In the given figure, potential difference between A and B is (1) 0

(2) 5 volt

(3) 10 volt

(4) 15 volt

(3) Equivalent resistance $R=10+\frac{10}{2}=15\text{\hspace{0.17em}}k\Omega$

Current i = $\frac{30}{15}=2×{10}^{-3}A$

Hence, potential difference between A and B

$V=\left(\frac{2×{10}^{-3}}{2}\right)×10×{10}^{3}=10\text{\hspace{0.17em}}Volt\text{.}$

Difficulty Level:

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