<prompt> Hebufx arccos x3 arcsin x3.Tafuta masafa ya fx. Vitendaji vyote viko katika radiani.  <response>: Kwanza, tunadai kwamba arccos x arcsin x fracpi2 kwa x yote katika -1,1.Kumbuka hilocos kushoto fracpi2 - arcsin x kulia cos arccos x x.Zaidi ya hayo, -fracpi2 le arcsin x le fracpi2, hivyo 0 le fracpi2 - arcsin x le pi. Kwa hiyo,fracpi2 - arcsin x arccos x,hivyo arccos x arcsin x fracpi2.Hebu alpha arccos x na beta arcsin x, hivyo alpha beta fracpi2. Kishaanzaalignfx arccos x3 arcsin x3 alpha3 beta3 alpha betaalpha2 - alpha beta beta2 fracpi2 kushoto kushoto fracpi2 - beta kulia2 - kushoto fracpi2 - beta kulia beta beta2 kulia fracpi2 kushoto 3 beta2 - frac3 pi beta2 fracpi24 kulia frac3 pi2 kushoto beta2 - fracpi2 beta fracpi212 kulia frac3 pi2 kushoto kushoto beta - fracpi4 kulia2 fracpi248 kulia .endalignKwa kuwa -fracpi2 le beta le fracpi2, anuwai ya fx ni left fracpi332, frac7 pi38 kulia. 