# How do you find the horizontal asymptote for 4/(1+e^(1-x)) ?

$y = 4$ and $y = 0$ are horizontal asymptotes

#### Explanation:

Let $y = \frac{4}{1 + {e}^{1 - x}}$

Try to imagine the value of $y$ if $x$ is made to increase up to $+ \infty$

As $x$ approaches the value $+ \infty$
$y$ approaches $4$

Try to imagine the value of $y$ if $x$ is made to decrease down to $- \infty$

As $x$ approaches the value $- \infty$
$y$ approaches $0$

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