<prompt> Kutokana na input string s na muundo p, kutekeleza kawaida kujieleza mechi na msaada kwa ajili ya . na . Kuandika programu Java na si kutumia kujenga katika kazi kwa regex.  <response>: To implement regular expression matching with support for . and , we need to use dynamic programming. Heres an approach in Java:public boolean isMatchString s, String p boolean dp new booleans.length1p.length1; dp00 true; for int j1; jp.length; j if p.charAtj-1 dp0j dp0j-2; for int i1; is.length; i for int j1; jp.length; j if p.charAtj-1. p.charAtj-1s.charAti-1 dpij dpi-1j-1; else if p.charAtj-1 dpij dpij-2; if p.charAtj-2. p.charAtj-2s.charAti-1 dpij dpi-1j; return dps.lengthp.length; 