<prompt> Kwa kuzingatia DC 7, CB 8, AB frac14AD, na ED frac45AD, pata FC. Eleza jibu lako kama desimali. asykuchora0,0---20,0---20,16--mzunguko;chora-13,0---13,10.4;chora-5,0---5,4;chora-5,0.5---50.5,0.5---50.5,0;chora-13,0.5---130.5,0.5---130.5,0;chora-20,0.5---200.5,0.5---200.5,0;leboA,0,0,E;leboB,-5,0,S;leboG,-5,4,N;leboC,-13,0,S;leboF,-13,10.4,N;leboD,-20,0,S;leboE,-20,16,N;asy  <response>: Tunaweza kuona kwa urahisi hiyo pembetatu ABG sim pembetatu ACF sim pembetatu ADE.Kwanza kabisa, BD AD - AB. Kwa kuwa AB dfrac14AD, tuna hiyo BD dfrac34AD. Kwa kuwa BD pia DC CB 15, tunaona kwamba AD 20 na AB 5. Sasa, tunaweza kupata ED dfrac45AD 16. kwa urahisi.Sasa, tunaona kwamba CA CB BA 8 5 13. Tangu dfracFCCA dfracEDDA, kutokana na kufanana, tuna FC dfracED cdot CADA dfrac16 cdot 1320 10.4. 