# Game of poker Discrete Math

Here is my attempt at solving these questions: Ok so since there is 52 cards in total and 5 in a hand $52 \choose 5$=2,598,960. I'm not sure how to solve this. Any help would be great!

First choose one of the 13 ranks for the 3 of a kind cards, next choose 3 of the 4 cards from that rank. Next choose two more ranks for the individual cards and then choose 1 of the 4 for each of the other two ranks. In this way you get $\binom {13} 1\binom 4 3\binom {12} 2\binom 4 1\binom 4 1$.
Alternatively, choose two of the 13 ranks for the 1 of a kind cards first, then choose one of each of the two ranks, then choose one of the remaining 11 ranks for the 3 of a kind cards, and choose 3 of the 4 cards from that rank. $\binom {13} 2\binom 4 1\binom 4 1\binom {11} 1\binom 4 3$.
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