of 7, and the 30 is subtracted from the 70, resulting in a value of 40. The final result is 47. The method of addition involves augmenting the subtrahend, rather than reducing the minuend, as in the borrowing method. This transforms the problem into (80 + 16) - (39 + 10). A small 1 is marked below the subtrahend digit as a reminder. The operations are then performed: 9 is subtracted from 16 to get 7, and 40 (30 + 10) is subtracted from 80 to get a result of 40. The final result is still 47. There are two variations of the addition method, which differ in their presentation. In the first variation, we attempt to subtract 9 from 6, and then 9 from 16, borrowing a 10 and marking it near the digit of the subtrahend in the next column. In the second variation, we try to find a digit that, when added to 9, gives us 6. When this is not possible, we give 16 and carry the 10 of the 16 as a 1, marking it near the same digit as in the first method. The markings are the same in both variations, it is simply a matter of preference as to how we explain their appearance. It is important to note that the borrowing method can become more complex in cases such as 100 - 87, where it is necessary to borrow from several columns. In this case, the minuend can be rewritten as 90 + 10 by taking a 100 from the hundreds place, making ten 10s from it, and immediately borrowing a 10 from the tens place and placing it in the ones place. This results in a value of 9 10s in the tens place and a value of 10 in the ones place. Example To find the difference between the numbers 792 and 308, one must start with the ones-column, in which 2 is smaller than 8, so we must borrow 10 from 90, making 90 become 80. We add this 10 to 2, which changes the problem to 12 - 8, which is 4. Next is the tens column. Since we took 10 from 90, it is now 80, which means we must find the difference between 80 and 0, which is just 80. Next is the hundreds-column. The difference between 700 and 300 is 400. The algorithm is completed