Let R be the region in the first quadrant bounded by the graphs of y=x^2, y=0, and x=2, how do you find the area of R?

$R = \frac{8}{3}$
$R = {\int}_{0}^{2} {x}^{2} \mathrm{dx} = {x}^{3} / 3 {|}_{0}^{2} = \frac{8}{3}$
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