<prompt> Parabola nyekundu iliyoonyeshwa ni grafu ya mlinganyo x ay2 by c. Tafuta c. Chukulia kuwa grafu ina kiwango cha kitengo cha kawaida.asyukubwa 150;ticklen halisi3;nafasi halisi ya tiki2;urefu halisi 0.1cm;saizi halisi ya mshale0.14cm;mhimili wa kalamunyeusi1.3bp;vectorarrowsize halisi0.2cm;tickdown halisi-0.5;tickdownlength halisi-0.15inch;halisi tickdownbase0.3;tickdown halisitickdown;utupu rr_cartesian axesxleft halisi, xright halisi, ybottom halisi, ytop halisi, xstep1 halisi, ystep1, booluseticksuongo, bool complexplaneuongo, bool usegridkweli kuagiza grafu;mimi halisi;ikiwacomplexplane lebotextnormalRe,xright,0,SE;lebotextnormalIm,0,ytop,NW; nyengine lebox,xright0.4,-0.5;leboy,-0.5,ytop0.2;ylimitsybottom,ytop;xlimits xleft, xright;halisi TicksArrx,TicksArry;kwaixleftxstep; i0.1 TicksArrx.pushi;kwaiybottomystep; i0.1 TicksArry.sukumai;ikiwa tumia gridi xaxisBottomTopextendfalse, Kupe, TicksArrx ,pTickgray0.22, ongezakweli,pisiyoonekana;,juukweli;yaxisLeftRightextendfalse,Ticks, TicksArry ,pTickgrey0.22,extendtrue,pisiyoonekana;,Mishale;ikiwa vijiti vya matumizi xequals0, yminybottom, ymaxytop, paxispen, Ticks,TicksArry ,pTicknyeusi0.8bp,Ukubwaurefu wa kutekenya, juukweli, Mishaleukubwaaxisarrowsize;yequals0, xminxleft, xmaxxright, paxispen, Ticks,TicksArrx ,pTicknyeusi0.8bp,Ukubwaurefu wa kutekenya, juukweli, Mishaleukubwaaxisarrowsize; nyengine xequals0, yminybottom, ymaxytop, pmhimili, juukweli, Mishaleukubwaaxisarrowsize;yequals0, xminxleft, xmaxxright, paxispen, juukweli, Mishalesizeaxisarrowsize;;lowerx halisi, upperx, lowery, uppery;f halisi x halisi kurudi -x-2x-223;chini -1;juu 5;rr_cartesian_axes-4,4,lowry,uppery;choratafakari0,0,1,1grafuf,lowry,uppery,operator .., nyekundu;asy  <response>: Kipeo cha parabola ni 3,2, kwa hivyo mlingano wa parabola ni wa umbo x ay - 22 3. Parabola hupitia nukta 1 ,4. Kuweka thamani hizi kwenye mlingano ulio hapo juu, tunapata 1 a4 - 22 3. Kutatua kwa a, tunapata a -12. Kwa hivyo, mlinganyo wa parabola umetolewa na x -frac12 y - 22 3 -frac12 y2 - 4y 4 3 -frac12 y2 2y 1. Jibu ni 1.Vinginevyo, thamani ya x ay2 by c ni c wakati y 0. Parabola hupita kwa uhakika 1,0, hivyo c 1. 