<prompt> Acha a, b, c ziwe nambari zisizo za kweli kama abc0 na a3b3c3a5b5c 5. Tafuta thamani ya a2b2c2.  <response>: Kutoka kwa factorizationa3 b3 c3 - 3abc a b ca2 b2 c2 - ab - ac - bc,tunajua kwamba a 3 b3 c3 3abc.Kwa kuwa a b c 0, c -a - b, hivyoanzaaligna5 b5 c5 a5 b5 - a b5 -5a4 b - 10a3 b2 - 10a2 b3 - 5ab4 -5aba3 2a2 b 2ab2 b3 -5aba3 b3 2a2 b 2ab2 -5aba ba2 - ab b2 2aba b -5aba ba2 ab b2 5abca2 ab b2,mwishoalignhivyo3abc 5abca2 ab b2.Kwa kuwa a,b, c zote si nzero, tunaweza kuandikaa2 ab b2 frac35.Kwa hiyo,anzaaligna2 b2 c2 a2 b2 a b2 a2 b2 a2 2ab b2 2a2 2ab 2b2 2a2 ab b2 frac65.mwishopanga 