<prompt> Acha ABCD iwe sehemu ya pembe nne iliyosonga, na G_A,G_B,G_C,G_D irejelee sehemu za katikati za pembetatu BCD,ACD,ABD, na ABC, mtawalia. Pata fracG_A G_B G_C G_DABCD.asyukubwa wa kitengo cm 0.6;jozi A, B, C, D;jozi G;A 0,0;B 7,1;C 5,-5;D 1,-3;G1 B C D3;G2 A C D3;G3 A B D3;G4 A B C3;kuchoraA--B--C--D--mzunguko;kuchoraG1--G2--G3--G4--mzunguko,nyekundu;leboA, A, W;leboB, B, NE;leboC, C, SE;leboD, D, SW;nuktaG_A, G1, SE;nuktaG_B, G2, W;nuktaG_C, G3, NW;nuktaG_D, G4, NE;asy  <response>: Tuna hiyoanzaalignmshale wa kulia zaidiG_A fracmshale uliopitilizaB ushale uliopitilizaC ushale wa kuliaD3, mshale uliopitilizaG_B fracarrow overrightarrowA overrightarrowC overrightarrowD3, mshale wa kulia zaidiG_C fracoverrightarrowA overrightarrowB overrightarrowD3, overrightarrowG_D fracoverrightarrowA overrightarrowB overrightarrowC3.mwishoalignKishaanzaalignmshale wa kulia zaidiG_B G_A ushale uliopitilizaG_A - ushale uliopitilizaG_B fracoverrightarrowB overrightarrowC overrightarrowD3 - fracoverrightarrowA overrightarrowC overrightarrowD3 frac13 arrowoverrightarrowB - overrightarrowA frac13 overrightarrowAB.endalignInafuata kwamba overlineG_B G_A ni sambamba na overlineAB, na frac13 kwa urefu.Vile vile,overrightarrowG_B G_C frac13 overrightarrowCB.Inafuata kwamba overlineG_B G_C ni sambamba na overlineBC, na frac13 kwa urefu. Kwa hiyo, pembetatu ABC na G_A G_B G_C ni sawa, naG_A G_B G_C frac19 ABC.Kwa njia hiyo hiyo, tunaweza kuonyesha kwambaG_C G_D G_A frac19 CDA.Kwa hiyo, G_A G_B G_C G_C frac19 ABCD, so frac G_A G_B G_C G_DABCD frac19. 