Selina solutions

# Question 1

Q1) Reduce the given fractions to their lowest terms :

(i) \frac{8}{10}

(ii) \frac{50}{75}

(iii) \frac{18}{81}

(iv) \frac{40}{120}

(v) \frac{105}{70}

Solution:

(i)\frac{8}{10}=\frac{8\div2}{10\div2}=\frac{4}{5}

(ii)\frac{50}{75}=\frac{50\div25}{75\div25}=\frac{2}{3}

(iii)\frac{18}{81}=\frac{18\div9}{81\div9}=\frac{2}{9}

(iv)\frac{40}{120}=\frac{40\div40}{120\div40}=\frac{1}{3}

(v)\frac{105}{70}=\frac{105\div35}{70\div35}=\frac{3}{2}

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