
#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <cmath>
#include <stack>
#include <queue>
#include <set>
#include <map>
#include <bitset>
#include <iomanip>
#include <climits>
#include <functional>
#include <cassert>
using namespace std;
typedef long long ll;
typedef pair<int,int> PII;
typedef pair<ll,ll> PLL;
typedef vector<int> VI;
typedef vector<ll> VL;
typedef vector<string> VS;
typedef vector<VI> VVI;
typedef vector<VL> VVL;
typedef vector<PII> VPI;
typedef vector<PLL> VPL;
#define rep(i,n) for(ll i=0;i<(n);i++)
#define rep1(i,n) for(ll i=1;i<(n);i++)
#define rep2(i,n,m) for(ll i=n;i<(m);i++)
#define all(a) (a).begin(),(a).end()
#define pf push_front
#define pb push_back
#define mp make_pair
#define mt make_tuple
#define ub upper_bound
#define lb lower_bound
#define fi first
#define se second
void YES(int a){
  if(a) cout<<"YES"<<endl;
  else cout<<"NO"<<endl;
}
void Yes(int a){
  if(a) cout<<"Yes"<<endl;
  else cout<<"No"<<endl;
}

//#include <atcoder/all>

//using namespace atcoder;
//typedef modint998244353 mint;

int a_max=200200;
const ll mod=998244353;

VL fac(a_max),finv(a_max),inv(a_max);

ll modpow(ll a,ll n){
  ll res=1;
  while(n){
    if(n&1) res=res*a%mod;
    a=a*a%mod;
    n>>=1;
  }
  return res;
}

ll modinv(ll a){
  return modpow(a,mod-2);
}

void init(){
  fac[0]=fac[1]=1;
  finv[0]=finv[1]=1;
  inv[1]=1;
  rep(i,a_max){
    if(i>1){
      fac[i]=fac[i-1]*i%mod;
      inv[i]=mod-inv[mod%i]*(mod/i)%mod;
      finv[i]=finv[i-1]*inv[i]%mod;
    }
  }
}

ll com(ll n,ll k){
  if(n<k) return 0;
  if(n<0||k<0) return 0;
  return fac[n]*(finv[k]*finv[n-k]%mod)%mod;
}


int main(){
  ll N,M;
  cin>>N>>M;
  VVL X(15,VL(5050,-1));
  X[0][0]=1;
  init();
  rep1(i,15){
    ll T=(1ll<<(14-i));
    rep(j,5050){
      if(X[i-1][j]!=-1){
        rep(k,N+1){
          if(k%2) continue;
          if(j+T*k<=5000){
            if(X[i][j+T*k]==-1) X[i][j+T*k]=X[i-1][j]*com(N,k)%mod;
            else (X[i][j+T*k]+=X[i-1][j]*com(N,k)%mod)%=mod;
          }
        }
      }
    }
  }
  if(X[14][M]!=-1) cout<<X[14][M]<<endl;
  else cout<<0<<endl;
  
}


    #include <bits/stdc++.h>
    using namespace std;
    #include <math.h>
    #include <iomanip>
    #include <cstdint>
    #include <string>
    #include <sstream>
    template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
    template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
    #define rep(i,n) for (int i = 0; i < (n); ++i)
    typedef long long ll;
    using P=pair<ll,ll>;
    const int INF=1001001001;
    const int mod=998244353;
    
    struct mint {
      ll x; 
      mint(ll x=0):x((x%mod+mod)%mod){}
      mint operator-() const { return mint(-x);}
      mint& operator+=(const mint a) {
        if ((x += a.x) >= mod) x -= mod;
        return *this;
      }
      mint& operator-=(const mint a) {
        if ((x += mod-a.x) >= mod) x -= mod;
        return *this;
      }
      mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
      mint operator+(const mint a) const { return mint(*this) += a;}
      mint operator-(const mint a) const { return mint(*this) -= a;}
      mint operator*(const mint a) const { return mint(*this) *= a;}
      mint pow(ll t) const {
        if (!t) return 1;
        mint a = pow(t>>1);
        a *= a;
        if (t&1) a *= *this;
        return a;
      }
       
      mint inv() const { return pow(mod-2);}
      mint& operator/=(const mint a) { return *this *= a.inv();}
      mint operator/(const mint a) const { return mint(*this) /= a;}
     };
      istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
      ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
      struct combination {
      vector<mint> fact, ifact;
      combination(int n):fact(n+1),ifact(n+1) {
        assert(n < mod);
        fact[0] = 1;
        for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
        ifact[n] = fact[n].inv();
        for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
      }
      mint operator()(int n, int k) {
        if (k < 0 || k > n) return 0;
        return fact[n]*ifact[k]*ifact[n-k];
      }
     } c(200005);

    void solve(){
      int n,m;
      cin>>n>>m;
      vector<mint>dp(m+1);
      dp[0]=1;
      for(int i=2;i<=m;i+=2){
        for(int j=0;j<=n;j+=2){
          if(i-j>=0){dp[i]+=dp[(i-j)/2]*c(n,j);}
        }
      }
      cout<<dp[m]<<endl;
    }
    int main(){
      ios_base::sync_with_stdio(false);
      cin.tie(NULL);
      solve();
      return 0;
    }