As previously explained, the most relevant mechanism involves the subsequent breakage of In-CH3 bonds to form CH3 radicals that react into C2H6, while leaving MI as an intermediate. Then, MI should either i) undergo full dissociation to form atomic indium In at higher temperatures or ii) polymerize into a white film. In this route, it is assumed that there is no radical attack on the TMI precursor, in accordance with previous experimental findings. The analysis is first given from a general perspective and, after that, is detailed for each temperature of interest, i.e.