## Algebra and Trigonometry 10th Edition

$x=-3; y=-3$
We need to solve for $x$ by subtracting $y$ from both sides. $x-y=0 \implies x=y ...(1)$ Now, plug the value of $x$ into the second equation. $2(y)-3y=3 \implies y=-3$ We will plug the value of $y$ into the first equation, giving: $x=-3$ Thus, $x=-3; y=-3$
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