<prompt> Mchemraba wa polinomia px inatosheleza p2 1, p7 19, p15 11, na p20 29. Tafutap1 p2 p3 dots p21.  <response>: Ujazo hupitia pointi 2,1, 7,19, 15,11, na 20,29. Pointi hizi zinapopangwa, tunapata kwamba zinaunda. vipeo vya parallelogramu, ambayo kituo chake ni 11,15. Tunachukua fursa hii kama ifuatavyo.asyukubwa wa kitengo cm 0.2;func halisi x halisi halisi y 23x3585 - 253x2195 7396x585 - 75739;kurudi y;jozi A, B, C, D;A 2,1;B 7,19;C 15,11;D 20,29;kuchoragraphfunc,1.5,20.5,nyekundu;choraA--B--D--C--mzunguko, umekatika;lebo11,15, 11,15, NE, UnFill;nukta2,1, A, SW;nukta7,19, B, W;nukta15,11, C, SE;nukta20,29, D, NE;nukta 11,15;asyHebu fx px 11 - 15. Kishaanzaalignf-9 p2 - 15 -14, f-4 p7 - 15 4, f4 p15 - 15 -4, f9 p20 - 15 14.endalignSasa, acha gx -f-x. Kishaanzaaligng-9 -f9 -14, g-4 -f4 4, g4 -f-4 -4, g9 -f-9 14.endalignZote fx na gx ni polinomia za ujazo, na zinaafikiana katika thamani nne tofauti, kwa hivyo kwa Nadharia ya Utambulisho, zinalingana. Kwa maneno mengine,-f-x fx.Kisha15 - p11 - x px 11 - 15,hivyop11 - x px 11 30kwa x. zoteHebuS p1 p2 p3 dots p21.KishaS p21 p20 p19 dots p1,hivyo2S p1 p21 p2 p20 p3 p19 dots p21 p 1.Kwa kuwa p11 - x px 11 30, kila moja ya muhtasari huu ni sawa na 30. Kwa hiyo,2S 21 cdot 30 630,na S 6302 315. 