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By : Denis S
Date : October 19 2020, 08:10 PM
I wish did fix the issue. Could somebody please point me in the right direction? I have a list of results (df2 below) and I want to use those to find the values from the matrix (df below). , Here is a base R way code :
``````mat <- cbind(match(df2\$V1, df\$Date), match(df2\$V2, names(df)))
df2\$results <- df1[mat]
df2
#         V1    V2 results
#1 24-Sep-18 Team1      18
#2 14-Sep-18 Team2       9
#3 10-Sep-18 Team3      11
#4 21-Sep-18 Team4      11 # your expected seems to be wrong here
#5 20-Sep-18 Team5      11
#6  7-Sep-18 Team6       1
`````` ## Finding mean of groups of values within a matrix

By : saeid TALA
Date : March 29 2020, 07:55 AM
it should still fix some issue I am trying to take the mean of select values in a matrix column, selecting them by their value in a different column. , Give this a try:
code :
``````X=[1950 1; 1950 2; 1950 3; 1951 1; 1951 5; 1952 1];

years = unique(X(:,1));

for ii=1:length(years)
yr_index = find(X == years(ii));
yr_avg(ii) = mean(X(yr_index,2));
end
`````` ## Keeping the dimension of the matrix but finding values greater than 0.1, and putting them in new matrix

By : sandeep sahu
Date : March 29 2020, 07:55 AM
Hope this helps i have a small problem. i have a 3D matrix, and i want to seperate values greater than 0.1 into a new matrix, but keep the dimentions intact.. Because it is 24x45x65. and 24 = hours, 45 = days and 65 = customers. is it possible? i used find() no luck..i used x_weekday(x_weekday > 0.1) i get the values greater than 0.1 but all in 1 column..and it destroys the dimention. , Approach 1:
code :
``````%%// new_x_weekday would be the one you are after, assuming you want to
%%// keep the rest of the data that are not greater than 0.1 to be 0

new_x_weekday = zeros(size(x_weekday))
new_x_weekday(x_weekday>0.1) = x_weekday((x_weekday>0.1))
``````
``````new_x_weekday = x_weekday;
new_x_weekday(new_x_weekday<=0.1)=0
`````` ## Matlab : how to verify if all values of a matrix are part of a list of values

By : Erickol Mhumble
Date : March 29 2020, 07:55 AM
code :
``````~all(ismember(my_input(:),[0 1]))
`````` ## Getting a matrix of values from a Matrix with names and list with values

By : whitejay
Date : March 29 2020, 07:55 AM
this one helps. One way is to unlist L1 and match the names with each element of the matrix
code :
``````apply(m1, 1:2, function(i) unlist(L1)[match(i, names(L1))])

#      [,1] [,2] [,3] [,4]
#[1,]    1   NA   NA   NA
#[2,]    2   NA    3   NA
#[3,]   NA   NA   NA   NA
`````` ## Python - finding extracts the same values in a list and calculate the differences between consecutive values

By : EatYourBeetS VG
Date : March 29 2020, 07:55 AM
this will help I was also working on the same project. I've shared the part of the code you need. I have my .ipynb file of the project on GitHub. You may want to also see my outcome of the function. Cheers!
code :
``````def read_csv(birth_data_file):
raw_data = raw_data.split("\n")
string_list = raw_data[1:]
final_list = []
for data in string_list:
int_fields = []
string_fields = data.split(",")
for string_field in string_fields:
field = int(string_field)
int_fields.append(field)
final_list.append(int_fields)
return(final_list)

def calc_counts(data, column):
births_counts = {}
if not column > 0 and column <= 4:
return("'column' must be either 1, 2, 3, or 4")
else:
for instance in data:
field = instance[column-1]
births  = instance
if field in births_counts.keys():
births_counts[field] += births
else:
births_counts[field] = births
return(births_counts)

# Write a function that extracts the same values across years and calculates the
# differences between consecutive values to show if number of
# births is increasing or decreasing.

def check_birth_growth(birth_data_file):
cdc_year_births = calc_counts(cdc_list, 1)
previous_year_birth = 0
previous_birth_diff = 0
for year, total_births in cdc_year_births.items():
current_year_birth = int(total_births)
if previous_year_birth == 0:
growth_status = "Growth of births in {} not available.".format(year)
print(growth_status)
previous_year_birth = current_year_birth
else:
if current_year_birth > previous_year_birth:
growth_status = "Births increased in {}.".format(year)
print(growth_status)
previous_year_birth = current_year_birth
elif current_year_birth < previous_year_birth:
growth_status = "Births decreased in {}.".format(year)
print(growth_status)
previous_year_birth = current_year_birth
elif current_year_birth == previous_year_birth:
growth_status = "Births in {} was same as previous year.".format(year)
print(growth_status)
previous_year_birth = current_year_birth
``````
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