series Longmire, now on Netflix
Ten years ago, Craig Johnson...
The fourth book in the series finds Verlaque and Bonnet on vacation on a remote island in the glittering Mediterranean
Like Donna Leon and Andrea Camilleri, M. L. Longworth's books enchant mystery lovers with...
The fifth book in the new Penguin Maigret series: Georges Simenon's gripping tale of small town suspicion and revenge, in Linda Asher's timeless translation.
There was an exaggerated humility about her. Her cowed...
A new translation of Georges Simenon's sensational tale of deceit and back-stabbing in an isolated community, book six in the new Penguin Maigret series.
'She came forward, the outlines of her figure blurred...
Fan favorite Etta Mae Wiggins takes center stage in the latest novel by the New York Times bestselling author, Ann B. Ross
Bestselling author Ann B. Ross is back with another lively adventure set in Miss Julia's...
Inspector John Madden—who debuted in River of Darkness—returns in a gripping post–World War II murder mystery
On a quiet afternoon in 1947, retired bank manager Oswald Gibson is shot in the head while fishing....
• Winner of the Strand Critics Award for Best First Novel • Nominated for the Barry and Macavity Awards for Best First Novel • Longlisted for the CWA John Creasy (New Blood) Dagger Award
The intrepid Edie Kiglatuk discovers one of her female students dead in a toxic lake in her third arctic mystery
In the third novel in this highly praised mystery series that will appeal to fans of The Killing...
A bestseller in the UK, this gripping thriller of a family that vanishes into thin air is Tim Weaver's American debut
Emily Kane arrives at her sister Carrie's house to find the front door unlocked, dinner...
The seventeenth installment of the beloved New York Times bestselling series that boasts more than 600,000 books in print
The last four books in Andrea Camilleri's Inspector Montalbano series have leapfrogged...
Winner of the Theakstons Old Peculier Crime Novel of the Year Award and Nominated for a Macavity Award for Best First Mystery Novel
No two victims are alike.
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An Australian teacher with stress-related problems ripped the head off an Easter Bunny mascot at Bunnings and yelled at the crowd that the bunny was not real, a court has been told.
Children began crying after Darren John Harry said: "It's not the real Easter Bunny. He's a fraud. Bunnings is a fraud taking down local hardware stores just like Mitre 10."
The first attack happened when the Easter Bunny was giving children high fives and posing for photographs at the New South Wales store in March, the Border Mail reported.
The person wearing a three-piece costume, including a helmet assembly with chin strap and large pink ears, had his head and neck jerked backwards when the bunny's head was pulled by Harry and the chin strap broke.
Another employee asked several times for Harry to leave the store before being shoved.
He lost his balance, fell backwards into a child and then to the ground. The whole incident was captured on closed-circuit camera.
Harry was charged with offensive behaviour, malicious damage and two counts of assault.
His solicitor Jason Hanke said Harry was extremely stressed on the day with a disabled child missing from home.
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60 Minutes kidnap child Theo Johnstone breaks silence
Air strikes pound Syria's Aleppo, 'calm' farther southwest
Refugees stuck in limbo while waiting to come to NZ - 'Each day is like a year'
Protesters storm into Baghdad's Green Zone, political crisis deepens
Grandmother, four grandchildren killed in Texas floods amid torrential rain
Rescuers search rubble of Nairobi building, at least 12 dead
Woman killed in Upper Hutt crash was driver's grandmother
Kiwi William Trubridge breaks his own freediving world record in the Bahamas
Barack Obama doesn't disappoint at final star-studded correspondents' dinner
Elderly man attacked and injured in Hastings home invasion
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python-clinic / Doc / library / numbers.rst
:mod:`numbers` --- Numeric abstract base classes
The :mod:`numbers` module (PEP 3141) defines a hierarchy of numeric :term:`abstract base classes <abstract base class>` which progressively define more operations. None of the types defined in this module can be instantiated.
The root of the numeric hierarchy. If you just want to check if an argument x is a number, without caring what kind, use isinstance(x, Number).
The numeric tower
Subclasses of this type describe complex numbers and include the operations that work on the built-in :class:`complex` type. These are: conversions to :class:`complex` and :class:`bool`, :attr:`.real`, :attr:`.imag`, +, -, *, /, :func:`abs`, :meth:`conjugate`, ==, and !=. All except - and != are abstract.
To :class:`Complex`, :class:`Real` adds the operations that work on real numbers.
In short, those are: a conversion to :class:`float`, :func:`math.trunc`, :func:`round`, :func:`math.floor`, :func:`math.ceil`, :func:`divmod`, //, %, <, <=, >, and >=.
Real also provides defaults for :func:`complex`, :attr:`~Complex.real`, :attr:`~Complex.imag`, and :meth:`~Complex.conjugate`.
