# The first term of

Let the first term, common difference and the number of terms of an AP are a, d and n respectively.

Given that, first term, a = - 5

last term, an = 45

Sum of the terms of the AP , Sn = 120

We know that, if last term of an AP is known, then sum of n terms of an AP is, 240 = 40n

n = 6

Also we know the nth term formula

an = a + (n - 1)d

45 = - 5 + (6 - 1)d

50 = 5d

d = 10

Hence, number of terms and the common difference of an AP are 6 and 10 respectively.

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