<s>[INST] Is there a way to perform "if" in python's lambda In python 2.6, I want to do:
f = lambda x: if x==2 print x else raise Exception()
f(2) #should print "2"
f(3) #should throw an exception

This clearly isn't the syntax. Is it possible to perform an if in lambda and if so how to do it?
thanks
 [/INST] The syntax you're looking for:
lambda x: True if x % 2 == 0 else False

But you can't use print or raise in a lambda.
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