# How do you combine (4n-3n^3)-(3n^3+4n)?

$\left(4 \textcolor{red}{n} - 3 \textcolor{b l u e}{{n}^{3}}\right) - \left(3 \textcolor{b l u e}{{n}^{3}} + 4 \textcolor{red}{n}\right)$
$= 4 \textcolor{red}{n} - 3 \textcolor{b l u e}{{n}^{3}} - 3 \textcolor{b l u e}{{n}^{3}} - 4 \textcolor{red}{n}$
$= \left(4 n - 4 n\right) - \left(3 {n}^{3} + 3 {n}^{3}\right)$
$= - 6 {n}^{3}$
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