<prompt> Mstari mmoja unafafanuliwa naanzapmatrix 3 -10 1 mwishopmatrix t anzapmatrix 2 -9 -2 mwishopmatrix.Mstari mwingine unafafanuliwa kwaanzapmatrix -5 -3 6 mwishopmatrix u anzapmatrix 4 -18 -4 mwishopmatrix.Mistari hii miwili inafanana . Tafuta umbali kati ya mistari hii miwili.  <response>: Tunaona kwamba 3,-10,1 ni nukta kwenye mstari wa kwanza.Hoja kwenye mstari wa pili inatolewa naanzapmatrix x y z mwishopmatrix anzapmatrix -5 -3 6 mwishopmatrix t anzapmatrix 4 - 18 -4 mwishopmatrix anzapmatrix -5 4t -3 - 18t 6 - 4t mwishopmatrix.asyukubwa wa kitengo 0.6 cm;jozi A, B, C, D, E, F, H;A 2,5;B 0,0;C 8,0;D A tafakariB,CA2;kuchoraA--D;chora0,5--8,5;chora0,0--8,0;nukta3,-10,1, A, N;nukta-5 4t, -3 - 18t, 6 - 4t, D, S;asyVekta inayoelekeza kutoka 3,-10,1 hadi -5 4t, -3 - 18t, 6 - 4t basimathbfv anzapmatrix -8 4t 7 - 18t 5 - 4t endpmatrix.Kwa uhakika kwenye mstari wa pili ulio karibu zaidi na 3, -10,1, vekta hii itakuwa ya orthogonal kwa vekta ya mwelekeo wa mstari wa pili, ambayo ni beginpmatrix 4 -18 -4 endpmatrix. Hivyo,anzapmatrix -8 4t 7 - 18t 5 - 4t mwishopmatrix cdot anzapmatrix 4 -18 -4 mwishopmatrix 0. Hii inatupa -8 4t4 7 - 18t-18 5 - 4t-4 0. Kutatua, tunapata t frac1 2.Kubadilisha thamani hii kuwa mathbfv, tunapata kwamba umbali kati ya mistari sambamba ni basi.mathbfv kushoto anzapmatrix -6 -2 3 mwishopmatrix kulia 7. 