## Equal height of elements inside grid item with CSS grid layout

Is it even possible? tldr; Yes. Codepen Demo #1 Codepen Demo # 2 (Uses SASS and is configurable) The difficulty here is that each article is a grid within itself and therefore any one article has no knowledge about another. Because of this, there is no way for a component of one article like a … Read more

## How to append rows to an R data frame

Update Not knowing what you are trying to do, I’ll share one more suggestion: Preallocate vectors of the type you want for each column, insert values into those vectors, and then, at the end, create your data.frame. Continuing with Julian’s f3 (a preallocated data.frame) as the fastest option so far, defined as: # pre-allocate space … Read more

## Collapse rows with overlapping ranges

You can try this: library(dplyr) ranges %>% arrange(start) %>% group_by(g = cumsum(cummax(lag(stop, default = first(stop))) < start)) %>% summarise(start = first(start), stop = max(stop)) # A tibble: 2 × 3 # g start stop # <int> <dbl> <dbl> #1 0 65.72000 87.75625 #2 1 89.61625 104.94062

## How to remove rows with any zero value

There are a few different ways of doing this. I prefer using apply, since it’s easily extendable: ##Generate some data dd = data.frame(a = 1:4, b= 1:0, c=0:3) ##Go through each row and determine if a value is zero row_sub = apply(dd, 1, function(row) all(row !=0 )) ##Subset as usual dd[row_sub,]

## Compare Python Pandas DataFrames for matching rows

One possible solution to your problem would be to use merge. Checking if any row (all columns) from another dataframe (df2) are present in df1 is equivalent to determining the intersection of the the two dataframes. This can be accomplished using the following function: pd.merge(df1, df2, on=[‘A’, ‘B’, ‘C’, ‘D’], how=’inner’) For example, if df1 … Read more

## remove IDs that occur x times R

You can use table like this: df[df\$names %in% names(table(df\$names))[table(df\$names) >= 5],]

## sum cells of certain columns for each row

You could do something like this: summed <- rowSums(zscore[, c(1, 2, 3, 5)])

## Numpy – add row to array

You can do this: newrow = [1, 2, 3] A = numpy.vstack([A, newrow])

## For each row in an R dataframe

You can use the by() function: by(dataFrame, seq_len(nrow(dataFrame)), function(row) dostuff) But iterating over the rows directly like this is rarely what you want to; you should try to vectorize instead. Can I ask what the actual work in the loop is doing?

## How to get number of rows in using JavaScript?

Well I found a much simplier way to do this, but you’ll need to set the line-height of the textarea in the CSS. I tried to read the line height inside the script ta.style.lineHeight but it doesn’t seem to return a value. CSS #ta { width: 300px; line-height: 20px; } HTML <textarea id=”ta”>Lorem ipsum dolor … Read more
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