which leads to result. Further, it is clear that ker p B # ∩ Z l k (K) = ker p Z # . (ii). One should pay more atention to these subtle conditions appears in proof for converse theorem. Suppose that H l,p k (K/Γ) = 0, then there is Z l k (K/Γ) ⊂ B l+p k (K/Γ).As these subspaces are always closed, one can prove its reverse theorem by doing the same steps only regarding on kernels and intersection of subsets. As F has a charateristic which is either zero or comprime to |Γ|, then ker p # is clearly free from module of their coefficient. Further, since Γ is disrete, then dim(K) = dim(K/Γ) and dim(σ) = dim(σ/Γ). One should find out it is able to complete rest of proof through contradiction. Thus, p # is proved to be an isomorphism indeed.