# NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles (EX 5.1) Exercise 5.1

Class 7 is undeniably one of the most significant years in a student’s education. Students’ academic careers are shaped by the lessons they learn in Class 7. Throughout a person’s life, the knowledge acquired in Class 7 is applied in a variety of ways. Each topic covered in Class 7 can significantly contribute to students’ progress. The exams taken in Class 7 are very crucial. Students must put in a lot of work to succeed in the Class 7 exams. Students might benefit from performing well on the Class 7 exams throughout their careers. Students’ confidence increases by doing well in the exams, and they will not be afraid of future exams. As a result, they will be able to do better in future tests. In Class 7, there are several subjects that students must learn. Therefore, Class 7 serves as a year where students take crucial steps for their future academic careers. Mathematics is a very important subject for Class 7 students to learn. While studying Mathematics, students frequently struggle to find useful resources to help in their studies. Extramarks provides a comprehensive response to the necessities of students’ studies. Even though NCERT textbooks are fantastic study resources, students still struggle to get reliable NCERT solutions. Extramarks provides accurate and comprehensive NCERT solutions such as the NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1. Additionally, it offers a complete learning solution that brings together the advantages of real-time instruction and the benefits of a Learning App to give students a smooth learning experience.

For Class 7 students to advance in their preparation for the yearly examinations in Mathematics, the NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1 act as a very useful resource. The CBSE suggests the NCERT Mathematics textbook for Class 7 students. The NCERT textbook is also suggested by a number of other state boards as well. Therefore, the NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1 provided by Extramarks will be helpful to students from various boards as well as those from the CBSE. The problems in the exercises of the NCERT books have answers provided at the end. However, only providing answers is insufficient since  students also need to grasp the methods required to arrive at the answer. If the methods and steps are clear, students can learn how to respond to any question that is posed to them. The NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1 by Extramarks is an example of the type of study resource that enables students to comprehend and learn about the answers and methods from the base.

Lines and Angles are covered in Chapter 5 of the NCERT textbook for Class 7. Class 7 Maths Exercise 5.1 is based on some of the basic concepts of Lines and Angles. It covers various important concepts like Complementary and Supplementary Angles, Adjacent Angles, Linear Pair, etc. Along with other study materials offered by Extramarks, the NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1 cover all of the key ideas given in the CBSE syllabus for the Class 7 exams. Expert teachers created the NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1 to help students be ready for questions found in CBSE Class 7 exams. Students can prepare for a variety of competitive exams like, the Olympiads, by practising the NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1. To become proficient with the problems, students should practise the NCERT Solutions for Class 7 Maths Chapter 5 Exercise 5.1 several times.In order to finish the exam question paper within the allotted time, students should practise the NCERT textbook exercises regularly. Their inability to finish the question paper within the allotted time is frequently caused by a lack of practise. The exam paper also has a number of NCERT book-related questions. Students who have access to the NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1 learn how to formulate their answers so that they can finish the question paper within the time limit

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## NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles (EX 5.1) Exercise 5.1

Extramarks provides the NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1 in PDF format. Class 7 students can easily download them from the Extramarks website and mobile application. This will give them offline access to the solutions for easy use in the future.

## Access NCERT Solutions for class 7 Maths Chapter 5 – Lines And Angles

For Class 7 students preparing for the annual exams, Extramarks provides access to a variety of study materials. Each of the study tools available on the Extramarks app and website has been compiled by academic professionals from a variety of fields. Due to the contributions of several academicians, the study materials and learning modules are interesting and easy to grasp. Students can also access the NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1 through the Extramarks portal. The Class 7 Maths Chapter 5 Exercise 5.1 Solutions can be downloaded from the Extramarks website and mobile application in a downloadable PDF format.

### NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Exercise 5.1

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Class 7 students must use the books produced by the National Council of Educational Research and Training (NCERT) in accordance with CBSE norms. The Mathematics textbooks for Class 7 are published by the NCERT. There are various exercises in each chapter of the NCERT Mathematics textbook. Students are typically instructed to read the NCERT book line by line. Students should try to answer the questions given in the book after finishing each chapter, including those in the examples and exercises. Students must have the correct answers to evaluate after answering the questions. The NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1 are therefore available on Extramarks. The NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1 have been provided by Extramarks in a stepwise format to help students fully comprehend the problems, even if they are dealing with them for the first time. Alternative solutions to some questions that are easier to understand are also included in Extramarks’ NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1.

### NCERT Solutions for Class 7

NCERT solutions are generally available on the internet. Students can find NCERT solutions from teachers with experience and qualifications on a variety of websites. However, students need to be sure that these sources are reliable. One such website is the Extramarks website. Extramarks provides NCERT solutions for Class 7 students in all subjects. Hence, it acts as a one-stop solution for students’ needs in all subjects.

Q.1

$\mathrm{Find}\mathrm{the}\mathrm{complement}\mathrm{of}\mathrm{the}\mathrm{following}\mathrm{angles}:$ Ans.

$\begin{array}{l}\text{(i) 20}°\\ \text{Since the sum of complementary angle is 90}°\\ \text{So, we have}\\ \text{Complement}=\text{90}°-20°=\overline{)70°}\\ \text{(ii) 63}°\\ \text{Since the sum of complementary angle is 90}°\\ \text{So, we have}\\ \text{Complement}=\text{90}°-63°=\overline{)27°}\\ \text{(iii) 57}°\\ \text{Since the sum of complementary angle is 90}°\\ \text{So, we have}\\ \text{Complement}=\text{90}°-57°=\overline{)33°}\end{array}$

Q.2 Find the supplement of the following angles: Ans.

$\begin{array}{l}\text{(i) 105}°\\ \text{Since the sum of supplementary angle is 180}°\\ \text{So, we have}\\ \text{Complement}=\text{180}°-105°=\overline{)75°}\\ \text{(ii) 87}°\\ \text{Since the sum of Supplementary angle is 180}°\\ \text{So, we have}\\ \text{Complement}=\text{180}°-87°=\overline{)93°}\text{(iii) 154}°\\ \text{Since the sum of Supplementary angle is 180}°\\ \text{So, we have}\\ \text{Complement}=\text{180}°-154°=\overline{)26°}\end{array}$

Q.3

$\begin{array}{l}\mathrm{Identify}\mathrm{which}\mathrm{of}\mathrm{the}\mathrm{following}\mathrm{pairs}\mathrm{of}\mathrm{angles}\mathrm{aren}\\ \mathrm{complementary}\mathrm{and}\mathrm{which}\mathrm{are}\mathrm{supplementary}.\\ \left(\mathrm{i}\right)65°,115°\left(\mathrm{ii}\right)63°,27°\left(\mathrm{iii}\right)112°,68°\\ \left(\mathrm{iv}\right)130°,50°\left(\mathrm{v}\right)45°,45°\left(\mathrm{vi}\right)80°,10°\end{array}$

Ans.

$\begin{array}{l}\left(\text{i}\right)\text{65}°,\text{115}°\\ \text{Since, the sum of complementary angle is 90}°\text{and sum of}\\ \text{supplementary angle is 180}°.\\ \text{So,}65°\text{+115}°=180°\\ \text{Therefore, given pair is supplemenatry}\text{.}\\ \left(\text{ii}\right)\text{63}°,\text{27}°\\ \text{Since, the sum of complementary angle is 90}°\text{and sum of}\\ \text{supplementary angle is 180}°.\\ \text{So,}63°\text{+27}°=90°\\ \text{Therefore, given pair is complementary}\text{.}\\ \left(\text{iii}\right)\text{112}°,\text{68}°\\ \text{Since, the sum of complementary angle is 90}°\text{and sum of}\\ \text{supplementary angle is 180}°.\\ \text{So,}112°\text{+68}°=180°\\ \text{Therefore, given pair is supplemenatry}\text{.}\\ \left(\text{iv}\right)\text{130}°,\text{50}°\\ \text{Since, the sum of complementary angle is 90}°\text{and sum of}\\ \text{supplementary angle is 180}°.\\ \text{So,}130°\text{+50}°=180°\\ \text{Therefore, given pair is supplemenatry}\text{.}\\ \left(\text{v}\right)\text{45}°,\text{45}°\\ \text{Since, the sum of complementary angle is 90}°\text{and sum of}\\ \text{supplementary angle is 180}°.\\ \text{So,}45°\text{+45}°=90°\\ \text{Therefore, given pair is complementary}\text{.}\\ \left(\text{vi}\right)\text{80}°,\text{10}°\\ \text{Since, the sum of complementary angle is 90}°\text{and sum of}\\ \text{supplementary angle is 180}°.\\ \text{So,}80°\text{+10}°=90°\\ \text{Therefore, given pair is complementary}\text{.}\end{array}$

