Figure , Y via reciprocal T of some asymmetric molecules However, NF3 (A=4.1011, D 2 =0.999) exhibits asymmetry due to the unbonded three occupied F sp 3 hybridized orbitals. As shown in Fig. , near M.P., A=5.7103 corresponds to n≥12. The tetrahedron possibly collapses. Therefore, the symmetry operations should be a molecule C3, with three migrations and the contribution from the rotation of three F sp 3 hybridized orbitals. Since each F atom has a C3, the total operations should be 9, i.e., molecule C3×F atom C3. Subtracting a C3, n=13 for NF3.