# 1/2 + 1/4 + 1/8 + 1/16 + …

${\frac {1}{2}}+{\frac {1}{4}}+{\frac {1}{8}}+{\frac {1}{16}}+\cdots ={\frac {\frac {1}{2}}{1-(+{\frac {1}{2}})}}=1.$ ## 注释

1. ^ Description of Zeno's paradoxes. [2008-12-21]. （原始内容存档于2009-01-26）.
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