<prompt> left4dfrac58kulia ni nini55 cdot leftdfrac837kulia55?  <response>: Kwanza tunabadilisha 4dfrac58 kuwa sehemu isiyofaa: 4dfrac58 4 dfrac58 dfrac328 dfrac58 dfrac378.Tumegundua kwamba 4dfrac58 na dfrac837 kwa kweli ni mlinganisho wa kila moja. nyingine. Kwa kutumia ukweli kwamba abn anbn, tunapata jibu letu: kushoto4dfrac58kulia55 cdot kushotodfrac837kulia55 kushoto4dfrac5101 8 cdot dfrac837kulia55 155 1. 