<prompt> Kutokana na mizizi ya mti binary, kurudi urefu wa kipenyo ya mti. Kipenyo cha mti binary ni urefu wa njia ndefu kati ya nodes yoyote mbili katika mti. Njia hii inaweza au hawezi kupita kupitia mizizi. urefu wa njia kati ya nodes mbili ni kuwakilishwa na idadi ya kingo kati yao.  <response>: You can calculate the diameter of a binary tree by finding the longest path between any two leaf nodes. One way to do this is to traverse the tree recursively and for each node, calculate the maximum depth of its left and right subtrees. Add these two depths which represents the edges on the longest path passing through this node and compare it to the current maximum diameter.Heres some Python code to accomplish this:class Solution: def diameterOfBinaryTreeself, root: TreeNode - int: self.diameter 0 def depthnode: if not node: return 0 left depthnode.left right depthnode.right self.diameter maxself.diameter, left right return 1 maxleft, right depthroot return self.diameterIn this solution, we define a helper function depthnode that returns the maximum depth of the input nodes subtree. It does this recursively by calculating the maximum depth of the left and right subtrees and returning the maximum of those two plus one for the current node.At each node, we also calculate the diameter of the tree passing through that node by adding the maximum depths of its left and right subtrees. We update the overall maximum diameter at each node.Finally, we call depthroot to recursively calculate the maximum depth and diameter of the entire binary tree, and we return the maximum diameter at the end. 