How do you draw the condensed structural formulas of four structural isomers of the carboxylic acids that have the molecular formula C_5H_10O_2?

Jul 21, 2016

The isomers of compound having molecular formula ${C}_{5} {H}_{10} {O}_{2}$ should contain $- C O O H$.So it contains ${C}_{4} {H}_{9} -$ as alkyl group.
Depending on the structures of alkyl groups there are following isomers of carboxylic acids with their condensed formulae.

1.Sraight chain of 4 C-atom

$C {H}_{3} C {H}_{2} C {H}_{2} C {H}_{2} C O O H \to \text{Pentanoic acid}$

2.One methyl group as branch at C-2

$C {H}_{3} C {H}_{2} \left(C {H}_{3}\right) C H C O O H \to \text{2-methylbutanoic acid}$

3.One methyl group as branch at C-3

$C {H}_{3} \left(C {H}_{3}\right) C H C {H}_{2} C O O H \to \text{3-methylbutanoic acid}$

4.Two methyl groups as branches at C-2

${\left(C {H}_{3}\right)}_{3} C . C O O H \to \text{2,2-dimethylpropanoic acid}$
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