<prompt> Kutokana na kichwa cha orodha kuunganishwa na integer val, kuondoa nodes wote wa orodha kuunganishwa ambayo ina Node.val val, na kurudi kichwa mpya.  <response>: To remove all nodes in the linked list with value equal to val, you can iterate through the linked list and keep track of the previous node, so that you can modify the pointers accordingly. Heres the Python code to accomplish this:class ListNode: def __init__self, val0, nextNone: self.val val self.next nextdef remove_elementshead: ListNode, val: int - ListNode: Handle empty list if head is None: return None Handle nodes at beginning with value equal to val while head is not None and head.val val: head head.next Handle remaining nodes previous head current head.next if head is not None else None while current is not None: if current.val val: previous.next current.next else: previous current current current.next return headHere, we handle the case of an empty list first. Then, we handle the nodes at the beginning of the list with value equal to val using a while loop. After that, we iterate over the remaining nodes using a while loop and update pointers as necessary. Finally, we return the new head of the linked list. 