# How do you graph y-2x=5?

Mar 4, 2018

See a solution process below:

#### Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$

$y - \left(2 \cdot 0\right) = 5$

$y - 0 = 5$

$y = 5$ or $\left(0 , 5\right)$

Second Point: For $x = 1$

$y - \left(2 \cdot 1\right) = 5$

$y - 2 = 5$

$y - 2 + \textcolor{red}{2} = 5 + \textcolor{red}{2}$

$y - 0 = 7$

$y = 7$ or $\left(1 , 7\right)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-5)^2-0.08)((x-1)^2+(y-7)^2-0.08)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-2x-5)(x^2+(y-5)^2-0.08)((x-1)^2+(y-7)^2-0.08)=0 [-20, 20, -10, 10]}
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