<prompt> Pata nambari zote halisi x kiasi kwamba leftfracx2x-1kulia2 le 9.  <response>: Tunapanua upande wa kushoto na kisha kutoa 9 kutoka pande zote mbili, tukitoa fracx2-94x2-4x14x2-4x1 frac -35x2 36x - 94x2-4x1 le 0 au frac35x2-36x94x2-4x1 ge 0. Kuweka alama juu na chini kunatoa frac5x-37x-32x-12 ge 0.Kuruhusu fx kuashiria upande wa kushoto, tunatoa jedwali la ishara kama ifuatavyo: anzatabularccccc 5x-3 7x-3 2x-12 fx hlinexfrac37 -- .1cmfrac37frac35 .1cmendtabularTunaona kwamba fx 0 wakati x tfrac37 au x tfrac35. Pia, fx 0 wakati x tfrac37 au x tfrac35. Kwa hivyo, suluhu iliyowekwa kuwa fx ge 0 ni x in -infty, tfrac37 cup tfrac35, infty , . 