# A projectile is shot from the ground at a velocity of 32 m/s and at an angle of (3pi)/4. How long will it take for the projectile to land?

Nov 2, 2016

$t = \frac{16 \sqrt{2}}{5} \sec$

#### Explanation:

Here,$u = 32 \frac{m}{s}$, $\theta = \frac{3 \pi}{4}$

$t = \frac{2 u \sin \theta}{g}$

$t = \frac{2 \times 32 \times \frac{1}{\sqrt{2}}}{10}$

$t = \frac{32 \times \frac{\sqrt{2}}{2}}{5}$

$t = \frac{16 \sqrt{2}}{5} \sec$
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