prompt: Calen originally had 5 more pencils than does Caleb, and Caleb has 3 less than twice as many pencils as does Candy.  If Calen lost 10 pencils, which left him with 10 pencils, then how many pencils does Candy have?
messages.content: Calen originally had 5 more pencils than does Caleb, and Caleb has 3 less than twice as many pencils as does Candy.  If Calen lost 10 pencils, which left him with 10 pencils, then how many pencils does Candy have?
messages.role: user
messages.content: If Calen lost 10 pencils, which left him with 10 pencils, then Calen originally had 10+10=<<10+10=20>>20 pencils.
  Calen originally had 5 more pencils than does Caleb, and thus Caleb has 20-5=<<20-5=15>>15 pencils.
  Let's let "x" represent the number of pencils owned by Candy.
  Since Caleb has 3 less than twice as many pencils as does Candy, then (2*x)-3=15.
  This simplifies to 2*x=18.
  Thus, the number of pencils owned by Candy is x=<<9=9>>9 pencils.
  #### 9
messages.role: assistant