Answer to Question #4554 in Calculus for ong

Question #4554
Amy had \$214 more than her brother.After their father gave Amy \$85 and her brother \$66,Amy had twice as much money as her brother.How much did Amy have at first?
Let&#039;s sign Amys money by A and her brothers money by B. Hence,

A = B + 214 - at first
A + 85 = 2(B + 66) - after their father gave Amy \$85 and her brother \$66

Let&#039;s solve this system of equations. We&#039;ll substitute A from them first equation into the second:

B + 214 + 85 = 2(B + 66)
B + 299 = 2B + 132
So, B = 167.
From the first equation we&#039;ll receive: A = 167 + 214 = 381.
So, Amy had \$381 at first.

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