<prompt> Kutokana na matrix ya m x n vipengele m safu, n nguzo, kurudi vipengele vyote vya matrix katika mpangilio wa spiral. Kwa mfano, kama matrix ya kuingia ni: 1, 2, 3, 4, 5, 6, 7, 8, 9 pato lazima: 1, 2, 3, 6, 9, 8, 7, 4, 5.  <response>: To solve this problem, you can iteratively traverse the matrix in a spiral order. One way to approach this is to keep track of the four boundaries of the matrix and move inwards in each iteration. Heres a Python implementation:def spiralOrdermatrix: if not matrix: return m, n lenmatrix, lenmatrix0 top, left, bottom, right 0, 0, m-1, n-1 output while top bottom and left right: Traverse top row for j in rangeleft, right1: output.appendmatrixtopj top 1 Traverse right column for i in rangetop, bottom1: output.appendmatrixiright right - 1 Traverse bottom row if top bottom: for j in rangeright, left-1, -1: output.appendmatrixbottomj bottom - 1 Traverse left column if left right: for i in rangebottom, top-1, -1: output.appendmatrixileft left 1 return outputFor your example input, the output of spiralOrder1, 2, 3, 4, 5, 6, 7, 8, 9 would be 1, 2, 3, 6, 9, 8, 7, 4, 5. 