# Alphabet Number Series Quiz Set 060

### Question 1

If the first half of the following series is reversed, then which item is 6th to the right of the 12th item from the right side? The series is:

\$ U K Y S P B O 9 C 8 V @ 1 D 6 T J H N

A

P

B

D

C

9

D

H

Soln.
Ans: b

Midpoint is 10. We have to find 20 - 12 + 6 = 14 + 1th item from the left side. Since the location lies in the right half, reversing the series has no effect in this zone. So counting from the left side, the item is D.

### Question 2

If the following series is reversed, then which item comes at position 11 counted from the left? The series is:

Y W 9 % A X E G F 5 S Z 6 D U K B 1 C M

A

9

B

5

C

Z

D

6

Soln.
Ans: b

The item at position 11 is total items + 1 - 11 which is 20 + 1 - 11 = 10. Counting from the left we get 5.

### Question 3

Which letter will be the 4th from right if 1st and 2nd, 3rd and 4th and so on are interchanged in the word FRAUDULENCES?

A

C

B

U

C

E

D

D

Soln.
Ans: a

The new letter is: RFUAUDELCNSE

### Question 4

Study the following series.

3 S C U G + Z B 8 1 F A D 5 7 @ H W I K

Find what should come in place of the question mark(?)

GZ, 8F, D7, ?

A

BS

B

+S

C

SZ

D

HI

Soln.
Ans: d

There is a gap of 3 between the first characters of each of the given pair. The second character of each pair is two positions to to the right of the first character.

### Question 5

Below is a series of numbers from 1 through 9. Some of them repeat. How many 8 does it contain such that they are completely divisible by both the two predecessors to their left?

8 4 8 7 3 8 3 2 5 6 8 4 2 4 8 1 8 7 7

A

4

B

3

C

0

D

1

Soln.
Ans: b

At these locations: 8-4-8 ;2-4-8 ;8-1-8 ;
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