#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <numeric>
#include <utility>
#include <tuple>

#define rep(i, a, b) for (int i = int(a); i < int(b); i++)
using namespace std;
using ll = long long int;
using P = pair<ll, ll>;

// clang-format off
#ifdef _DEBUG_
#define dump(...) do{ cerr << __LINE__ << ":\t" << #__VA_ARGS__ << " = "; PPPPP(__VA_ARGS__); cerr << endl; } while(false)
template<typename T> void PPPPP(T t) { cerr << t; }
template<typename T, typename... S> void PPPPP(T t, S... s) { cerr << t << ", "; PPPPP(s...); }
#else
#define dump(...) do{ } while(false)
#endif
template<typename T> vector<T> make_v(size_t a, T b) { return vector<T>(a, b); }
template<typename... Ts> auto make_v(size_t a, Ts... ts) { return vector<decltype(make_v(ts...))>(a, make_v(ts...)); }
template<typename T> bool chmin(T &a, T b) { if (a > b) {a = b; return true; } return false; }
template<typename T> bool chmax(T &a, T b) { if (a < b) {a = b; return true; } return false; }
template<typename T> void print(T a) { cout << a << '\n'; }
template<typename T, typename... Ts> void print(T a, Ts... ts) { cout << a << ' '; print(ts...); }
template<typename T> istream &operator,(istream &in, T &t) { return in >> t; }
// clang-format on

template<ll MOD = 1000000007>
class ModInt {
    ll n;
    ModInt constexpr inverse() const {
        return ModInt::pow(*this, MOD - 2);
    }

public:
    ModInt() : n(0) {}
    ModInt(ll _n) : n(((_n % MOD) + MOD) % MOD) {}
    ModInt operator+=(const ModInt &m) {
        n += m.n;
        if (n >= MOD) n -= MOD;
        return *this;
    }
    ModInt operator-=(const ModInt &m) {
        n -= m.n;
        if (n < 0) n += MOD;
        return *this;
    }
    ModInt operator*=(const ModInt &m) {
        n *= m.n;
        if (n >= MOD) n %= MOD;
        return *this;
    }
    ModInt operator/=(const ModInt &m) {
        (*this) *= m.inverse();
        return *this;
    }
    friend ModInt operator+(ModInt t, const ModInt &m) {
        return t += m;
    }
    friend ModInt operator-(ModInt t, const ModInt &m) {
        return t -= m;
    }
    friend ModInt operator*(ModInt t, const ModInt &m) {
        return t *= m;
    }
    friend ModInt operator/(ModInt t, const ModInt &m) {
        return t /= m;
    }
    ModInt operator=(const ll l) {
        n = l % MOD;
        if (n < 0) n += MOD;
        return *this;
    }
    friend ostream &operator<<(ostream &out, const ModInt &m) {
        out << m.n;
        return out;
    }
    friend istream &operator>>(istream &in, ModInt &m) {
        ll l;
        in >> l;
        m = l;
        return in;
    }
    static constexpr ModInt pow(const ModInt x, ll p) {
        ModInt<MOD> ans = 1;
        for (ModInt<MOD> m = x; p > 0; p /= 2, m *= m) {
            if (p % 2) ans *= m;
        }
        return ans;
    }
};
using mint = ModInt<998244353>;
mint operator"" _m(unsigned long long m) {
    return mint(m);
}

int main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    int n, m, k;
    cin, n, m, k;
    mint ans = 0;
    if (n == 1 || m == 1) {
        print(mint::pow(k, m * n));
        return 0;
    }
    rep(i, 0, k) {
        mint a = mint::pow(k - i, m) - mint::pow(k - i - 1, m);
        ans += a * mint::pow(i + 1, n);
        // dump(ans, a);
    }
    print(ans);
    return 0;
}

// Skyqwq
#include <iostream>
#include <cstdio>

using namespace std;

typedef long long LL;

const int N = 2e5 + 5, P = 998244353;

int n, m, K;

int inline power(int a, int b) {
	int res = 1;
	while (b) {
		if (b & 1) res = (LL)res * a % P;
		a = (LL)a * a % P;
		b >>= 1;
	}
	return res;
}

int ans;

int main() {
	scanf("%d%d%d", &n, &m, &K);
	if (n > 1 && m > 1) {
		for (int i = 1; i <= K; i++) {
			ans = (ans + ((LL)power(i, n) - power(i - 1, n) + P) * power(K - i + 1, m)) % P;
		}
	} else if (n == 1 && m == 1) {
		ans = K;
	} else if (n == 1) {
		for (int i = 1; i <= K; i++) {
			ans = (ans + (LL)power(K - i + 1, m) - power(K - i, m) + P) % P;
		}
	} else if (m == 1) {
		for (int i = 1; i <= K; i++) {
			ans = (ans + (LL)power(i, n) - power(i - 1, n) + P) % P;
		}
	}
	printf("%d\n", ans);
	return 0;
}