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# Note for Switching Theory and Logic Design - STLD By JNTU Heroes

• Switching Theory and Logic Design - STLD
• Note
• Jawaharlal Nehru Technological University Anantapur (JNTU) College of Engineering (CEP), Pulivendula, Pulivendula, Andhra Pradesh, India - JNTUACEP
• 8 Topics
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#### Note for Switching Theory and Logic Design - STLD By JNTU Heroes

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LECTURE NOTES ON SWITCHING THEORY AND LOGIC DESIGN II B. Tech I semester (JNTUH-R15) ELECTRONICS AND COMMUNICATION ENGINEERING

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Switching Theory And Logic Design UNIT-I Number System and Boolean Algebra and Switching functions The Decimal Number system: The Decimal number system contains ten unique symbols. 0,1,2,3,4,5,6,7,8,9. Since Counting in decimal involves ten symbols its base or radix is ten. There is no symbol for its base. i.e, for ten .It is a positional weighted system i.e,the value attached to a symbol depends on its location w.r.t. the decimal point.In this system, any no.(integer, fraction or mixed) of any magnitude can be rep. by the use of these ten symbols only. Each symbol in the no. is called a Digit. The leftmost digit in any no.rep ,which has the greatest positional weight out of all the digits present in that no. is called the MSD (Most Significant Digit) and the right most digit which has the least positional weight out of all the digits present in that no. is called the LSD(Least Significant Digit).The digits on the left side of the decimal pt. form the integer part of a decimal no. & those on the right side form the fractional part.The digits to the right of the decimal pt have weights which are negative powers of 10 and the digits to the left of the decimal pt have weights are positive powers of 10. The value of a decimal no.is the sum of the products of the digit of that no. with their respective column weights. The weights of each column is 10 times greater than the weight of unity or 1010.The first digit to the right of the decimal pt. has a weight of 1/10 or 10-1.for the second 1/100 & for third 1/1000.In general the value of any mixed decimal no. is dn dn-1 dn-2 ………d1 d0.d-1 d-2 d-3 …….d-k is given by (dn x10n)+(dn-1 x10 n-1)+ ………(d1 x101)+(d0 x101)+(d-1 x102)(d-2 x103) ……. 9’s & 10’s Complements: It is the Subtraction of decimal no.s can be accomplished by the 9‘s & 10‘s compliment methods similar to the 1‘s & 2‘s compliment methods of binary . the 9‘s compliment of a decimal no. is obtained by subtracting each digit of that decimal no. from 9. The 10‘s compliment of a decimal no is obtained by adding a 1 to its 9‘s compliment. Example: 9‘s compliment of 3465 and 782.54 is 9999 -3465 ---------6534 999.99 -782.54 ----------217.45 ------------------ --------------------
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