<prompt> 5, 3, 6, 1, 8Kutokana na safu ya integer, rearrange safu hiyo ili hata nafasi vipengele ni kubwa kuliko wao kabla na kufuatia vipengele.  <response>: One possible solution algorithm to rearrange the array such that even position elements are greater than their preceding and succeeding elements would be to first sort the array in non-descending order, that is 1, 3, 5, 6, 8. Then, starting at the second element in the array which is index 1, swap adjacent elements iteratively.pythondef rearrange_arrayarr: arr.sort for i in range1, lenarr-1, 2: arri, arri1 arri1, arri return arrFor the above input, the series of swaps would be: 1,3,5,6,8 1,5,3,6,8 1,5,6,3,8. Then the final rearranged array is: 1, 5, 3, 6, 8.Here, all even position elements - 5 index 1 and 6 index 3 are greater than their preceding and succeeding elements. Note that the array, defined as being of zero-indexed, and hence, the first element is at an odd position; only elements with even index positions - thats, positions 2, 4, 6, so on - follow this condition. 