<prompt> ABCD ni karatasi ya mstatili ambayo imekunjwa ili kona B ilingane na ncha B kwenye ukingo AD. Mkunjo ni EF, ambapo E iko kwenye AB na F iko kwenye CD. Vipimo AE8, BE17, na CF3 vimetolewa. Mzunguko wa mstatili ABCD ni mn, ambapo m na n ni nambari kamili chanya. Tafuta mn.asy ukubwa 200; defaultpenlinewidth0.7fontsize10; jozi Aasili, B25,0, C25,703, D0,703, E8,0, F22,703 , BptafakariE,FB, CptafakariE,FC; kuchoraF--D--A--E; choraE--B--C--F, aina ya mstari4 4; filldrawE--F--Cp--Bp--mzunguko, nyeupe, nyeusi; pair point 12.5, 353 ; leboA, A, dirpoint--A; leboB, B, dirpoint--B; leboC, C, dirpoint--C; leboD, D, dirpoint--D; leboE, E, dirpoint--E; leboF, F, dirpoint--F; leboBprime, Bp, dirpoint--Bp; leboCprime, Cp, dirpoint--Cp;asy  <response>: asy pointpen nyeusi; pathpen nyeusi linewidth0.7; jozi A0,0,B0,25,C703,25,D703,0,E0,8,F70 3,22,G15,0; DMPA,A--MPB,B,N--MPC,C,N--MPD,D--mzunguko; DMPE,E,W--MPF,F,1,0; DB--G; DE--MPB,G--F--B,dashed; MP8,AE2,W;MP17,BE2,W;MP22,DF2,1 ,0; asyKwa kuwa EF ndio kipengee kiwiliwili cha overlineBB, inafuata kwamba BE BE na SAS. Kwa nadharia ya Pythagorean, tuna AB 15. Vile vile, kutoka BF BF, tumeanzaalign BC2 CF2 BD2 DF2 Longrightarrow BC2 9 BC - 15 2 484 BC frac703 endalignHivyo eneo la ABCD ni 2kushoto25 frac703kulia frac2903, na jibu ni mn293. 