<prompt> Next kubwa kipengele cha baadhi ya kipengele x katika safu ni kwanza kubwa kipengele kwamba ni upande wa kulia wa x katika safu hiyo. Una kupewa tofauti mbili 0-indexed integer safu nums1 na nums2, ambapo nums1 ni sehemu ya nums2. Kwa kila 0 i nums1.length, kupata index j kama kwamba nums1i nums2j na kuamua next kubwa kipengele cha nums2j katika nums2. Kama hakuna next kubwa kipengele, basi jibu kwa ajili ya swali hili ni -1. Kurudi safu ya urefu ans nums1.length hivyo kwamba ansi ni ya pili kubwa kipengele kama ilivyoelezwa hapo juu.  <response>: To solve the problem, we can iterate through nums2 from right to left and use a stack to keep track of the next greater element for each element in nums2. Then, for each element in nums1, we can find its index in nums2 and return the corresponding elements next greater element from the stack. If the element does not have a next greater element, we return -1.Heres the Python code to implement this:def nextGreaterElementnums1, nums2: stack next_greater for num in nums2::-1: while stack and num stack-1: pop elements from stack smaller than num stack.pop if stack: next_greaternum stack-1 else: next_greaternum -1 stack.appendnum ans for num in nums1: ans.appendnext_greaternum return ans 