<prompt> Chaguo za kukokotoa f zimechorwa hapa chini. Kila sanduku dogo lina upana na urefu 1.asyukubwa 150;ticklen halisi3;nafasi halisi ya tiki2;urefu halisi 0.1cm;saizi halisi ya mshale0.14cm;mhimili wa kalamunyeusi1.3bp;vectorarrowsize halisi0.2cm;tickdown halisi-0.5;tickdownlength halisi-0.15inch;halisi tickdownbase0.3;tickdown halisitickdown;utupu rr_cartesian_axesxleft halisi, xright halisi, ybottom halisi, ytop halisi, xstep1, ystep1, bool useticksfalse, bool complexplanefalse, bool usegridtrue kuagiza grafu;mimi halisi;ikiwacomplexplane lebotextnormalRe,xright,0,SE;lebotextnormalIm,0,ytop,NW; nyengine lebox,xright0.4,-0.5;leboy,-0.5,ytop0.2;ylimitsybottom,ytop;xlimits xleft, xright;halisi TicksArrx,TicksArry;kwaixleftxstep; i0.1 TicksArrx.pushi;kwaiybottomystep; i0.1 TicksArry.sukumai;ikiwa tumia gridi xaxisBottomTopextendfalse, Ticks, TicksArrx ,pTickgray0.22,extendtrue,pisiyoonekana;,juukweli;yaxisLeftRightextendfalse,Ticks, TicksArry ,pTickgray0.22,extendtrue, pinvisible;,mishale;ikiwa vijiti vya matumizi xequals0, yminybottom, ymaxytop, paxispen, Ticks,TicksArry , pTickblack0.8bp,Sizeticklength, juukweli, Mishalesizeaxisarrowsize;yequals0, xminxleft, xmaxxright, paxispen, Ticks,TicksArrx , pTickblack0.8bp,Sizeticklength, juukweli, Mishalesizeaxisarrowsize; nyengine xequals0, yminybottom, ymaxytop, pmhimili, juukweli, Mishaleukubwaaxisarrowsize;yequals0, xminxleft, xmaxxright, paxispen, juukweli, Mishalesizeaxisarrowsize;;rr_cartesian_axes-1,9,-1,9;nukta0,0,nyekundu5bp;nukta2,1,nyekundu5bp;nukta4,3,nyekundu5bp;nukta6,5,nyekundu5bp;nukta8,7,nyekundu5bp;nukta1,8,nyekundu5bp;nukta 3,6, nyekundu5bp;nukta5,4,nyekundu5bp;nukta 7,2,nyekundu5bp;nukta9,0,nyekundu5bp;asyLarry anaandika nambari 3 kwenye kidole chake cha pinky. Kisha anatumia f kwa 3 na kuandika matokeo kwenye kidole chake cha pete. Ikiwa Larry ataendelea na mchakato huu wa kutumia f na kuandika matokeo kwenye kidole kipya, Larry ataandika nambari gani kwenye kidole chake cha kumi?  <response>: Kusoma kutoka kwa grafu tunaona kuwa f36. Kwa hivyo Larry anaandika 6 kwenye kidole chake cha pili. Kwa kuwa f65 tunaona kwamba Larry anaandika 5 kwenye kidole hiki cha tatu. Tukiweka f tena, tunaona kwamba Larry anaandika f54 kwenye kidole cha nne. Baada ya hayo Larry anaandika f43 kwenye kidole chake cha tano. Sasa mchakato unarudiwa!Kwa kuwa kidole cha kwanza kina 3 juu yake na kidole cha tano pia kinapata 3 zamu 4 baadaye, kidole cha tisa pia kitaitwa 3. Kwa hivyo Larry anaandika f36 kwenye kidole chake cha kumi. 