<prompt> Safu iliyoonyeshwa ina msingi wa mraba wa urefu wa upande s. Ukingo wa juu unalingana na msingi na una urefu wa 2s. Kingo zingine zote zina urefu wa s. Kwa kuzingatia kwamba s6sqrt2, ni kiasi gani cha kiasi cha solid?asy ukubwa 180; kuagiza tatu; pathpen nyeusi linewidth 0.65; pointpen nyeusi; currentprojection mtazamo30,-20,10; halisi s 6 2 .5; triple A0,0,0,Bs,0,0,Cs,s,0,D0,s,0,E-s2,s 2,6,F3s2,s2,6; choraA--B--C--D--A--E--D; kuchoraB--F--C; kuchoraE--F; leboA,A,W; leboB,B,S; leboC,C,SE; leboD,D,NE; leboE,E,N; leboF,F,N; asy  <response>: asy ukubwa 180; kuagiza tatu; pathpen nyeusi linewidth 0.65; pointpen nyeusi; currentprojection mtazamo30,-20,10; halisi s 6 2 .5; triple A0,0,0,Bs,0,0,Cs,s,0,D0,s,0,E-s2,s 2,6,F3s2,s2,6,Gs2,-s2,-6,Hs2,3s2 ,-6; choraA--B--C--D--A--E--D; kuchoraB--F--C; kuchoraE--F; choraA--G--B,iliyokatika;choraG--H,dashed;choraC--H--D,iliyokatika; leboA,A,-1,-1,0; leboB,B,2,-1,0; leboC,C, 1, 1,0; leboD,D,-1, 1,0; leboE,E,0,0,1; leboF,F,0,0,1; leboG,G,0,0,-1; leboH,H,0,0,-1; asyOngeza EA na FB ili kukutana kwa G, na ED na FC ili kukutana kwa H. Sasa, tunayo tetrahedron ya kawaida EFGH, ambayo kwa ulinganifu ina mara mbili ya ujazo wa kigumu chetu cha asili. Tetrahedron hii ina urefu wa upande 2s 12sqrt2. Kwa kutumia fomula ya ujazo wa tetrahedron ya kawaida, ambayo ni V fracsqrt2S312, ambapo S ni urefu wa upande wa tetrahedron, ujazo wa solid yetu asili ni :V frac12 cdot fracsqrt2 cdot 12sqrt2312 288. 