<prompt> Kuandika kazi Java kutatua hili: Kutokana na kamba mbili s na t, kurudi kweli kama s ni mfululizo wa t, au uongo vinginevyo. mfululizo wa kamba ni kamba mpya ambayo ni sumu kutoka string ya awali kwa kufuta baadhi inaweza kuwa hakuna ya herufi bila kuvuruga nafasi ya jamaa ya wahusika waliobaki. yaani, ace ni mfululizo wa abcde wakati aec si.  <response>: Heres a Java function that solves the problem:public boolean isSubsequenceString s, String t int sIndex 0; int tIndex 0; while sIndex s.length tIndex t.length if s.charAtsIndex t.charAttIndex sIndex; tIndex; return sIndex s.length;This function uses two index variables, sIndex and tIndex, to iterate through the characters of the two strings. If the current characters match, sIndex is incremented to move on to the next character in s. Regardless, tIndex is always incremented to move on to the next character in t. If sIndex reaches the end of the s string, we know that all of the characters in s are present in t in their original relative positions, so we return true. Otherwise, we return false.Note that this function assumes that s and t are non-null. To handle null strings, we would need to add additional null checking and return false if either string is null. 