# 50 J of heat is produced each second in a 5 Ω resistance. The potential difference across the resistor is

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HSSC Group D Previous Year Paper 5 (Held On : 18 Nov 2018 Shift 1 )
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1. $$\sqrt{50}$$ V
2. 40 V
3. $$\sqrt{10}$$ V
4. 10 $$\sqrt{5}$$ V

Option 3 : 5 $$\sqrt{10}$$ V
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Haryana Group D 2018 Full Mock Test
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## Detailed Solution

The correct answer is $$\sqrt{10}$$ V Key Points

• The potential difference (or voltage) of a supply is a measure of the energy given to the charge carriers in a circuit.
• To Calculate the potential difference across the resistor:-
• Given:-
• Heat= 50 J, T= 1 Sec, R= 5 Ω
• The produced heat is given as,
• H=I2Rt
• 50= I2×5×1
• I =$$\sqrt{10} A$$
• The potential difference is given as,
• V= IR
• =$$\sqrt{10} *5$$
• =$$5\sqrt{10}$$
• Thus, the potential difference across the resistor is $$5\sqrt{10}$$ V.
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