<prompt> Kutokana na idadi mbili kamili, n na k, kupata mchanganyiko wote iwezekanavyo wa idadi k kwamba kuongeza hadi n, kutokana na kwamba tu idadi kutoka 1 hadi 9 inaweza kutumika na kila mchanganyiko lazima kuwa ya kipekee. Kuandika programu C kutatua tatizo hapo juu.  <response>: Heres the C program to solve the above problem:include include using namespace std;void findCombinationsint n, int k, vector current, vector result if k 0 if n 0 result.push_backcurrent; return; for int i 1; i 9; i if n - i 0 current.push_backi; findCombinationsn - i, k - 1, current, result; current.pop_back; int main int n, k; cout Enter the value of n: ; cin n; cout Enter the value of k: ; cin k; vector result; vector current; findCombinationsn, k, current, result; for auto combination : result for int i 0; i combination.size; i cout combinationi; if i ! combination.size - 1 cout ; cout endl; return 0;In this program, we use a recursive function findCombinations that takes in the values of n, k, the current combination being generated current, and the final result result, and finds all possible combinations of k numbers that add up to n. We iterate through all possible values of numbers that we can use 1 to 9 and add them to our current combination only if their value is less than or equal to the remaining value n - i. Once k elements have been added to the current combination, we check if their sum equals n. If it does, we add this combination to the final result. If it doesnt, we backtrack and try other possible combinations.In the main function, we take in the values of n and k from the user and call the findCombinations function to get all possible combinations. We then iterate through the final result and print out all combinations to the console. 