# 2010 AMC 8 Problems/Problem 14

## Problem

What is the sum of the prime factors of $2010$? $\textbf{(A)}\ 67\qquad\textbf{(B)}\ 75\qquad\textbf{(C)}\ 77\qquad\textbf{(D)}\ 201\qquad\textbf{(E)}\ 210$

## Solution

First, we must find the prime factorization of $2010$. $2010=2\cdot 3 \cdot 5 \cdot 67$. We add the factors up to get $\boxed{\textbf{(C)}\ 77}$

## Video by MathTalks

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.
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