Question

# A five digit number is formed by the digits 1, 2, 3, 4, 5, 6 and 8.  The probability that the number has even digit at both ends is:  None372747

Solution

## The correct option is C 27Total number of 5 digit numbers obtained by the digits 1, 2,3,4,5,6 and 8 =7P5=7.6.5.4.3=2520. There are 4 even digits (2, 4, 6 and 8). ∴ 2 even digits can be selected in 4C2=6 ways  ∴ The two ends can be filled in 2×6=12 ways. Remaining 3 places from remaining 5 digits can be filled in 5P3=60 ways Hence the required probability =12×602520=27 Short cut: Suggest corrections
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