## Algebra 2 (1st Edition)

Since the coefficient of the squared term is one, we know that the expression must factor to: $$(x\pm a)(x\pm b)$$ Here, we see that a and b must multiply to get $-45$ and add to get $-12$. Thus, we find that the solution is: $$(x-15)(x+3)$$ Thus, setting each factor equal to zero, we find that the solutions are: $$-3, 15$$
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