## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 249: 57

#### Answer

One that open upwards: $y=x^2-9$ One that open downwards: $y=-x^2+9$

#### Work Step by Step

Use: $y=a(x-x_1)(x-x_2)$, where $x_1$ and $x_2$ are the $x$ of the x-intercepts. $y=a[x-(-3)](x-3)=a(x^2-9)$ One that open upwards ($a\gt0$). $y=1(x^2-9)=x^2-9$ One that open downwards ($a\lt0$). $y=-1(x^2-9)=-x^2+9$

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