<prompt> Kuna viambajengo r,s, na t ilipn rpn - 1 spn - 2 tpn - 3kwa quadratic polynomial px, na nambari yoyote n. Ingiza uliyoagiza mara tatu r,s,t.  <response>: Kwa kuwa hii lazima ishikilie kwa quadratic yoyote, hebu tuangalie kesi ambapo px x2. Kisha equation iliyotolewa inakuwa.n2 rn - 12 sn - 22 tn - 32.Hii inapanuka kaman2 r s tn2 -2r - 4s - 6tn r 4s 9t.Kulingana na mgawo wa pande zote mbili, tunapata mfumo.anzaalignr s t 1, -2r - 4s - 6t 0, r 4s 9t 0.endalignKutatua mfumo huu wa mstari, tunapata r 3, s -3, na t 1.Tunathibitisha dai: Hebu px ax2 bx c. Kishaanzaalign3pn - 1 - 3pn - 2 pn - 3 3an - 12 bn - 1 c - 3an - 22 bn - 2 c an - 3 2 bn - 3 c a3n - 12 - 3n - 22 n - 32 b3n - 1 - 3n - 2 n - 3 c3 - 3 1 an2 bn c pn.endalignKwa hivyo, dai ni kweli, na r,s,t 3,-3,1. 