Storing a dict in a DataFrame fails
#### Code Sample, a copy-pastable example if possible

Both of the examples below fail with the same error
```
df = pd.DataFrame(index=[0, 1, 2], columns=['a', 'b'])

df.loc[0, 'a'] = dict(x=2)
df.iloc[0, 0] = dict(x=2)

---------------------------------------------------------------------------
ValueError                                Traceback (most recent call last)
<ipython-input-282-62f3ee5ff885> in <module>()
      1 # file_map.loc[file_no, 'Q_step_length'] = dict(a=1)
      2 df = pd.DataFrame(index=[0, 1, 2], columns=['a', 'b'])
----> 3 df.iloc[0, 0] = dict(x=2)
      4 df['a'] = df['a'].apply(lambda x: x[0] if not pd.isnull(x) else x)
      5 df

...\lib\site-packages\pandas\core\indexing.py in __setitem__(self, key, value)
    177             key = com._apply_if_callable(key, self.obj)
    178         indexer = self._get_setitem_indexer(key)
--> 179         self._setitem_with_indexer(indexer, value)
    180 
    181     def _has_valid_type(self, k, axis):

...\lib\site-packages\pandas\core\indexing.py in _setitem_with_indexer(self, indexer, value)
    603 
    604             if isinstance(value, (ABCSeries, dict)):
--> 605                 value = self._align_series(indexer, Series(value))
    606 
    607             elif isinstance(value, ABCDataFrame):

...\lib\site-packages\pandas\core\indexing.py in _align_series(self, indexer, ser, multiindex_indexer)
    743             return ser.reindex(ax)._values
    744 
--> 745         raise ValueError('Incompatible indexer with Series')
    746 
    747     def _align_frame(self, indexer, df):

ValueError: Incompatible indexer with Series
```
---------------------------------------------------------------------------

This works, but is placing a list into the dataframe
```
df[0, 'a'] = [dict(x=2)]
```
It is possible to get the dict directly in the dataframe by using a very inelegant construct like this:
```
df['a'] = df['a'].apply(lambda x: x[0] if not pd.isnull(x) else x)
```
#### Problem description
Since it is possible to store a dict in a dataframe, trying an assignment as above should not fail. I am aware that df.loc[...] = dict(...) will assign values in the dict to the corresponding columns if present (is that documented?) and has its own issues but this behaviour should not apply when accessing a single location of the dataframe

#### Expected Output
A dataframe with a dict inside the specified location.

#### Output of ``pd.show_versions()``

<details>

INSTALLED VERSIONS
------------------
commit: None
python: 3.5.4.final.0
python-bits: 64
OS: Windows
OS-release: 10
machine: AMD64
processor: Intel64 Family 6 Model 58 Stepping 9, GenuineIntel
byteorder: little
LC_ALL: None
LANG: None
LOCALE: None.None

pandas: 0.20.3
pytest: None
pip: 9.0.1
setuptools: 36.5.0
Cython: 0.26
numpy: 1.13.1
scipy: 0.19.1
xarray: None
IPython: 6.1.0
sphinx: None
patsy: 0.4.1
dateutil: 2.6.1
pytz: 2017.2
blosc: None
bottleneck: None
tables: None
numexpr: None
feather: None
matplotlib: 2.0.2
openpyxl: None
xlrd: None
xlwt: None
xlsxwriter: None
lxml: None
bs4: None
html5lib: 0.9999999
sqlalchemy: None
pymysql: None
psycopg2: None
jinja2: 2.9.6
s3fs: None
pandas_gbq: None
pandas_datareader: None

</details>
