#include<bits/stdc++.h>

#include <ext/pb_ds/assoc_container.hpp> //required
#include <ext/pb_ds/tree_policy.hpp> //required

using namespace __gnu_pbds; 
using namespace std;

template <typename T> using ordered_set =  tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; 
// find_by_order(k)  returns iterator to kth element starting from 0;
// order_of_key(k) returns count of elements strictly smaller than k;
typedef long long  ll;
typedef vector<ll> VL;
typedef vector<int> VI;
typedef pair<ll,ll> PLL;
typedef pair<int,int> PII;
#define pb push_back

#define F first
#define S second
#define SZ(a) int((a).size())
#define ALL(a) a.begin(),a.end()
#define fr(i,x,y) for(int i=x;i<y;i++)
#define frr(i,x,y) for(int i=x-1;i>=y;i--)
#define inf 1e18+1
const long double PI = acos(-1.0L);
#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
int mod=1000000007;
//const int mod=998244353;
ll gcd(ll a,ll b) { return b?gcd(b,a%b):a;}
ll power(ll a,ll b){ll ans=1;while(b!=0){if(b&1){ans*=a;}a=a*a;b>>=1;}return ans;}
ll powerm(ll a,ll b){ll ans=1;while(b!=0){if(b&1){ans*=a;ans%=mod;}a=a*a;a%=mod;b>>=1;}return ans%mod;}
VL dx={1,0,-1,0};
VL dy={0,1,0,-1};
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();

void solve()
{
    ll n,m;
    cin>>n>>m;
    mod=m;
    ll rem=powerm(10,n);
    //cout<<rem<<endl;
    mod=m*m;
    ll x=powerm(10,n);
    x/=m;
    x%=mod;
    cout<<x<<endl;
    return;
}
int main()
{
    IOS;
    ll t=1,pp;
    //cin>>t;
    pp=t;
    while(t--)
    {
        //cout<<"Case #"<<pp-t<<": ";
        solve();
    }
    return 0;
}
/* stuff you should look for
        * int overflow, array bounds
        * special cases (n=1?)
        * do smth instead of nothing and stay organized
        * WRITE STUFF DOWN
        * BE CAREFUL REGARDING THE DEFAULT VALUES IN segement trees etc
        * BE very careful in int vs long long vs unsigned long long 
*/
/*
recursion - matrix exponential

*/
// BITMASK:
// 1)When some constrall is of the order of 15-20, think of bitmask DP.
// 2)When some constrall is around 40, try out meet in the middle
// 3) See Strings,palindromes,prefix,suffix etc -> KMP,Z algorithmQ
// atcoder/arc107/D/main.cpp
// author: @___Johniel
// github: https://github.com/johniel/

#include <bits/stdc++.h>

#define each(i, c) for (auto& i : c)
#define unless(cond) if (!(cond))

using namespace std;

template<typename P, typename Q> ostream& operator << (ostream& os, pair<P, Q> p) { os << "(" << p.first << "," << p.second << ")"; return os; }
template<typename P, typename Q> istream& operator >> (istream& is, pair<P, Q>& p) { is >> p.first >> p.second; return is; }
template<typename T> ostream& operator << (ostream& os, vector<T> v) { os << "("; for (auto& i: v) os << i << ","; os << ")"; return os; }
template<typename T> istream& operator >> (istream& is, vector<T>& v) { for (auto& i: v) is >> i; return is; }
template<typename T> ostream& operator << (ostream& os, set<T> s) { os << "#{"; for (auto& i: s) os << i << ","; os << "}"; return os; }
template<typename K, typename V> ostream& operator << (ostream& os, map<K, V> m) { os << "{"; for (auto& i: m) os << i << ","; os << "}"; return os; }

template<typename T> inline T setmax(T& a, T b) { return a = std::max(a, b); }
template<typename T> inline T setmin(T& a, T b) { return a = std::min(a, b); }

using lli = long long int;
using ull = unsigned long long;
using point = complex<double>;
using str = string;
template<typename T> using vec = vector<T>;

constexpr array<int, 8> di({0, 1, -1, 0, 1, -1, 1, -1});
constexpr array<int, 8> dj({1, 0, 0, -1, 1, -1, -1, 1});
constexpr lli mod = 998244353;

const int N = 3000 + 3;
const int K = 3000 + 3;
static int memo[N][K];
int rec(int n, int k)
{
  if (k == 0) return n == 0;
  if (n < k) return 0;
  if (n == k) return 1;
  // cout << n << ' ' << k << endl;
  int& ret = memo[n][k];
  if (ret != -1) return ret;
  return ret = (rec(n - 1, k - 1) + rec(n, k * 2)) % mod;
}

int main(int argc, char *argv[])
{
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.setf(ios_base::fixed);
  cout.precision(15);

  int n, k;
  while (cin >> n >> k) {
    if (n < k) {
      cout << 0 << endl;
      continue;
    }
    fill(&memo[0][0], &memo[N - 1][K - 1] + 1, -1);
    cout << rec(n, k) << endl;
  }

  return 0;
}
