<prompt> Kutokana na kamba s na kamusi ya maneno dict, kuamua kama s inaweza kuwa segmented katika mfululizo nafasi-aliyetenganishwa ya moja au zaidi kamusi maneno. Kwa mfano, kama input kamba ni leetcode na kamusi ni leet, code, pato lazima kweli.  <response>: This problem can be solved with dynamic programming. We can create an array dp of size n1 where n is the length of the input string s such that dpi is true if substring s0:i can be segmented into space-separated words, otherwise false. We can use a nested loop to iterate over all possible substrings and for each substring, check if it can be formed by concatenating a word from the dictionary with a previously segmented substring. If such a segment is found, we can set dpi to true and continue to the next iteration. Once we have computed dpn, the last element in the array, we can return its value as the final result. Here is the code:def word_breaks, word_dict: n lens dp False n1 dp0 True for i in range1, n1: for j in rangei: if dpj and sj:i in word_dict: dpi True break return dpnWe start with dp0 True since an empty string can always be formed. We then iterate over all substrings s0:i and try to find a word w in the dictionary such that sj:i w s0:j, where 0 j i-1. If such a word is found, we set dpi to True and continue with the next iteration. Once the iteration is complete, we return dpn as the final result. 