Question

# Given that y=(cx+d)b,where b≠0. If ax+by+c=0 , where (a+c)≠0, then what is the value of x ?

A
(d+c)(a+c)
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B
(dc)(a+c)
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C
(a+c)(d+c)
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D
(d+c)(a+c)
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Solution

## The correct option is B (−d−c)(a+c)Given ax+by+c=0. Also given that y=(cx+d)b. Substituting this in ax+by+c=0, we get ax+[b(cx+d)b]+c=0. So, ax+cx+d+c=0 ⇒(a+c)x=−d−c ∴ x=(−d−c)(a+c) Suggest Corrections 0 Similar questions Related Videos Algebraic Solution
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