<prompt> Una n sarafu na unataka kujenga ngazi na sarafu hizi. ngazi lina mistari k ambapo mstari wa th ina hasa i sarafu. mstari wa mwisho wa ngazi inaweza kuwa incomplete. kutokana na integer n, kurudi idadi ya mistari kamili ya ngazi utakuwa kujenga.  <response>: The problem of finding the number of complete rows in a staircase with n coins can be solved by using binary search. The highest possible number of complete rows is the square root of twice the number of coins stored in n. We can therefore start our binary search with a low value of 0, a high value of the square root of 2n, and a middle value of the average of these two values. In each iteration, we check if the sum of the coins in each row up to the middle value is greater than n. If it is, we update our high value to the middle value - 1. Otherwise, we update our low value to the middle value 1. We keep iterating until the low value is greater than the high value, at which point we return the high value as the number of complete rows.The code for this algorithm is as follows:def get_num_complete_rowsn: low 0 high int2 n 0.5 while low high: mid low high 2 coins_in_rows mid mid 1 2 if coins_in_rows n: high mid - 1 else: low mid 1 return highThis algorithm has a time complexity of Ologn, where n is the number of coins stored in n. 