From: Forrest, a secondary school student I'm having a little trouble with these arithmetic and geometric sequence problems and I was hoping you could help me. They are similar problems, one deals with arithmetic sequences and the other deals with geometric sequences. 1) Find three successive terms in an arithmetic sequence such that their sum is 24 and their product is 440 2) Find three successive terms in a geometric sequence such that their sum is 21 and their product is 216 Thanks!! ~Forrest Hi Forrest, I'll give you some help on the first problem. The sequence is arithmetic so let's suppose that the first of your three terms id k and the common difference is d. The three terms are then k, k + d and k + 2d Hence the sum of the three terms, which is 24, is given by k + k + d + k + 2d = 24 thus 3k + 3d = 24, so k + d = 8 or d = 8 - k The product of the three terms is 440 so k(k + d)(k + 2d) = 440 Substitute d = 8 - k and solve for k. Use the same technique for the second problem but using the fact that the sequence is geometric not arithmetic. Penny
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