A charge of 4 C is passing through points A and B on a circuit. If the charge's electric potential changes from 15 J to 11 J, what is the voltage between points A and B?

Jan 5, 2018

The voltage is $= 1 V$

Explanation:

Apply the equation

$\text{Energy"(J)}$ $= \text{ Electric potential(V)"xx"Charge (C)}$

The charge is $Q = 4 C$

The energy is $\Delta E = 15 - 11 = 4 J$

The voltage is

$U = \frac{\Delta E}{Q} = \frac{4}{4} = 1 V$
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