<prompt> Please answer with one of the option in the bracket. Write reasoning in between . Write answer in between .Q:An investigator is studying biomolecular mechanisms in human cells. A radioactive isotope that is unable to cross into organelles is introduced into a sample of cells. The cells are then fragmented via centrifugation and the isotope-containing components are isolated. Which of the following reactions is most likely to be present in this cell component?? A: Glucose-6-phosphate to glucose, B: Fatty acyl-CoA to acetyl-CoA, C: Carbamoyl phosphate to citrulline, D: Glucose-6-phosphate to 6-phosphogluconolactone, E: Isocitrate to α-ketoglutarate,  <response>: This is a question about cellular biology and metabolism. The key information is that a radioactive isotope was introduced into cells but could not cross organelle membranes. After centrifugation, the isotope was found in a specific cell component. The question asks which metabolic reaction is most likely occurring in that cell component. Based on the information provided, the isotope must be in the cytoplasm, since it could not enter organelles. Choices A, B, and E involve reactions that occur inside organelles like mitochondria, endoplasmic reticulum, or peroxisomes. Choice C occurs in the cytoplasm but is specific to the urea cycle in the liver. Choice D, the conversion of glucose-6-phosphate to 6-phosphogluconolactone, is the first step of glycolysis which takes place in the cytoplasm. This is the most likely answer based on the experimental details provided.D: Glucose-6-phosphate to 6-phosphogluconolactone 