Cannot parse query for df.query() with column name containing parenthesis.
##### Code:

```python
 import pandas as pd

 a = {'abc':[1,2,3],'xy (z)':[4,5,6]}

 df = pd.DataFrame(a)
 query = "`xy (z)` == 2"
 new_df = df.query(query)

```
#### Error :

xy_(_z_)_BACKTICK_QUOTED_STRING ==2
SyntaxError: invalid syntax

#### Problem description
df.query is not able to parse the query where column name of df is not valid python identifier.

Workaround: https://stackoverflow.com/questions/40045545/pandas-query-string-where-column-name-contains-special-characters

#### Output of ``pd.show_versions()``

<details>
INSTALLED VERSIONS

commit           : None
python           : 3.6.8.final.0
python-bits      : 64
OS               : Linux
OS-release       : 4.4.187-1.el7.elrepo.x86_64
machine          : x86_64
processor        : x86_64
byteorder        : little
LC_ALL           : None
LANG             : en_US.UTF-8
LOCALE           : en_US.UTF-8

pandas           : 0.25.1
numpy            : 1.17.0
pytz             : 2019.2
dateutil         : 2.8.0
pip              : 18.1
setuptools       : 40.6.2
Cython           : 0.28.2
pytest           : 5.1.2
hypothesis       : None
sphinx           : None
blosc            : None
feather          : None
xlsxwriter       : 1.0.4
lxml.etree       : 4.4.1
html5lib         : 1.0.1
pymysql          : 0.9.3
psycopg2         : 2.8.3 (dt dec pq3 ext lo64)
jinja2           : None
IPython          : None
pandas_datareader: None
bs4              : 4.8.0
bottleneck       : None
fastparquet      : None
gcsfs            : None
lxml.etree       : 4.4.1
matplotlib       : None
numexpr          : None
odfpy            : None
openpyxl         : 2.6.2
pandas_gbq       : None
pyarrow          : None
pytables         : None
s3fs             : None
scipy            : 1.1.0
sqlalchemy       : 1.3.3
tables           : None
xarray           : None
xlrd             : None
xlwt             : None
xlsxwriter       : 1.0.4


</details>
