Loading tabs, please wait... PostAbout... > The Social > Homework If you see this install Flash Player. Uker - Mar 18 2008, 03:14 PM
Post #1
 Group: Members Posts: 5,138 Joined: 24-June 05 Location: New Yawk Guilds: The Empire, The FFA, Hylian-Legends, D2GM, duckfluffed Gold: 1.51 Staff-Certified TrustyTrader

Diablo 2 Accounts:
*Uker No idea where to start............ thanks for help lotd - Mar 18 2008, 09:50 PM
Post #2 Group: Price Checker Posts: 3,758 Joined: 1-December 04 Guilds: The Empire Gold: 34.26 Neutral/Unrated Trader Okies, let's see how well I remember related rates lol..

So first off, when the player is halfway on his way to first base, his distance from first base is 45 feet.

You can make a triangle from player/first base/second base.

So you get a triangle with lengths 45, 90, 45*root5 which i will call sides a,b,c respectively.

You know the rate the player is running at is 24 ft/s. This value is da/dt

Now you set up your related rates problem.

a^2 + b^2 = c^2

Now you take the derivative. b is a constant 90 and doesn't change so it goes to 0.

you are left with:

2a*da/dt = 2c*dc/dt

You are looking for the rate at distance from second base is decreasing, so that is dc/dt.

Solve for dc/dt and you get 24/root5

If you form a triangle with third base now, you notice it is the same. In this case the rate the player's distance from second base is decreasing is the same at which his distance from 3rd base is increasing.

a) Decreasing at 24/root5 ft/s or -24/root5 ft/s Increasing at 24/root5 ft/s

Hope this helps. (and that it is correct lmao) Uker - Mar 18 2008, 10:04 PM
Post #3
 Group: Members Posts: 5,138 Joined: 24-June 05 Location: New Yawk Guilds: The Empire, The FFA, Hylian-Legends, D2GM, duckfluffed Gold: 1.51 Staff-Certified TrustyTrader

Diablo 2 Accounts:
*Uker Okies, let's see how well I remember related rates lol..

So first off, when the player is halfway on his way to first base, his distance from first base is 45 feet.

You can make a triangle from player/first base/second base.

So you get a triangle with lengths 45, 90, 45*root5 which i will call sides a,b,c respectively.

You know the rate the player is running at is 24 ft/s. This value is da/dt

Now you set up your related rates problem.

a^2 + b^2 = c^2

Now you take the derivative. b is a constant 90 and doesn't change so it goes to 0.

you are left with:

2a*da/dt = 2c*dc/dt

You are looking for the rate at distance from second base is decreasing, so that is dc/dt.

Solve for dc/dt and you get 24/root5

If you form a triangle with third base now, you notice it is the same. In this case the rate the player's distance from second base is decreasing is the same at which his distance from 3rd base is increasing.

a) Decreasing at 24/root5 ft/s or -24/root5 ft/s Increasing at 24/root5 ft/s

Hope this helps. (and that it is correct lmao)

thank youuuu, but is root5 square root of 5? √5?? if so.....where did you get 45*√5? or the √5 in general lol

appreciate it though man <33's lotd - Mar 18 2008, 10:30 PM
Post #4 Group: Price Checker Posts: 3,758 Joined: 1-December 04 Guilds: The Empire Gold: 34.26 Neutral/Unrated Trader Okies, let's see how well I remember related rates lol..

So first off, when the player is halfway on his way to first base, his distance from first base is 45 feet.

You can make a triangle from player/first base/second base.

So you get a triangle with lengths 45, 90, 45*root5 which i will call sides a,b,c respectively.

You know the rate the player is running at is 24 ft/s. This value is da/dt

Now you set up your related rates problem.

a^2 + b^2 = c^2

Now you take the derivative. b is a constant 90 and doesn't change so it goes to 0.

you are left with:

2a*da/dt = 2c*dc/dt

You are looking for the rate at distance from second base is decreasing, so that is dc/dt.

Solve for dc/dt and you get 24/root5

If you form a triangle with third base now, you notice it is the same. In this case the rate the player's distance from second base is decreasing is the same at which his distance from 3rd base is increasing.

a) Decreasing at 24/root5 ft/s or -24/root5 ft/s Increasing at 24/root5 ft/s

Hope this helps. (and that it is correct lmao)

thank youuuu, but is root5 square root of 5? √5?? if so.....where did you get 45*√5? or the √5 in general lol

appreciate it though man <33's

root5 = square root of five.

You get it from the Pythagorean theorem. 45^2 + 90^2 = C^2
C=45*root5

root5 is just easier to type than square root of 5 lol.. Uker - Mar 18 2008, 11:10 PM
Post #5
 Group: Members Posts: 5,138 Joined: 24-June 05 Location: New Yawk Guilds: The Empire, The FFA, Hylian-Legends, D2GM, duckfluffed Gold: 1.51 Staff-Certified TrustyTrader

Diablo 2 Accounts:
*Uker Okies, let's see how well I remember related rates lol..

