<prompt> Kwa kuzingatia nambari mbili, saa na dakika, rudisha _pembe ndogo zaidi katika digrii iliyoundwa kati ya_ saa _na_ dakika _mkono_.Majibu ndani ya 10-5 ya thamani halisi yatakubaliwa kuwa sahihi.Mfano wa 1:Ingizo: saa 12, dakika 30Pato: 165Mfano wa 2:Ingizo: saa 3, dakika 30Pato: 75Mfano wa 3:Ingizo: saa 3, dakika 15Pato: 7.5Vikwazo: 1 saa 12 0 dakika 59  <response>: def maxEqualFreqnambari: hesabu, mara kwa mara , max_len, max_freq 0, 0 kwa i, nambari katika enumeratenambari: countnum count.getnambari, 0 1 freqcountnum - 1 freq.gethesabunum - 1, 0 - 1 freqcountnum freq.getcountnum, 0 1 max_freq maxmax_freq, countnum ikiwa max_freq i 1 i au max_freq freq.getmax_freq - 1, 0 1 max_freq - 1 freq.getmax_freq - 1, 0 i: max_len mimi 1 rudisha max_len 