Q.4

$\mathrm{Find}\mathrm{the}\mathrm{angle}\mathrm{which}\mathrm{is}\mathrm{equal}\mathrm{to}\mathrm{its}\mathrm{complement}.$

Ans.

$\begin{array}{l}\text{Let the angle be}\mathrm{x}.\\ \text{Since, it also equal to its complement.}\\ \text{So, complement angle}=\text{}\mathrm{x}.\\ \text{Sum of complementary angle is 90}°\\ \text{So, we get}\\ \mathrm{x}+\mathrm{x}=90°\\ 2\mathrm{x}=90°\\ \mathrm{x}=\frac{90°}{2}=45°\\ \text{Thus, the angle be}\overline{)\text{45}°}.\end{array}$

Q.5

$\mathrm{Find}\mathrm{the}\mathrm{angle}\mathrm{which}\mathrm{is}\mathrm{equal}\mathrm{to}\mathrm{its}\mathrm{supplement}.$

Ans.

$\begin{array}{l}\text{Let the angle be}\mathrm{x}\text{.}\\ \text{Since, it also equal to its supplement.}\\ \text{So, supplement angle}=\text{}\mathrm{x}\text{.}\\ \text{Sum of supplementary angle is 180}°\\ \text{So, we get}\\ \mathrm{x}+\mathrm{x}=180°\\ 2\mathrm{x}=180°\\ \mathrm{x}=\frac{180°}{2}=90°\\ \text{Thus, the angle be}\overline{)\text{90}°}.\end{array}$

Q.6

$\begin{array}{l}\mathrm{In}\mathrm{the}\mathrm{given}\mathrm{figure},\angle 1\mathrm{and}\angle 2\mathrm{are}\mathrm{supplementary}\mathrm{angles}.\\ \mathrm{If}\angle 1\mathrm{is}\mathrm{decreased},\mathrm{what}\mathrm{changes}\mathrm{should}\mathrm{take}\mathrm{place}\mathrm{in}\angle 2\mathrm{so}\\ \mathrm{that}\mathrm{both}\mathrm{angles}\mathrm{still}\mathrm{remain}\mathrm{supplementary}.\end{array}$ Ans.

$\begin{array}{l}\text{Since,}\text{\hspace{0.17em}}\angle 1\text{and}\angle 2\text{\hspace{0.17em}}\text{are supplementary angles}\text{.}\\ \text{If}\angle 1\text{\hspace{0.17em}}\text{reduced, then}\angle 2\text{should be increased by the same}\\ \text{measure so that this angle remain supplementary}\text{.}\end{array}$

Q.7

$\begin{array}{l}\mathrm{Can}\mathrm{two}\mathrm{angles}\mathrm{be}\mathrm{supplementary}\mathrm{if}\mathrm{both}\mathrm{of}\mathrm{them}\mathrm{are}\\ \left(\mathrm{i}\right)\mathrm{acute}?\\ \left(\mathrm{ii}\right)\mathrm{obtuse}?\\ \left(\mathrm{iii}\right)\mathrm{right}?\end{array}$

Ans.

