The compound above contains a triple bond, so we form a lone pair hybrid to visualize the conjugated pi system in a way that can be observed through application of the inclusive and non-inclusive steric number approaches (a calculable sp 2 -hybridization lens). The nitrogen atom (atom of interest here) is then analyzed using the inclusive vs. non-inclusive approach. It is sp -hybridized under the inclusive approach (because all groups, even delocalized lone pairs, connected to the atom of interest count towards steric number and hybridization of the atom in the inclusive approach; 3 sigma bonds + 1 lone pair = 4, sp ), thus making the compound nonaromatic. Under the non-inclusive approach, the nitrogen is sp -hybridized (because it has delocalized lone pairs, which do not count towards steric number and hybridization, rather they count towards the number of pi electrons in the compound in the non-inclusive approach; 3 sigma bonds + 0 localized lone pairs = 3, sp 2 ) which makes the compound have 8 pi electrons and adopt an antiaromatic configuration. Since nonaromatic is more stable than antiaromatic, we determine that the compound shown is nonaromatic.