<prompt> Please answer with one of the option in the bracket. Write reasoning in between . Write answer in between .Q:A newlywed couple comes to your office for genetic counseling. Both potential parents are known to be carriers of the same Cystic Fibrosis CF mutation. What is the probability that at least one of their next three children will have CF if they are all single births?? A: 0, B: 164, C: 2764, D: 3764, E: 1,  <response>: This is a question about calculating the probability of a child having cystic fibrosis CF given that both parents are known carriers of the same CF mutation. Since both parents are carriers, each of their children has a 1 in 4 25 chance of having CF. The question asks for the probability that at least one of their next three children will have CF. To calculate this, we look at the probability that each child does not have CF, which is 34. Then the probability that all three children do not have CF is 34 34 34 2764. Therefore, the probability that at least one child has CF is 1 - 2764 3764.D: 3764 