# Calculation of Titration problems - Should be Easy?

## Homework Statement

1. Calculate the volume (mL) of 0.100 M H3PO4 required to neutralize 30.0 mL of 0.050 M

2. If 0.2178 g of a diprotic solid acid is neutralized by 44.81 mL of 0.0953 M NaOH, calculate the molar mass of the solid acid.

## Homework Equations

Molar Mass = Mass/Moles
Concentration = Moles/Volume(mL)
Neutralization --> Moles of H+ = Moles of OH-

## The Attempt at a Solution

First Problem
For this problem, I've already done work to arrive to my answer, I just require someone else's opinion on whether it is right or not. I also felt lazy to type out the work for this one, since this problem is not that important and is easier compared to the second one (which is why I showed work for the second problem and not this one, hopefully you guys understand).

The volume I derived from the problem was that you needed 10 mL of H3PO4; is this correct?

Second Problem

For the second problem, I will show work:

44.81 mL x 0.0953 M = 4.27 moles of NaOH = 4.27 moles of OH-

4.27 moles of OH- imply that you need 4.27 moles of H+ for neutralization

Because the solid acid is diprotic, that means there are two acidic hydogens, which means the chemical formula for the acid is H2X, X being the remaining part of the acid's formula.

To get 4.27 moles of H+, then you would need (4.27/2), or 2.14 moles of H2X?

Since there was 0.2178 g of the diprotic solid acid, then the molar mass would be mass/moles, or 0.2178 g/ 2.14 moles = 0.101 g/mol

At this point, I got confused because the molar mass was so small; can anyone confirm whether or not this is truly the right answer?

Last edited:
{"ft_lang_label":"__label__en","ft_lang_prob":0.9233933,"math_prob":0.9489556,"size":1602,"snap":"2022-27-2022-33","text_gpt3_token_len":474,"char_repetition_ratio":0.12265331,"word_repetition_ratio":0.0,"special_character_ratio":0.29525593,"punctuation_ratio":0.12637363,"nsfw_num_words":0,"has_unicode_error":false,"math_prob_llama3":0.99751526,"pos_list":[0],"im_url_duplicate_count":[null],"WARC_HEADER":"{\"WARC-Type\":\"response\",\"WARC-Date\":\"2022-07-05T12:36:14Z\",\"WARC-Record-ID\":\"<urn:uuid:b1bb4fc2-f9be-4b43-8e93-1ba27d715aaa>\",\"Content-Length\":\"64397\",\"Content-Type\":\"application/http; msgtype=response\",\"WARC-Warcinfo-ID\":\"<urn:uuid:1f080918-7eed-47dd-96ec-baa83f7ab924>\",\"WARC-Concurrent-To\":\"<urn:uuid:7e4353c7-c1b8-419e-a486-6ae242b9c375>\",\"WARC-IP-Address\":\"104.26.15.132\",\"WARC-Target-URI\":\"https://www.physicsforums.com/threads/calculation-of-titration-problems-should-be-easy.548434/\",\"WARC-Payload-Digest\":\"sha1:JMOH2NHLOY7PI3N4OT7MN5T5CYVL7IUZ\",\"WARC-Block-Digest\":\"sha1:WN4H7RTUYHJR53IAWA5VT4AMCFVQOXJW\",\"WARC-Identified-Payload-Type\":\"text/html\",\"warc_filename\":\"/cc_download/warc_2022/CC-MAIN-2022-27/CC-MAIN-2022-27_segments_1656104576719.83_warc_CC-MAIN-20220705113756-20220705143756-00547.warc.gz\"}"}