# How do you simplify (4i)(-2i)(-8+4i)?

Sep 4, 2016

$\left(4 i\right) \left(- 2 i\right) \left(- 8 + 4 i\right) = - 64 + 32 i$

#### Explanation:

While multiplying complex numbers we should always remember that ${i}^{2} = - 1$.

Hence, $\left(4 i\right) \left(- 2 i\right) \left(- 8 + 4 i\right)$

= -8i^2×(-8+4i)

= -8×(-1)(-8+4i)

= 8×(-8+4i)

= $- 64 + 32 i$
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