# How do you factor 6x^2+9x+4x+6?

Oct 27, 2016

$\left(2 x + 3\right) \left(3 x + 2\right)$

#### Explanation:

There are 4 terms and there is no common factor.
Group them to create a common factor and put in brackets.
There MUST be a PLUS sign between the brackets.

$\left(6 {x}^{2} + 9 x\right) + \left(4 x + 6\right)$

=$3 x \left(2 x + 3\right) + 2 \left(2 x + 3\right)$

Now there is a common bracket. $\left(2 x + 3\right) \left(3 x + 2\right)$
{"ft_lang_label":"__label__en","ft_lang_prob":0.8233499,"math_prob":0.99999845,"size":383,"snap":"2020-34-2020-40","text_gpt3_token_len":99,"char_repetition_ratio":0.1292876,"word_repetition_ratio":0.0,"special_character_ratio":0.2532637,"punctuation_ratio":0.08974359,"nsfw_num_words":0,"has_unicode_error":false,"math_prob_llama3":0.99618405,"pos_list":[0],"im_url_duplicate_count":[null],"WARC_HEADER":"{\"WARC-Type\":\"response\",\"WARC-Date\":\"2020-08-08T15:30:06Z\",\"WARC-Record-ID\":\"<urn:uuid:5433d945-9968-4810-8476-5f272a3d21f9>\",\"Content-Length\":\"32409\",\"Content-Type\":\"application/http; msgtype=response\",\"WARC-Warcinfo-ID\":\"<urn:uuid:fce91b35-8c2b-4b6d-b633-7133c5a3cb34>\",\"WARC-Concurrent-To\":\"<urn:uuid:2dc32f8e-b305-4e7b-98d4-536c6c201f40>\",\"WARC-IP-Address\":\"216.239.32.21\",\"WARC-Target-URI\":\"https://socratic.org/questions/how-do-you-factor-6x-2-9x-4x-6\",\"WARC-Payload-Digest\":\"sha1:546KVZAMCPP72KCQXYAO6ABZ76VFF65J\",\"WARC-Block-Digest\":\"sha1:3333A35VNNPLWZE5HJW4A2PUBJEHIV2K\",\"WARC-Identified-Payload-Type\":\"text/html\",\"warc_filename\":\"/cc_download/warc_2020/CC-MAIN-2020-34/CC-MAIN-2020-34_segments_1596439737883.59_warc_CC-MAIN-20200808135620-20200808165620-00371.warc.gz\"}"}