<prompt> Please answer with one of the option in the bracket. Write reasoning in between . Write answer in between .Q:A 22-year-old male college student volunteers for a research study involving renal function. He undergoes several laboratory tests, the results of which are below: UrineSerumGlucose0 mgdL93 mgdLInulin100 mgdL1.0 mgdLPara-aminohippurate PAH150 mgdL0.2 mgdLHematocrit50 Urine flow rate1 mLmin What is the estimated renal blood flow?? A: 200 mLmin, B: 1,000 mLmin, C: 1,500 mLmin, D: 750 mlmin, E: 3,000 mLmin,  <response>: This is a question about estimating renal blood flow using clearance values. The key information given is the clearance values for inulin and PAH in urine and serum. Inulin is freely filtered at the glomerulus, so its clearance approximates the glomerular filtration rate GFR. PAH is both filtered at the glomerulus and secreted by the renal tubules, so its clearance approximates renal plasma flow RPF. The hematocrit is needed to convert RPF to renal blood flow RBF.The GFR is calculated as the urine inulin concentration divided by the serum inulin concentration, which is 1001.0 100 mLmin. The RPF is calculated as the urine PAH concentration divided by the serum PAH concentration, which is 1500.2 750 mLmin.To convert RPF to RBF, the RPF is divided by 1 - hematocrit. With a hematocrit of 50, the calculation is:RBF RPF 1 - hematocrit 750 mLmin 1 - 0.50 750 0.50 1,500 mLminC: 1,500 mLmin 