<prompt> Kuna 2n nambari changamano zinazotosheleza z28 - z8 - 1 0 na z 1. Nambari hizi zina fomu z_m costheta_m isintheta_m, ambapo 0leqtheta_1 theta_2 dots theta_ 2n 360 na pembe hupimwa kwa digrii. Pata thamani ya theta_2 theta_4 dots theta_2n.  <response>: Kutoka kwa mlinganyo z28 - z8 - 1 0, z28 - z8 1, auz8 z20 - 1 1.Kisha z8 z20 - 1 1. Tangu z 1,z20 - 1 1. Kwa hivyo ikiwa w z20, basi w iko kwenye mduara unaozingatia 1 na radius 1. Lakini w z20 z20 1, kwa hivyo w pia iko kwenye mduara unaozingatia asili na radius 1. Miduara hii inakatiza kwa operatornamecis 60circ na operatornamecis 300circ, hivyo w z20 lazima iwe mojawapo ya thamani hizi.asyukubwa wa kitengo 1.5 cm;choraMduara0,0,1;choraMduara1,0,1;chora-1.5,0--2.5,0;chora0,-1.5--0,1.5;nukta 0,0;nukta 1,0;nukta dir60, nyekundu;nukta dir-60, nyekundu;asyIkiwa z20 jina la uendeshajicis 60circ, basi z20 - 1 jina la operetacis 120circ, hivyo z8 jina la operetacis 240circ. Kishaz4 fracz20z82 jina la operetacis 300circ.Kinyume chake, if z4 operatornamecis 300circ, basianzaalignz8 z20 - 1 jina la operetacis 600circ jina la operetacis 1500circ - 1 jina la operetacis 240circ jina la operetacis 60circ - 1 jina la operetacis 240circ jina la kiendeshajicis 120circ 1.endalignMasuluhisho ya z4 jina la operetacis 300circ ni operatornamecis 75circ, operatornamecis 165circ, jina la operetacis 255circ, na jina la operetacis 345circ.Vile vile, kesi z20 operatornamecis 300circ inaongoza kwaz4 jina la uendeshajicis 60circ.Masuluhisho ya mlingano huu ni operatornamecis 15circ, operatornamecis 105circ, opereta jinacis 195circ, na operatornamecis 285circ.Kwa hiyo, ufumbuzi wote nijina la operetacis 15circ, jina la mendeshajicis 75circ, jina la operetacis 105circ, jina la operetacis 165circ, jina la operetacis 195circ, jina la operetacis 255circ, jina la operetacis 285circ, jina la operetacis 345circ.Jibu la mwisho ni 75 165 255 345 840. 