# How do you solve (3x )/ (x+1) = 12 / (x-1)?

the answer is $x = \frac{5 + \sqrt{41}}{2} , \frac{5 - \sqrt{41}}{2}$
first you have to cross multiply and you get: $12 x + 12 = 3 {x}^{2} - 3 x$ and now move all the terms to one side to make it equal to zero. $3 {x}^{2} - 15 x - 12 = 0$ and you can take out $3$ from all numbers so: $3 \left({x}^{2} - 5 x - 4\right) = 0$ since you can't factor the parenthesis equation, you have to use the quadratic formula which is: $\frac{- b \sqrt{{b}^{2} - 4 a c}}{2 a}$ and put in the respectful numbers in:$- \left(- 15\right) \frac{\sqrt{4 \left(3\right) \left(- 12\right)}}{2 \left(3\right)}$ and now solve to get your answer
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