$\begin{array}{l}\text{(i) No, if both angles are acute, that means that both angles}\\ \text{are less than 90}°\text{. In that case, their sum can not be equal to 180}°.\\ \\ \text{(ii) No, if both angles are obtuse, that means that both angles}\\ \text{greater than 90}°.\text{In that case, their sum will exceed 180}°.\\ \\ \text{(iii) Yes, if both angles are right angles, that is, 90}°,\text{\hspace{0.17em}}\text{then their}\\ \text{sum will be exact 180}°.\end{array}$

Q.8 An angle is greater than 45°. Is its complementary angle greater than 45° or equal to 45° or less than 45°?

Ans.

$\begin{array}{l}\text{Let}\mathrm{x}\text{and}\mathrm{y}\text{be two angles having complementary angle pair}\\ \text{and}\mathrm{x}\text{is greater than 45}°.\\ \text{Then,}\\ \mathrm{x}+\mathrm{y}=90°\\ \mathrm{y}=90°-\mathrm{x}\\ \text{Thus, y will be less than 45}°.\end{array}$

Q.9

$\begin{array}{l}\mathrm{In}\mathrm{the}\mathrm{adjoining}\mathrm{figure}:\\ \left(\mathrm{i}\right)\mathrm{Is}\angle 1\mathrm{adjacent}\mathrm{to}\angle 2?\\ \left(\mathrm{ii}\right)\mathrm{Is}\angle \mathrm{AOC}\text{\hspace{0.17em}}\mathrm{adjacent}\mathrm{to}\angle \mathrm{AOE}?\\ \left(\mathrm{iii}\right)\mathrm{Do}\angle \mathrm{COE}\text{\hspace{0.17em}}\mathrm{and}\text{\hspace{0.17em}}\angle \mathrm{EOD}\text{\hspace{0.17em}}\mathrm{form}\mathrm{a}\mathrm{linear}\mathrm{pair}?\\ \left(\mathrm{iv}\right)\mathrm{Are}\angle \mathrm{BOD}\mathrm{and}\text{\hspace{0.17em}}\angle \mathrm{DOA}\text{\hspace{0.17em}}\mathrm{supplementary}?\\ \left(\mathrm{v}\right)\mathrm{Is}\angle 1\mathrm{vertically}\mathrm{opposite}\mathrm{to}\angle 4?\\ \left(\mathrm{v}\right)\mathrm{What}\mathrm{is}\mathrm{the}\mathrm{vertically}\mathrm{opposite}\mathrm{angle}\mathrm{of}\angle 5?\end{array}$ Ans.

$\begin{array}{l}\text{(i) Yes, since they have a common vetex O and also a common}\\ \text{arm OC}\text{. Also, their non-common arms, OA}\text{​}\text{and OB are on}\\ \text{either side of the common arm}\text{.}\\ \text{(ii) No}\text{. they have a common vertex O and also a common}\\ \text{arm OA}\text{. However, their non common arms, OC and OE are on}\\ \text{the same side of the common arm}\text{. Therefore, theses are not}\\ \text{adjacent to each other}\text{.}\\ \text{(iii) Yes, since they have a common vertex O and a common}\\ \text{arm OE}\text{. Also, their non common arms OC and OD, are}\\ \text{opposite rays}\text{.}\\ \text{(iv) Yes, since}\angle \text{BOD and}\angle \text{DOA have a common vertex O and}\\ \text{their non-common arms opposite to each other}\text{.}\\ \text{(v) Yes, since these are fromed dure to the intersection of two}\\ \text{straight lines (AB and CD)}\\ \text{(vi)}\angle \text{COB is the vertically opposite angle of}\angle 5\text{as these are}\\ \text{formed due to the intersection of two straight lines AB and CD}\text{.}\end{array}$

Q.10

$\begin{array}{l}\mathrm{Indicate}\mathrm{which}\mathrm{pairs}\mathrm{of}\mathrm{angles}\mathrm{are}:\\ \left(\mathrm{i}\right)\mathrm{Vertically}\mathrm{opposite}\mathrm{angles}.\\ \left(\mathrm{ii}\right)\mathrm{Linear}\mathrm{pairs}.\end{array}$ Ans.

