Generally, in RRDE technique, LSV is done on the disk and the ring is biased at such a potential where the product formed on the disk during the LSV would get reduced/oxidized back to another product thus giving a negative/positive ring current respectively. Thus, until the specific reaction does not start on the disk electrode, the ring current should be zero or very low as there is no product which the ring would reduce/oxidize. In our case, the product formed on the disk during LSV is oxygen due to water oxidation so the ring must show a reduction current only when the disk potential crosses the water oxidation regime (in this case around 1.52 V). But surprisingly, we observed that the ring current (reduction current) is very pronounced (-444 µA/cm 2 ) right in the beginning itself where there is no water oxidation occurring. To emphasize further, even when the applied potential is just 1.0 V and the oxygen evolution reaction has not yet started, significant reduction on the ring is noticed (red curve in Figure ). Similar behaviour is also observed when we performed the experiment in methanol containing electrolyte medium (red curve in Figure ). Some major observations and conclusions from Figure are: (a) reduction in the oxygen reduction onset voltage in presence of methanol (b) ring current (reduction current shown as the red curve) is pronounced before the reaction. Point (a) gives us clear validation of methanol assisted OER as the onset for the reduction current on the ring electrode was observed at -1.50 V vs. RHE in presence of methanol (Figure ) while the same is -1.57 V vs RHE without methanol (Figure ). Point (b) Ring current is very pronounced even in alkaline and methanol contained electrolyte system, which confirms the reduction of the catalyst's lattice oxygen because even without OER, significant reduction current is generated on the ring so it has to be the lattice oxygen from LSCO whose reduction is going on at the ring.