#include <bits/stdc++.h>
#define fo(i, k, n) for (ll i = k; i < n; i++)
#define rfo(i, k, n) for (ll i = k; i >= n  ; i--)
#define ll long long
#define ld long double
#define que queue
#define pb push_back
#define mp make_pair
#define vi vector<int> 
#define vl vector<ll>
#define gcd(m,n) __gcd( m,  n)
#define sq(x)   (x*x)
#define rev(v)  reverse(v.begin(),v.end())
#define srt(v)  sort(v.begin(),v.end())
#define grtsrt(v) sort(v.begin(),v.end(),greater<int>())
#define mnv(v)     *min_element(v.begin(),v.end())
#define mxv(v)    *max_element(v.begin(),v.end())
#define all(v)    v.begin(),v.end()
#define toInteger(s) stoll(s) 
#define toString(num) to_string(num)
#define show(arr) { for (auto x: arr) cout << x << " "; cout << '\n'; }
 

 
using namespace std;
ll MOD = 1e9 + 7;
//--------------------------------------------functions-------------------------------------------------//
 
ll power(ll a,ll b){ll result=1;while(b>0){if(b%2 == 1){result *= a;} a *= a;b /= 2;}return result;}
ll countSetBits(ll x){ll Count=0;while(x>0){if(x&1) Count++;x=x>>1;}return Count;}
bool isPerfectSquare(ll n){ll sr = sqrt(n);if (sr * sr == n)return true;else return false;}
ll mod(ll x,ll M){return ((x%M + M)%M);}
ll mul(ll a, ll b,ll M){return mod(mod(a,M)*mod(b,M),M);}
ll powerM(ll a,ll b,ll M){
    ll res=1ll;
    while(b){
        if(b%2ll==1ll){
            res=mul(a,res,M);
        }
        a=mul(a,a,M);b/=2ll;
    }
    return res;
}
int log22(long long x)
{
    return 64 - __builtin_clzll(x) - 1;
}

//--------------------------------------------SieveOfEratosthenes-------------------------------------------------//
//mem will have true if its prime.
void SieveOfEratosthenes( vector<bool>&mem)
{ ll n = 1e6 +1;
    
    bool prime[n + 1];
    memset(prime, true, sizeof(prime));
 
    for (int p = 2; p * p <= n; p++)
    {
        
        if (prime[p] == true)
        {
            for (int i = p * p; i <= n; i += p)
                prime[i] = false;
        }
    }
 
     fo(i,2,n)
     if(prime[i])mem[i]=true;
    
}


//--------------------------------------------solve-------------------------------------------------//



int main()
{
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);


//freopen("input.txt","r",stdin); 
//freopen("output.txt","w",stdout);
  
cout<<fixed;
float a,b;
cin>>a>>b;

float answer = a*b/100.0;

cout<<setprecision(8)<<answer;


 

 
 
 
 
  return 0;
}
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

 

//clear adj and visited vector declared globally after each test case
//check for long long overflow
//Mod wale question mein last mein if dalo ie. Ans<0 then ans+=mod;
//Incase of close mle change language to c++17 or c++14 
/**#pragma GCC target ("avx2")
#pragma GCC optimization ("O3")
#pragma GCC optimization ("unroll-loops”)**/
#include <bits/stdc++.h>  
#include <ext/pb_ds/assoc_container.hpp>
#define int long long
#define IOS std::ios::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL);cout.precision(dbl::max_digits10);
#define pb push_back
#define mod  998244353ll
#define lld long double
#define mii map<int, int>
#define pii pair<int, int>
#define ff first
#define ss second 
#define all(x) (x).begin(), (x).end()
#define rep(i,x,y) for(int i=x; i<y; i++)    
#define fill(a,b) memset(a, b, sizeof(a))
#define vi vector<int>
#define setbits(x) __builtin_popcountll(x)
#define print2d(dp,n,m) for(int i=0;i<=n;i++){for(int j=0;j<=m;j++)cout<<dp[i][j]<<" ";cout<<"\n";}
typedef std::numeric_limits< double > dbl;
using namespace __gnu_pbds;
using namespace std;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> indexed_set;
//member functions :
//1. order_of_key(k) : number of elements strictly lesser than k
//2. find_by_order(k) : k-th element in the set
const long long N=200005, INF=2000000000000000000;
lld pi=3.1415926535897932;
int lcm(int a, int b)
{
    int g=__gcd(a, b);
    return a/g*b;
}
int power(int a, int b, int p)
    {
        if(a==0)
        return 0;
        int res=1;
        a%=p;
        while(b>0)
        {
            if(b&1)
            res=(res*a)%p;
            b>>=1;
            a=(a*a)%p;
        }
        return res;
    }
int dp[N][20];
int fact[N],inv[N];
void pre()
{
    fact[0]=1;
    inv[0]=1;
    for(int i=1;i<N;i++)
    fact[i]=(i*fact[i-1])%mod;
    for(int i=1;i<N;i++)
    inv[i]=power(fact[i], mod-2, mod);
}
int nCr(int n, int r, int p) 
{ 
    if(r>n)
    return 0;
    if(n==r)
    return 1;
    if (r==0) 
    return 1; 
    return (((fact[n]*inv[r]) % p )*inv[n-r])%p;
}
int32_t main()
{
    IOS;
    pre();
    int n, m;
    cin>>n>>m;
    int ans=0;
    for(int i=m;i>0;i--)
    {
        dp[i][0]=1;
        for(int j=i*2;j<=m;j+=i)
        {
            for(int k=1;k<20;k++)
            dp[i][k]+=dp[j][k-1];
        }
        rep(j,0,20)
        {
            dp[i][j]%=mod;
            ans+=(nCr(n-1, j, mod)*dp[i][j])%mod;
            ans%=mod;
        }
    }
    cout<<ans;
}