<prompt> Acha x na y ziwe nambari halisi zinazotosheleza x4y5y4x5810 na x3y6y3x6945. Tathmini 2x3xy32y3.  <response>: Tukiweka x4y4 na x3y3 kutoka pande za mkono wa kushoto wa milinganyo miwili, mtawalia, tunapata beginaligned x4y4xy 810, x3y3x3y3 945. endalignedHebu s xy na p xy. Kisha tunaweza kuandika upya iliyotolewa milinganyo kama anzailiyopangwa p4s 810, p3s3-3ps 945,mwishoiliyopangwakwa kutumia x3y3 xy3 - 3xyxy s3 - 3ps. Kubadilisha s 810p4 kwenye mlingano wa pili, tunapata beginaligned p3leftfrac8103p12 - 3p cdot frac 810p4kulia 945 frac8103p9 - 3 cdot 810 945 p9 frac8103 3 cdot 810 945 frac8103153 543. endiliyopangwaHivyo p sqrt354, na s 810p4 81054sqrt354 15sqrt 354. Kiasi tunachotaka kukokotoa ni anzailiyopangwa 2x3 xy3 2y3 2s3 - 3ps p3 2s3 - 6ps p3 2 cdot frac15354 - 6 cdot sqrt354 cdot frac15 sqrt354 54 125 - 90 54 89. mwishozilizopangiliwa 