# The number of molecules in 22.4cm3 of nitrogen gas at STP is a) 6.022×10 to the power 20 b) 6.022×10 to the power 23 c) 22.4×10 to the power 20 d) 22.4×10 to the power 23

Dear student,
In 1 mole of gas ,
the no. of L = 22.4 L = 22.4*1000 cm³. = 22400 cm³.

now for 22.4 cm³ ,
the no. of moles will be
= 22.4/22400 = 0.001
so the no. of molecules will be 0.001*(6.022×1023)
= 6.022×1020 molecules.

Regards

• 3
There are 6.022*10^23 molecules present in 22400cm^3 gas.
Therefore the no. of molecules present in 22.4cm^3=

6.022*10^23 * 22.4cm^3 divide by:
224000 cm^3

Hence we get the ans as 6.022*10^20 molecules.
• 24
There are 6.022*10^23 molecules present in 22400cm^3 gas.?
Therefore the no. of molecules present in 22.4cm^3=?

6.022*10^23 * 22.4cm^3 divide by:?
224000 cm^3?

Hence we get the ans as 6.022*10^20 molecules. Hope u will get it
• 3
=6.022*10^20 MOLECULES
• 6
6.022×10^23
• -6
6.022*10 to the power23
• 2
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