`DataFrame.iterrows()` breaks timezone on index
Duplicate of #8890. 

As far as I can tell, the Timestamps for the index generated by `iterrows()` are 5 hours behind where they should be in this example:

``` python
In [33]: idx = pd.date_range("2010-01-01 00:00:00-0500", freq='D', periods=3)

In [34]: df = pd.DataFrame([1,2,3], index=[idx])

In [35]: df # this looks correct
Out[35]: 
                           0
2010-01-01 00:00:00-05:00  1
2010-01-02 00:00:00-05:00  2
2010-01-03 00:00:00-05:00  3

In [36]: [index for index, row in df.iterrows()] # but this looks wrong:
Out[36]: 
[Timestamp('2009-12-31 19:00:00-0500', tz='pytz.FixedOffset(-300)', offset='D'),
 Timestamp('2010-01-01 19:00:00-0500', tz='pytz.FixedOffset(-300)', offset='D'),
 Timestamp('2010-01-02 19:00:00-0500', tz='pytz.FixedOffset(-300)', offset='D')]
```

 I would have expected `iterrows()` to produce the same indices as this code:

``` python
In [38]: [df.index[i] for i in range(len(df))]
Out[38]: 
[Timestamp('2010-01-01 00:00:00-0500', tz='pytz.FixedOffset(-300)', offset='D'),
 Timestamp('2010-01-02 00:00:00-0500', tz='pytz.FixedOffset(-300)', offset='D'),
 Timestamp('2010-01-03 00:00:00-0500', tz='pytz.FixedOffset(-300)', offset='D')]
```

The `row.name` is also incorrect:

``` python
In [37]: [row.name for index, row in df.iterrows()]
Out[37]: 
[Timestamp('2009-12-31 19:00:00-0500', tz='pytz.FixedOffset(-300)', offset='D'),
 Timestamp('2010-01-01 19:00:00-0500', tz='pytz.FixedOffset(-300)', offset='D'),
 Timestamp('2010-01-02 19:00:00-0500', tz='pytz.FixedOffset(-300)', offset='D')]
```

But all is fine if we use a geographical timezone instead of a `pytz.FixedOffset`: 

``` python

In [47]: idx = pd.date_range("2010-01-01 00:00:00", freq='D', periods=3, tz="America/New_York")

In [48]: df = pd.DataFrame([1,2,3], index=[idx])

In [49]: [index for index, row in df.iterrows()]
Out[49]: 
[Timestamp('2010-01-01 00:00:00-0456', tz='America/New_York', offset='D'),
 Timestamp('2010-01-02 00:00:00-0456', tz='America/New_York', offset='D'),
 Timestamp('2010-01-03 00:00:00-0456', tz='America/New_York', offset='D')]

In [50]: df
Out[50]: 
                           0
2010-01-01 00:00:00-04:56  1
2010-01-02 00:00:00-04:56  2
2010-01-03 00:00:00-04:56  3
```

Forgive me if I am using Pandas incorrectly!

Versions:

```

In [51]: pd.show_versions()

INSTALLED VERSIONS
------------------
commit: None
python: 2.7.8.final.0
python-bits: 64
OS: Linux
OS-release: 3.16.0-25-generic
machine: x86_64
processor: x86_64
byteorder: little
LC_ALL: None
LANG: en_GB.UTF-8

pandas: 0.15.1
nose: 1.3.4
Cython: 0.21.1
numpy: 1.8.2
scipy: 0.14.0
statsmodels: None
IPython: 2.3.1
sphinx: 1.2.3
patsy: None
dateutil: 2.2
pytz: 2014.10
bottleneck: 0.6.0
tables: 3.1.1
numexpr: 2.4
matplotlib: 1.4.2
openpyxl: 1.8.6
xlrd: 0.9.2
xlwt: 0.7.5
xlsxwriter: None
lxml: 3.3.6
bs4: None
html5lib: 0.999
httplib2: 0.9
apiclient: None
rpy2: 2.3.8
sqlalchemy: None
pymysql: None
psycopg2: None
```

(it goes without saying that I'm a huge fan of Pandas!)
