<prompt> Tatua kwa x: dfrac66-2x2x3dfrac4-2x2x16  <response>: Kwanza, tunatambua kwamba 2x1622x3: dfrac266-2x22x3 dfrac4-2x22x3Kisha, tunapanua na kukusanya masharti kama vile: dfrac128-2x22x3 0Mlinganyo huu unaweza kuwa kweli tu wakati 2x 128, ambayo inaonyesha kuwa x 7. 