$\begin{array}{l}\text{(i)}\angle 1\text{,}\angle 4\text{\hspace{0.17em}}\text{and}\angle 5,\text{}\left(\angle 2+\angle 3\right)\text{are vertically opposite angles}\\ \text{as these formed due to the intersection of straight lines}\\ \text{(ii)}\angle 1\text{and}\angle \text{5,}\angle 5\text{\hspace{0.17em}}\text{and,}\angle 4\text{as these have common vertex}\\ \text{and also have non-common arms opposite to each other}\text{.}\end{array}$

Q.11 In the following figure, is

$\angle 1$

$\angle 2$

? Give reasons. Ans.

$\angle 1$

and

$\angle 2$

are not adjacent angles because they don’t have common vertex.

Q.12

Find the values of the angles x, y and z in each of the following: Ans.

$\begin{array}{l}\text{(i) Since}\angle \mathrm{x}\text{\hspace{0.17em}and}\angle 55°\text{are vertically opposite angles.}\\ \text{So,}\mathrm{x}=\angle 55°\\ \angle \mathrm{x}°+\angle \mathrm{y}°=\angle 180°\\ \angle 55°+\angle \mathrm{y}°=\angle 180°\\ \angle \mathrm{y}°=\angle 180°-\angle 55°\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\angle 125°\\ \angle \mathrm{y}°=\angle \mathrm{z}°\left(\text{vertically\hspace{0.17em}opposite\hspace{0.17em}angles}\right)\\ \mathrm{So},\text{\hspace{0.17em}}\angle \mathrm{z}°=\angle 125°\\ \text{(ii)}\angle \mathrm{z}°=\angle 40°\left(\text{vertically\hspace{0.17em}opposite\hspace{0.17em}angles}\right)\\ \angle \mathrm{y}°+\angle \mathrm{z}°=\angle 180°\left(\text{Linear pair}\right)\\ \angle \mathrm{y}°=\angle 180°-\angle 40°\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\angle 140°\\ \angle 40°+\angle \mathrm{x}°+\angle 25°=\angle 180°\\ \angle \mathrm{x}°+\angle 65°=\angle 180°\\ \angle \mathrm{x}°=\angle 180°-\angle 65°\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\angle 115°\end{array}$

Q.13

$\begin{array}{l}\mathrm{Fill}\mathrm{in}\mathrm{the}\mathrm{blanks}:\\ \left(\mathrm{i}\right)\mathrm{If}\mathrm{two}\mathrm{angles}\mathrm{are}\mathrm{complementary},\mathrm{then}\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{their}\\ \mathrm{measures is}______.\\ \left(\mathrm{ii}\right)\mathrm{If}\mathrm{two}\mathrm{angles}\mathrm{are}\mathrm{supplementary},\mathrm{then}\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{their}\\ \mathrm{measures is}_____.\\ \left(\mathrm{iii}\right)\mathrm{Two}\mathrm{angles}\mathrm{forming}\mathrm{a}\mathrm{linear}\mathrm{pair}\mathrm{are}_______________.\\ \left(\mathrm{iv}\right)\mathrm{If}\mathrm{two}\mathrm{adjacent}\mathrm{angles}\mathrm{are}\mathrm{supplementary},\mathrm{they}\mathrm{form}\mathrm{a}__________.\\ \left(\mathrm{v}\right)\mathrm{If}\mathrm{two}\mathrm{lines}\mathrm{intersect}\mathrm{at}\mathrm{a}\mathrm{point},\mathrm{then}\mathrm{the}\mathrm{vertically}\mathrm{opposite}\\ \begin{array}{l}\mathrm{angles}\mathrm{are}\mathrm{always}_____________.\\ \begin{array}{l}\left(\mathrm{vi}\right)\mathrm{If}\mathrm{two}\mathrm{lines}\mathrm{intersect}\mathrm{at}\mathrm{a}\mathrm{point},\mathrm{and}\mathrm{if}\mathrm{one}\mathrm{pair}\mathrm{of}\\ \mathrm{vertically}\mathrm{opposite}\mathrm{angles}\mathrm{are}\mathrm{acute}\mathrm{angles},\mathrm{then}\mathrm{the}\\ \mathrm{other}\mathrm{pair}\mathrm{of}\mathrm{vertically}\mathrm{opposite}\mathrm{angles}\mathrm{are}__________.\end{array}\end{array}\end{array}$

Ans.

