<prompt> Tafuta idadi ya suluhishofrac1sin2 theta - frac1cos2 theta - frac1tan2 theta - frac1 cot2 theta - frac1sec2 theta - frac1csc2 theta -3katika kipindi 0 le theta le 2 pi.  <response>: Tunaweza kuandikaanzaalignfrac1sin2 theta - frac1cos2 theta - frac1tan2 theta - frac1 cot2 theta - frac1sec2 theta - frac1csc2 theta frac1sin2 theta - frac1cos2 theta - fraccos2 thetasin2 theta - tan2 theta - cos2 theta - sin2 theta frac1 - cos2 thetasin2 theta - frac1cos2 theta - tan2 theta - 1 fracsin2 thetasin2 theta - frac1cos2 theta - tan2 theta - 1 -frac1cos2 theta - tan2 theta -3.mwishoalignKwa hiyo,frac1cos2 theta tan2 theta 3.Tunaweza kuandika hili kamafracsin2 theta cos2 thetacos2 theta tan2 theta 3,hivyo tan2 theta 1 tan2 theta 3, ambayo hurahisisha kuwa tan2 theta 1. Kumbuka kuwa hadi kufikia hatua hii, hatua zetu zote zimeweza kutenduliwa.Kisha tan theta pm 1, kwa hivyo suluhu ni fracpi4, frac3 pi4, frac5 pi 4, na frac7 pi4, kwa jumla ya 4 suluhu. 