Subtypes :class:`Real` and adds :attr:`~Rational.numerator` and :attr:`~Rational.denominator` properties, which should be in lowest terms. With these, it provides a default for :func:`float`.
Subtypes :class:`Rational` and adds a conversion to :class:`int`. Provides defaults for :func:`float`, :attr:`~Rational.numerator`, and :attr:`~Rational.denominator`. Adds abstract methods for ** and bit-string operations: <<, >>, &, ^, |, ~.
Notes for type implementors
Implementors should be careful to make equal numbers equal and hash them to the same values. This may be subtle if there are two different extensions of the real numbers. For example, :class:`fractions.Fraction` implements :func:`hash` as follows:
def __hash__(self): if self.denominator == 1: # Get integers right. return hash(self.numerator) # Expensive check, but definitely correct. if self == float(self): return hash(float(self)) else: # Use tuple's hash to avoid a high collision rate on # simple fractions. return hash((self.numerator, self.denominator))
Adding More Numeric ABCs
There are, of course, more possible ABCs for numbers, and this would be a poor hierarchy if it precluded the possibility of adding those. You can add MyFoo between :class:`Complex` and :class:`Real` with:
class MyFoo(Complex): ... MyFoo.register(Real)
Implementing the arithmetic operations
We want to implement the arithmetic operations so that mixed-mode operations either call an implementation whose author knew about the types of both arguments, or convert both to the nearest built in type and do the operation there. For subtypes of :class:`Integral`, this means that :meth:`__add__` and :meth:`__radd__` should be defined as:
class MyIntegral(Integral): def __add__(self, other): if isinstance(other, MyIntegral): return do_my_adding_stuff(self, other) elif isinstance(other, OtherTypeIKnowAbout): return do_my_other_adding_stuff(self, other) else: return NotImplemented def __radd__(self, other): if isinstance(other, MyIntegral): return do_my_adding_stuff(other, self) elif isinstance(other, OtherTypeIKnowAbout): return do_my_other_adding_stuff(other, self) elif isinstance(other, Integral): return int(other) + int(self) elif isinstance(other, Real): return float(other) + float(self) elif isinstance(other, Complex): return complex(other) + complex(self) else: return NotImplemented
There are 5 different cases for a mixed-type operation on subclasses of :class:`Complex`. I'll refer to all of the above code that doesn't refer to MyIntegral and OtherTypeIKnowAbout as "boilerplate". a will be an instance of A, which is a subtype of :class:`Complex` (a : A <: Complex), and b : B <: Complex. I'll consider a + b:
- If A defines an :meth:`__add__` which accepts b, all is well.
- If A falls back to the boilerplate code, and it were to return a value from :meth:`__add__`, we'd miss the possibility that B defines a more intelligent :meth:`__radd__`, so the boilerplate should return :const:`NotImplemented` from :meth:`__add__`. (Or A may not implement :meth:`__add__` at all.)
- Then B's :meth:`__radd__` gets a chance. If it accepts a, all is well.
- If it falls back to the boilerplate, there are no more possible methods to try, so this is where the default implementation should live.
- If B <: A, Python tries B.__radd__ before A.__add__. This is ok, because it was implemented with knowledge of A, so it can handle those instances before delegating to :class:`Complex`.
If A <: Complex and B <: Real without sharing any other knowledge, then the appropriate shared operation is the one involving the built in :class:`complex`, and both :meth:`__radd__` s land there, so a+b == b+a.
Because most of the operations on any given type will be very similar, it can be useful to define a helper function which generates the forward and reverse instances of any given operator. For example, :class:`fractions.Fraction` uses:
def _operator_fallbacks(monomorphic_operator, fallback_operator): def forward(a, b): if isinstance(b, (int, Fraction)): return monomorphic_operator(a, b) elif isinstance(b, float): return fallback_operator(float(a), b) elif isinstance(b, complex): return fallback_operator(complex(a), b) else: return NotImplemented forward.__name__ = '__' + fallback_operator.__name__ + '__' forward.__doc__ = monomorphic_operator.__doc__ def reverse(b, a): if isinstance(a, Rational): # Includes ints. return monomorphic_operator(a, b) elif isinstance(a, numbers.Real): return fallback_operator(float(a), float(b)) elif isinstance(a, numbers.Complex): return fallback_operator(complex(a), complex(b)) else: return NotImplemented reverse.__name__ = '__r' + fallback_operator.__name__ + '__' reverse.__doc__ = monomorphic_operator.__doc__ return forward, reverse def _add(a, b): """a + b""" return Fraction(a.numerator * b.denominator + b.numerator * a.denominator, a.denominator * b.denominator) __add__, __radd__ = _operator_fallbacks(_add, operator.add) # ...


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