Non-standard poker hands are hands which are not recognized by official poker rules but are made by house rules. Non-standard hands usually appear in games using wild cards or bugs. Other terms for nonstandard hands are special hands or freak hands. Because the hands are defined by house rules, the composition and ranking of these hands is subject to variation. Any player participating in a game with non-standard hands should be sure to determine the exact rules of the game before play begins. Types The usual hierarchy of poker hands from highest to lowest runs as follows (standard poker hands are in italics): Royal Flush: The highest straight flush, A-K-Q-J-10 suited. Skeet flush: The same cards as a skeet (see below) but all in the same suit. Straight flush: When wild cards are used, a wild card becomes whichever card is necessary to complete the straight flush, or the higher of the two cards that can complete an open-ended straight flush. For example, in the hand 10♠ 9♠ (Wild) 7♠ 6♠, it becomes the 8♠, and in the hand (Wild) Q♦ J♦ 10♦ 9♦, it plays as the K♦ (even though the 8♦ would also make a straight flush). Four of a kind: Between two equal sets of four of a kind (possible in wild card and community card poker games or with multiple or extended decks), the kicker determines the winner. Big bobtail: A four card straight flush (four cards of the same suit in consecutive order). Full house Flush: When wild cards are used, a wild card contained in a flush is considered to be of the highest rank not already present in the hand. For example, in the hand (Wild) 10♥ 8♥ 5♥ 4♥, the wild card plays as the A♥, but in the hand A♣ K♣ (Wild) 9♣ 6♣, it plays as the Q♣. (As noted above, if a wild card would complete a straight flush, it will play as the card that would make the highest possible hand.) A variation is the double-ace flush rule, in which a wild card in a flush always plays as an ace, even if one is already present (unless the wild card would complete a straight flush). In such a game, the hand A♠ (Wild) 9♠ 5♠ 2♠ would defeat A♦ K♦ Q♦ 10♦ 8♦ (the wild card playing as an imaginary second A♠), whereas by the standard rules