<prompt> Kupata theta kati ya vectors mbili 6i 2j na -3i 6j  <response>: Sure! To find the angle between two vectors, we can use the formula θ arccosuv u v . Where arccos is the inverse cosine, uv represents the dot product between vectors u and v, and u is the magnitude of the vector u. Lets say vector u 6,2 and vector v-3,6, The dot product between u and v uv 6-3 26 -12.The magnitude of u is u sqrt62 22 sqrt364 sqrt402sqrt10.The magnitude of v is v sqrt-32 62 sqrt936 3sqrt5.Substituting these values into the formula, we get θ arccosuv u v arccos -122sqrt103sqrt5 arccos-1arccos-1 is equal to π radians, or 180 degrees.Therefore, the angle between the two vectors is 180 degrees. 