## Algebra 2 (1st Edition)

a) In this case the events are independent; the first one has probability $\frac{8}{16}$, and the second one has probability $\frac{8}{16}$. Thus the probability is: $\frac{8}{16}\frac{8}{16}=\frac{1}{2}$ b) In this case the events are not independent; the first one has probability $\frac{8}{16}$, and the second one has probability $\frac{7}{15}$. Thus the probability is: $\frac{8}{16}\frac{7}{15}=\frac{7}{30}$
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