<prompt> Ikiwa omega1997 1 na omega neq 1, basi tathminifrac11 omega frac11 omega2 dots frac11 omega1997.  <response>: Kumbuka hiloanzaalignfrac11 omegak frac11 omega1997 - k frac11 omegak frac omegakomegak omega1997 frac11 omegak fracomegakomegak 1 frac1 omegak1 omegak 1.endalignKwa hivyo, tunaweza kuoanisha mashartifrac11 omega, frac11 omega2, dots, frac11 omega1995, frac11 omega1996katika 19962 998 jozi, ili jumla ya nambari katika kila jozi ni 1. Pia, frac11 omega1997 frac12, kwa hivyo jumla itafikia 998 frac12 frac19972. 