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### Transcript of CHAPTER ONE SOL PROBLEMS Lines and Angles Vertical angles are equal 15x – 5 = 10x + 35 5x...

Modified and Animated By Chris Headlee

Nov 2011

CHAPTER ONE SOL PROBLEMS

SOL Problems; not Dynamic Variable Problems

• Lines and Angles

Vertical angles are equal

15x – 5 = 10x + 35

5x – 5 = 35

5x = 40

x = 8

Substitute: m1 = 15(8) – 5 = 115

SSM:

•1 is obtuse; only answer J works

• Coordinate Relations and Transformations

Midpoint formula:

[(x1 + x2)/2 , (y1 + y2)/2] = [(1 + x)/2 , (1 + y)/2] = [-2, 0]

(1 + x)/2 = -2  1 + x = -4 (1 + y)/2 = 0  1 + y = 0

x = -5 y = -1

SSM:

•plot points and see

which make sense

• Lines and Angles

Angle 1 and Angle 2 are complimentary

1 + 2 = 90°

(4x + 12) + (6x + 8) = 90

10x + 20 = 90

10x = 70

x = 7

m 1 = 4(7) + 12 = 40°

SSM:

•Corner of scratch paper tells

us that 1+2=90°

•Our eyes tell us that 2 > 1,

but not by much

•Answers A & B are possible,

with B fitting better

• Lines and Angles

Vertical Angles are equal

2x + 20 = 60

2x = 40

x = 20

SSM:

•Two acute angles:

assume equal

• Lines and Angles

Vertical angles are equal

6x + 12 = 9x – 4

6x + 16 = 9x

16 = 3x

16/3 = x

SSM:

•Our eyes tell us that 1 and

2 are small acute angles

only F and G give small

acute angles

• Coordinate Relations and Transformations

SSM:

•which is in the middle and

on SR

Midpoint formula:

(-4+ 8) , (-5+1)

-------- -------

2 2

(2, -2)

• Coordinate Relations and Transformations

Pythagorean Theorem or Distance formula

6² + 10² = AC² √(-5 – 5)² + (3 – (-3))²

36 + 100 = AC² √(-10)² + (6)²

136 = AC² √(100 + 36)

11.67 = AC √136 = 11.67

SSM:

•measure AC

•use graph to estimate

• Coordinate Relations and Transformations

SSM:

•draw BD

•which is in the middle and on BD

Midpoint formula:

(-3+ 2) , (-6+5)

-------- -------

2 2

(-0.5, -0.5)

• Coordinate Relations and Transformations

Midpoint formula:

(3+ x) , (2+y)

-------- ------- = (6, -2)

2 2

(3 + x, 2 + y) = (12, -4)

(x, y) = (9, -6)

y

x

SSM:

•plot given midpoint and

endpoint of graph

E

M

• Coordinate Relations and Transformations

midpoint formula: ( (x1+x2)/2 , (y1+y2)/2 )

( (3+6)/2 , (3+6)/2 ) = (9/2, 9/2) = (4.5, 4.5)

SSM:

graph paper

AB

• Lines and Angles

x + y = 90 complementary

x – y = 18 difference of 18

2x = 108 (add line 1 and 2)

x = 54

SSM:

• complement  adds to 90

• eliminates H and J

• Coordinate Relations and Transformations

•Midpoint ((12-5)/2, (2-7)/2) = (7/2, -5/2) = (3.5, -2.5)

SSM:

•draw endpoints on graph paper

• Angle x is an acute angle

Three angles sum to 180

missing angle is 30 (vertical angle)

80 + 30 = 110 180 – 110 = 70

SSM:

•Angle 2 is large acute

•Angle x is smaller than 80 but

bigger than 65

Lines and Angles

• Lines and Angles

Angle x is an acute angle

To form an “x” – two straight lines

need to have a vertical angle

x = 55

SSM:

•Angle x is an acute angle

•“vertical” angles!

• Coordinate Relations and Transformations

midpoint formula: ( (x1+x2)/2 , (y1+y2)/2 )

( (3+6)/2 , (3+6)/2 ) = (9/2, 9/2) = (4.5, 4.5)

SSM:

•plot each answer on graph paper

• Coordinate Relations and Transformations

distance formula:

√(x2 – x1)² + (y2 – y1)²

√(-2 – 3)² + (2 – 0)²

√(-5)² + 2² = √29

SSM:

•measure AC on scratch paper

• lay out on graph and estimate

the distance

• Lines and Angles

Straight line means linear pair (supplementary angles)

180 – 136 = 44

SSM:

•x is an acute angle

•180 is a magic number

•180 – 136 = 44

• Lines and Angles

SSM:

•which is “magic” number, 180

• Coordinate Relations and Transformations

midpoint formula:

( (x1+x2)/2 , (y1+y2)/2 )

( (-2+3)/2 , (2+0)/2 ) = (1/2, 2/2) = (1/2, 1)

SSM:

•plot each answer on graph paper

• Coordinate Relations and Transformations

Pythagorean Theorem or Distance formula

5² + 12² = AC² √(-2 – 3)² + (-4 – 8)²

25 + 144 = AC² √(-5)² + (-12)²

169 = AC² √(25 + 144)

13 = AC √169 = 13

SSM:

•plot points on graph paper

•measure distance with

scratch paper

•use graph paper to

estimate distance

• Lines and Angles

x and y form linear pairs with adjacent angles

180 – 82 = 98 = y

180 – 89 = 91 = x

SSM:

•both are obtuse angles

• subtract from 180

• Lines and Angles

To ensure A, C and E are collinear

x must be a vertical angle

x = 85

SSM:

• corner of scratch paper

x is large acute angle – not

quite 90

• Lines and Angles

3 angles of triangle add to 180

180 – 90 – 62 = 28

SSM:

•angle is small acute

• Lines and Angles

angle MON = 40 (linear pair with 140)

angle NMO = 58 (vertical with 58)

angle N = 180 – 40 – 58 = 82

SSM:

•use corner of scrap paper

•angle N is very large acute

• Polygons and Circles

Linear pair: sums to 180

x + 2x = 180

3x = 180

x = 60

SSM:

•angle CAB is acute

double answers to see which is

obtuse

• Coordinate Relations and Transformations

Greatest distance from origin will result in the greatest sum of numbers squared!

A) 8² + 5² = 64 + 25 = 89

B) 9² + 1² = 81 + 1 = 82

C) 3² + 4² = 9 + 16 = 25

D) 9² + 2² = 81 + 4 = 85

89 is the largest so A is correct answer

Pythagorean Theorem or Distance formula can also be used for each point

SSM:

•plot points on graph paper

•measure distance with

scrap paper

• Coordinate Relations and Transformations

midpoint formula: ( (x1+x2)/2 , (y1+y2)/2 )

( (5+7)/2 , (1+4)/2 ) = (12/2, 5/2) = (6, 2.5)

SSM:

•plot each answer on graph paper

• Lines and Angles

150 is an exterior angle

by Ext Angle Theorem 150 = 65 + 3

85 = 3

SSM:

•angle 3 is large acute

eliminates A and D

• Complements  adds to 90

90 = (14x + 8) + (8x – 6)

= 22x + 2

88 = 22x

4 = x m1 = 14(4) + 8 = 56 + 8 = 64

SSM:
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