Qalaxia QA Bot
0

I found an answer from physics.stackexchange.com

Is the de Broglie wavelength of a photon equal to the EM ...

May 10, 2013 ... 1) Yes. The photon's matter wave is actually its electromagnetic wave. 2) Photon emission is not such a kind of process when you get some ...

For more information, see Is the de Broglie wavelength of a photon equal to the EM ... Qalaxia Info Bot
0

I found an answer from www.britannica.com

Electromagnetic radiation - Development of the quantum theory of ...

The Faraday-Maxwell-Hertz theory of electromagnetic radiation seemed to be able to ... It was his idea to use as a good approximation for the ideal blackbody an oven ... The energy hν of a photon of this wavelength is equal to the rest mass energy mc ... with a momentum p has, according to de Broglie, a wavelength λ = h/p. Qalaxia Knowlege Bot
0

I found an answer from en.wikipedia.org

Matter wave - Wikipedia

Matter waves are a central part of the theory of quantum mechanics, being an example of ... The de Broglie wavelength is the wavelength, λ, associated with a massive ... to consist of waves of electromagnetic fields which propagated according to ... More recent experiments prove the quantum nature of molecules made of ... Qalaxia Master Bot
0

De Broglie wavelength (video) | Khan Academy

Bohr model energy levels (derivation using physics) ... Since visible light has a wavelength of about 500 nanometers, this means that visible ... couldn't they explain the photoelectric effect by saying that the light is a wave that carries ... it applies only for particles that travel at near-light speed because in the relation you used ... Veda
0

Step 1: Wavelength of the electromagnetic radiation

Wavelength of electromagnetic radiation is inversely proportional to the frequency.

Equation that relates to wavelength, frequency, and speed of light.

\lambda = \frac{c}{\upsilon} ..................(1)

Step 2: de Broglie wavelength of photon

de Broglie wavelength \lambda = \frac{h}{p} .....................(2)

Where, h - Planck constant = 6.63* 10^{-34} J   and p - linear momentum.

We know that

Where an object has no mass, such as a photon, the energy equation is reduced to

E = pc

Where, p - momentum and c - speed of light

p = \frac{E}{c}

p = \frac{h \upsilon}{c}                                    \because Energy of proton E=h\upsilon\

Step 3: Substituting the p(momentum) value in equation (2)

de Broglie wavelength  \lambda = \frac{h}{ \frac{h \upsilon}{c}}

de Broglie wavelength   \lambda = \frac{c}{\upsilon} ..........................(3)

From equation (1) and (3) we can conclude that

Wavelength of the electromagnetic radiation = de Broglie wavelength of photon
{"ft_lang_label":"__label__en","ft_lang_prob":0.8651639,"math_prob":0.9950805,"size":2815,"snap":"2022-40-2023-06","text_gpt3_token_len":670,"char_repetition_ratio":0.17644966,"word_repetition_ratio":0.11479029,"special_character_ratio":0.260746,"punctuation_ratio":0.2512479,"nsfw_num_words":0,"has_unicode_error":false,"math_prob_llama3":0.997519,"pos_list":[0,1,2,3,4,5,6,7,8,9,10],"im_url_duplicate_count":[null,null,null,null,null,null,null,null,null,null,null],"WARC_HEADER":"{\"WARC-Type\":\"response\",\"WARC-Date\":\"2023-01-27T00:49:10Z\",\"WARC-Record-ID\":\"<urn:uuid:2858088f-be7b-4722-8ee3-aea986104386>\",\"Content-Length\":\"36351\",\"Content-Type\":\"application/http; msgtype=response\",\"WARC-Warcinfo-ID\":\"<urn:uuid:86628458-dc67-4b19-bbee-7902a97316d3>\",\"WARC-Concurrent-To\":\"<urn:uuid:707f6c6c-71c2-4d05-9d46-0a3eabe04830>\",\"WARC-IP-Address\":\"3.215.73.129\",\"WARC-Target-URI\":\"https://www.qalaxia.com/questions/Show-that-the-wavelength-of-electromagnetic-radiation-is-equal-to\",\"WARC-Payload-Digest\":\"sha1:DHLJJMHSFJF7UGWANEINVIEXQVNXFOBM\",\"WARC-Block-Digest\":\"sha1:LXDSHVX5PT6HT4INRLPZZ6I66T5RPJIA\",\"WARC-Identified-Payload-Type\":\"application/xhtml+xml\",\"warc_filename\":\"/cc_download/warc_2023/CC-MAIN-2023-06/CC-MAIN-2023-06_segments_1674764494852.95_warc_CC-MAIN-20230127001911-20230127031911-00138.warc.gz\"}"}