# 9(E) = 8VZtem3/2 1. (20 points) The Fermi energy in copper is 7.04 eV. a) What...

###### Question: 9(E) = 8VZtem3/2 1. (20 points) The Fermi energy in copper is 7.04 eV. a) What percentage of free electrons in copper are in the excited state at room temperature, 25°C? b) What percentage of free electrons in copper are in the excited state at the melting point of copper, 1083°C? The density of energy states per unit volume per unit energy interval in copper is given by 8V2m3/2 ZVĒ. h3VE, Note the m is the mass of an electron and h is h not h with a bar. The Fermi energy of a metal is h2 (3n 2/3 ềf = 2m (81) where n is the number density of available electrons (one for every atom) per unit volume. Note that you will get a Fermi energy of 7.04 eV. This is what I have given you. This is the lowest occupied level and thus this should be the lower limit on your integral. Use this Fermi energy for the Fermi level for both temperatures and ignore the small changes in density with temperature.

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