<prompt> Kutokana na kamba mbili s na t, kupata dirisha chini katika s ambayo itakuwa na herufi zote katika t katika utata O n. Andika programu C kutatua tatizo hili.  <response>: Here is the C program to solve the problem:include include include using namespace std;string minWindowstring s, string t unordered_map tFreq, windowFreq; int required t.size; int left 0, right 0; int minLeft 0, minLength s.size 1; for char ch : t tFreqch; while right s.size Expand the window to the right windowFreqsright; if tFreq.countsright windowFreqsright tFreqsright required--; Shrink the window from the left while required 0 left right if right - left 1 minLength minLength right - left 1; minLeft left; windowFreqsleft--; if tFreq.countsleft windowFreqsleft tFreqsleft required; left; right; if minLength s.size return ; else return s.substrminLeft, minLength; int main string s ADOBECODEBANC; string t ABC; cout minWindows, t endl; return 0;The minWindow function takes two strings s and t as input and returns the minimum window in s that contains all the characters in t. The function first creates two frequency maps: tFreq to store the frequency of characters in the target string t and windowFreq to store the frequency of characters in the current window. The function then uses two pointers left and right to create a sliding window on string s. The required variable stores how many characters from t are still needed in the window. The function first expands the window to the right and updates the frequency counts in the windowFreq map. If the added character is in t, its frequency count is compared against the frequency count in the tFreq map, and if they match, required is decremented. The function then shrinks the window from the left until required becomes zero. The minLength variable stores the minimum length seen so far, and minLeft stores the starting index of the minimum window. If the current window is shorter than minLength, update minLength and minLeft. Finally, the function returns an empty string if no valid window was found, otherwise it returns the substring of length minLength starting at index minLeft. In this example, minWindowADOBECODEBANC, ABC returns BANC. 