<prompt> Acha theta iwe pembe ya papo hapo, na iruhususin fractheta2 sqrtfracx - 12x.Onyesha tan theta kulingana na x.  <response>: Kwa fomula ya pembe mbili,cos theta 1 - 2 sin2 fractheta2 1 - 2 cdot fracx - 12x frac1x. Kwa kuwa theta ni kali,sin theta sqrt1 - cos2 theta sqrt1 - frac1x2,hivyotan theta fracsin thetacos theta fracsqrt1 - frac1x2frac1x x sqrt1 - frac1x2 sqrtx2 - 1. 