So first off, when the player is halfway on his way to first base, his distance from first base is 45 feet.

You can make a triangle from player/first base/second base.

So you get a triangle with lengths 45, 90, 45*root5 which i will call sides a,b,c respectively.

You know the rate the player is running at is 24 ft/s. This value is da/dt

Now you set up your related rates problem.

a^2 + b^2 = c^2

Now you take the derivative. b is a constant 90 and doesn't change so it goes to 0.

you are left with:

2a*da/dt = 2c*dc/dt

You are looking for the rate at distance from second base is decreasing, so that is dc/dt.

Solve for dc/dt and you get 24/root5

If you form a triangle with third base now, you notice it is the same. In this case the rate the player's distance from second base is decreasing is the same at which his distance from 3rd base is increasing.

a) Decreasing at 24/root5 ft/s or -24/root5 ft/s Increasing at 24/root5 ft/s

Hope this helps. (and that it is correct lmao)

thank youuuu, but is root5 square root of 5? √5?? if so.....where did you get 45*√5? or the √5 in general lol

appreciate it though man <33's

root5 = square root of five.

You get it from the Pythagorean theorem. 45^2 + 90^2 = C^2
C=45*root5

root5 is just easier to type than square root of 5 lol..

hahha aight thanks - this can be closed 0 User(s) are reading this topic (0 Guests and 0 Anonymous Users)
0 Members:
 « Next Oldest · Homework · Next Newest » Lo-Fi Version Time is now: 14th December 2019 - 07:08 AM
{"ft_lang_label":"__label__en","ft_lang_prob":0.9360173,"math_prob":0.9243218,"size":5635,"snap":"2019-51-2020-05","text_gpt3_token_len":1738,"char_repetition_ratio":0.12626532,"word_repetition_ratio":0.9050279,"special_character_ratio":0.3110914,"punctuation_ratio":0.12275449,"nsfw_num_words":0,"has_unicode_error":false,"math_prob_llama3":0.9689462,"pos_list":[0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99,100,101,102,103,104,105,106,107,108,109,110,111,112,113,114,115,116,117,118,119,120,121,122,123,124,125,126,127,128,129,130,131,132,133,134,135,136,137,138,139,140,141,142,143,144,145,146,147,148,149,150,151,152,153,154,155,156,157,158,159,160,161,162,163,164,165,166,167,168],"im_url_duplicate_count":[null,null,null,2,null,2,null,4,null,4,null,9,null,9,null,3,null,9,null,1,null,null,null,null,null,null,null,3,null,null,null,9,null,null,null,null,null,9,null,9,null,null,null,9,null,9,null,null,null,5,null,9,null,null,null,null,null,9,null,null,null,null,null,9,null,9,null,null,null,9,null,9,null,3,null,9,null,null,null,null,null,null,null,3,null,null,null,9,null,null,null,null,null,9,null,9,null,null,null,9,null,9,null,null,null,5,null,9,null,null,null,null,null,null,null,null,null,9,null,null,null,null,null,9,null,9,null,null,null,9,null,9,null,3,null,9,null,null,null,null,null,null,null,null,null,3,null,null,null,9,null,null,null,null,null,9,null,9,null,null,null,4,null,4,null,2,null,2,null],"WARC_HEADER":"{\"WARC-Type\":\"response\",\"WARC-Date\":\"2019-12-14T13:08:55Z\",\"WARC-Record-ID\":\"<urn:uuid:c457497c-50a1-44b0-bd18-254e0c414ebe>\",\"Content-Length\":\"144307\",\"Content-Type\":\"application/http; msgtype=response\",\"WARC-Warcinfo-ID\":\"<urn:uuid:8fa64db6-c7e3-41af-b159-6b4fce83f473>\",\"WARC-Concurrent-To\":\"<urn:uuid:5c0f297e-436c-4ea3-9ca1-0f3bc6dcab10>\",\"WARC-IP-Address\":\"24.49.212.249\",\"WARC-Target-URI\":\"http://www.amerfs.com/index.php?s=3ea7ab991b0aaa15651cd53f47a74e92&showtopic=413495&pid=2220118&st=0\",\"WARC-Payload-Digest\":\"sha1:RIC7IS23BHRLIMALMZASX5LDOJNOZLO5\",\"WARC-Block-Digest\":\"sha1:BGRCPFZA4S4DRM7WLLNXRZVKNAJEA2U3\",\"WARC-Identified-Payload-Type\":\"application/xhtml+xml\",\"warc_filename\":\"/cc_download/warc_2019/CC-MAIN-2019-51/CC-MAIN-2019-51_segments_1575541157498.50_warc_CC-MAIN-20191214122253-20191214150253-00255.warc.gz\"}"}