$\begin{array}{l}\text{Fill in the blanks}:\\ \left(\text{i}\right)\text{If two angles are complementary},\text{then the sum of their}\\ \text{measures is}\overline{)\text{90}°}.\\ \left(\text{ii}\right)\text{If two angles are supplementary},\text{then the sum of their}\\ \text{measures is}\overline{)180°}.\\ \left(\text{iii}\right)\text{Two angles forming a linear pair are}\overline{)\text{supplementary}}.\\ \left(\text{iv}\right)\text{If two adjacent angles are supplementary},\text{they}\\ \text{form a}\overline{)\text{Linear pair}}.\\ \left(\text{v}\right)\text{If two lines intersect at a point},\text{then the vertically opposite}\\ \text{angles are always}\overline{)\text{equal}}\text{​}.\\ \left(\text{vi}\right)\text{If two lines intersect at a point},\text{and if one pair of vertically}\\ \text{opposite angles are acute angles},\text{then the other pair of}\\ \text{vertically opposite angles are}\overline{)\text{obtuse angles}}.\end{array}$

Q.14

$\begin{array}{l}\mathrm{In}\mathrm{the}\mathrm{adjoining}\mathrm{figure},\mathrm{name}\mathrm{the}\mathrm{following}\mathrm{pairs}\mathrm{of}\mathrm{angle}.\\ \left(\mathrm{i}\right)\mathrm{Obtuse}\mathrm{vertically}\mathrm{opposite}\mathrm{angles}\\ \left(\mathrm{ii}\right)\mathrm{Adjacent}\mathrm{complementary}\mathrm{angles}\\ \left(\mathrm{iii}\right)\mathrm{Equal}\mathrm{supplementary}\mathrm{angles}\\ \left(\mathrm{iv}\right)\mathrm{Unequal}\mathrm{supplementary}\mathrm{angles}\\ \left(\mathrm{v}\right)\mathrm{Adjacent}\mathrm{angles}\mathrm{that}\mathrm{do}\mathrm{not}\mathrm{form}\mathrm{a}\mathrm{linear}\mathrm{pair}.\end{array}$ Ans.

$\begin{array}{l}\text{(i)}\angle \text{AOD},\text{\hspace{0.17em}}\angle \text{BOC}\\ \text{(ii)}\angle \text{EOA},\text{\hspace{0.17em}}\angle \text{AOB}\\ \text{(iii)}\text{\hspace{0.17em}}\angle \text{EOB},\text{\hspace{0.17em}}\angle \text{EOD}\\ \text{(iv)}\text{\hspace{0.17em}}\angle \text{EOA},\text{\hspace{0.17em}}\angle \text{EOC}\\ \text{(v)}\text{\hspace{0.17em}}\angle \text{AOB}\text{\hspace{0.17em}}\text{and}\text{\hspace{0.17em}}\angle \text{AOE},\text{\hspace{0.17em}}\angle \text{AOE}\text{\hspace{0.17em} and}\text{\hspace{0.17em}}\angle \text{EOD},\text{\hspace{0.17em}}\angle \text{EOD}\text{\hspace{0.17em}}\text{and}\text{\hspace{0.17em}}\angle \text{COD}\text{.}\end{array}$

## 1. How can students access the NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1?

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## 2. How many questions are there in NCERT Solutions For Class 7 Maths Chapter 5 Exercise 5.1?

The NCERT Class 7 Maths Chapter 5 Exercise 5.1 consist of 14 questions. All 14 questions have been solved in the solutions provided by Extramarks. This makes sure that students will have no issues completing this exercise.

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