#include <bits/stdc++.h>
using namespace std;

typedef long long ll;

bool ll_sqrt(ll x, ll& lower_bound, ll& upper_bound)
{
	constexpr ll ll_max = numeric_limits<ll>::max();
 
	bool first_boost = true;
 
	lower_bound = 0;
	upper_bound = x;
	while (upper_bound - lower_bound > 1)
	{
		if (first_boost)
		{
			ll guess = (ll)sqrt((double)x);
			lower_bound = max(guess - 1, (ll)0);
			upper_bound = lower_bound + 3;
			first_boost = false;
		}
 
		ll newval = (lower_bound + upper_bound) / 2;
		if ((newval != 0) && (newval > ll_max / newval))  // newval*newval becomes overflow
			upper_bound = newval;  // because overflow means newval is too big
		else
		{
			ll newval_sqr = newval * newval;
			if (newval_sqr < x)
				lower_bound = newval;
			else
				upper_bound = newval;
		}
	}
 
	if ((upper_bound != 0) && (upper_bound > ll_max / upper_bound))
	{
		if (lower_bound * lower_bound == x)
			upper_bound = lower_bound;
	}
	else
	{
		if (lower_bound * lower_bound == x)
			upper_bound = lower_bound;
		else if (upper_bound * upper_bound == x)
			lower_bound = upper_bound;
	}
	bool is_exact = (lower_bound == upper_bound);
	return is_exact;
}

ll ll_ceil(ll x, int digit);
ll ll_floor(ll x, int digit);


ll ll_floor(ll x, int digit)
{
	if (x < 0)
		return -ll_ceil(-x, digit);
 
	ll div = 1;
	while (digit != 0)
	{
		div *= 10;
		digit--;
	}
	ll modval = x % div;
	ll ans = x - modval;
	return ans;
}

ll ll_ceil(ll x, int digit)
{
	if (x < 0)
		return -ll_floor(-x, digit);
 
	ll div = 1;
	while (digit != 0)
	{
		div *= 10;
		digit--;
	}
	ll modval = x % div;
	ll ans = x - modval;
	if (modval != 0)
		ans += div;
	return ans;
}
int main() {
	ll M,H;
	cin >> M >> H;


	string ans = "No";
	
	if(H%M==0){
		ans="Yes";
	}

	
	cout << ans << endl;

  return 0;
}
#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(ll i=0;i<n;i++)
#define repl(i,l,r) for(ll i=(l);i<(r);i++)
#define per(i,n) for(ll i=(n)-1;i>=0;i--)
#define perl(i,r,l) for(ll i=r-1;i>=l;i--)
#define fi first
#define se second
#define pb push_back
#define ins insert
#define pqueue(x) priority_queue<x,vector<x>,greater<x>>
#define all(x) (x).begin(),(x).end()
#define CST(x) cout<<fixed<<setprecision(x)
#define rev(x) reverse(x);
using ll=long long;
using vl=vector<ll>;
using vvl=vector<vector<ll>>;
using pl=pair<ll,ll>;
using vpl=vector<pl>;
using vvpl=vector<vpl>;
const ll MOD=1000000007;
const ll MOD9=998244353;
const int inf=1e9+10;
const ll INF=4e18;
const ll dy[8]={-1,0,1,0,1,1,-1,-1};
const ll dx[8]={0,-1,0,1,1,-1,1,-1};
template <typename T> inline bool chmax(T &a, T b) {
  return ((a < b) ? (a = b, true) : (false));
}
template <typename T> inline bool chmin(T &a, T b) {
  return ((a > b) ? (a = b, true) : (false));
}

const int mod = 1000000007;
const int max_n = 200005;
struct mint {
  ll x; // typedef long long ll;
  mint(ll x=0):x((x%mod+mod)%mod){}
  mint operator-() const { return mint(-x);}
  mint& operator+=(const mint a) {
    if ((x += a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator-=(const mint a) {
    if ((x += mod-a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
  mint operator+(const mint a) const { return mint(*this) += a;}
  mint operator-(const mint a) const { return mint(*this) -= a;}
  mint operator*(const mint a) const { return mint(*this) *= a;}
  mint pow(ll t) const {
    if (!t) return 1;
    mint a = pow(t>>1);
    a *= a;
    if (t&1) a *= *this;
    return a;
  }
  bool operator==(const mint &p) const { return x == p.x; }
  bool operator!=(const mint &p) const { return x != p.x; }
  // for prime mod
  mint inv() const { return pow(mod-2);}
  mint& operator/=(const mint a) { return *this *= a.inv();}
  mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}

struct combination {
  vector<mint> fact, ifact;
  combination(int n):fact(n+1),ifact(n+1) {
    assert(n < mod);
    fact[0] = 1;
    for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
    ifact[n] = fact[n].inv();
    for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
  }
  mint operator()(int n, int k) {
    if (k < 0 || k > n) return 0;
    return fact[n]*ifact[k]*ifact[n-k];
  }
}comb(max_n);

int main(){
    ll n,p;cin >> n >>p;
    mint ans=p-1;
    cout << ans*(ans-1).pow(n-1) <<endl;
}   