<prompt> Kona A ya kipande cha karatasi ya mstatili ya upana wa inchi 8 inakunjwa ili sanjari na uhakika C upande wa pili. Ikiwa BC inchi 5, tafuta urefu katika inchi za kukunjwa l.asyukubwa 100;kuchora 0,0 -- 8,0 -- 8, 10 -- 0, 10 -- mzunguko;nukta 8,10; nukta 0,6; nukta 3,10;leboA, 8,10 , NE; leboC, 0,6, W; leboB, 3,10, N;lebo 8 , 0,0--8,0, S;chora0,0--8,0; chora0,0--0,6; chora0,10--3,10;chora8,0--3,10, 1ptdashed;chora0,6--3,10; chora0,6--8,0;lebo l, 6,6, SE;asy  <response>: Weka alama kwenye O, N, M kama ifuatavyo. asyukubwa 100;kuchora 0,0 -- 8,0 -- 8, 10 -- 0, 10 -- mzunguko;nukta 8,10; nukta 0,6; nukta 3,10; nukta 8,0;leboA, 8,10 , NE; leboC, 0,6, W; leboB, 3,10, N; leboN, 8,0, SE; leboO, 0,0, SW; leboM, 0,10, NW; lebo5, 1.5, 8, SE;lebo 8 , 0,0--8,0, S;chora0,0--8,0; chora0,0--0,6; chora0,10--3,10;chora8,0--3,10, 1ptdashed;chora0,6--3,10; chora0,6--8,0;lebo l, 6,6, SE;asy Kwa sababu kukunja huhifadhi kona A ambayo sasa ni C, tuna pembetatu mbili zinazolingana pembetatu BAN cong pembetatu BCN. Hii ina maana kwamba ABBC5. Kwa kujua hili, tunaweza kukokotoa MB8-53 na MCsqrt52-324.Ona pia kwamba tuna pembetatu zinazofanana pembetatu BMC sim pembetatu CON. Hii inaweza kubainishwa kwa kutafuta pembe. Kwa hivyo, tuna fracMBCOfracBCCNfracMCONfrac48 . Kwa kujua MB3 na CB5, tunaweza kukokotoa CO6 na CN10.asyukubwa 100;kuchora 0,0 -- 8,0 -- 8, 10 -- 0, 10 -- mzunguko;nukta 8,10; nukta 0,6; nukta 3,10; nukta 8,0;leboA, 8,10 , NE; leboC, 0,6, W; leboB, 3,10, N; leboN, 8,0, SE; leboO, 0,0, SW; leboM, 0,10, NW; lebo5, 1.5, 8, SE;lebo 8 , 0,0--8,0, S;chora0,0--8,0; chora0,0--0,6; chora0,10--3,10;chora8,0--3,10, 1ptdashed;chora0,6--3,10; chora0,6--8,0;lebo l, 6,6, SE; lebo6, 0,3, W; lebo10,4,3,SW; lebo4,0,9, W; lebo3,1.5,10,N; lebo5,5.5,10,N;asySasa, tunaona kwamba AN6410. Na Pythagoras kwenye pembetatu BAN, tuna BNsqrt521025sqrt5. Kwa hivyo, l5sqrt5. 