# Calculate Force of 4 Spheres on 1 Sphere

• Scorpiogrl
In summary: Finally, do the same for B, C and D.In summary, the problem asks to calculate the magnitude and direction of the gravitational force on one sphere due to the other three, given their masses and the distance between them. Using the formula F=G(mass of #1)(mass of #2)/r^2, you can find the attraction force between two adjacent spheres. By considering all possible combinations of the four spheres, you can find the total force acting on each individual sphere.

## Homework Statement

Four 9.5 kg spheres are located at the corners of a square of side 0.60 m. Calculate the magnitude and direction of the gravitational force on one sphere due to the other three.

## Homework Equations

F=G(mass of #1)(mass of #2)/r^2
F=G(mass of #1)(mass of #3)/r^2
F=G(mass of #1)(mass of #2)/r^2
For #3 take Fsin(45)=x value
For #3 x value=y value

F=squareroot(x^2+y^2)

Scorpiogrl said:

## Homework Statement

Four 9.5 kg spheres are located at the corners of a square of side 0.60 m. Calculate the magnitude and direction of the gravitational force on one sphere due to the other three.

## Homework Equations

F=G(mass of #1)(mass of #2)/r^2
F=G(mass of #1)(mass of #3)/r^2
F=G(mass of #1)(mass of #2)/r^2
For #3 take Fsin(45)=x value
For #3 x value=y value

F=squareroot(x^2+y^2)

## The Attempt at a Solution

Since you are given the mass and separation of these spheres, you could use the standard formula to find the attraction force between two adjacent spheres.
Let's call that F at the moment.

Now, suppose the 4 spheres are A, top Left; B top Right; C bottom Left; D Bottom Right.

Consider Sphere C.
A pulls up with force F [as calculated above.
D pulls Right with Force F
B bulls diagonally with a force less than F, because it is forther away. But you know how much further so can calculate the force.

Now just add those three forces as vectors and you have it.

Now do A, B and D
{"ft_lang_label":"__label__en","ft_lang_prob":0.82012594,"math_prob":0.99242944,"size":425,"snap":"2023-40-2023-50","text_gpt3_token_len":152,"char_repetition_ratio":0.17577197,"word_repetition_ratio":0.028169014,"special_character_ratio":0.34117648,"punctuation_ratio":0.04,"nsfw_num_words":0,"has_unicode_error":false,"math_prob_llama3":0.99990964,"pos_list":[0],"im_url_duplicate_count":[null],"WARC_HEADER":"{\"WARC-Type\":\"response\",\"WARC-Date\":\"2023-12-11T15:46:14Z\",\"WARC-Record-ID\":\"<urn:uuid:ce771717-6d3e-456d-a16e-e760221ad337>\",\"Content-Length\":\"60654\",\"Content-Type\":\"application/http; msgtype=response\",\"WARC-Warcinfo-ID\":\"<urn:uuid:c4df1fb7-d318-4e86-a8cc-46bdfb0a0774>\",\"WARC-Concurrent-To\":\"<urn:uuid:2f94b2ab-8c3a-4bc4-91ae-da842afd6b54>\",\"WARC-IP-Address\":\"172.67.68.135\",\"WARC-Target-URI\":\"https://www.physicsforums.com/threads/calculate-force-of-4-spheres-on-1-sphere.549085/\",\"WARC-Payload-Digest\":\"sha1:YES3MKDR64YTTPW6NB47XJTEK4BXRRDI\",\"WARC-Block-Digest\":\"sha1:WMFCZISP5JMLA7E5EVFDFMXWCYCL32C4\",\"WARC-Identified-Payload-Type\":\"text/html\",\"warc_filename\":\"/cc_download/warc_2023/CC-MAIN-2023-50/CC-MAIN-2023-50_segments_1700679515260.97_warc_CC-MAIN-20231211143258-20231211173258-00676.warc.gz\"}"}