#include<bits/stdc++.h>

#define ll long long
#define int long long
#define pb push_back
#define mp make_pair
#define eb emplace_back
#define fi first
#define se second
#define PI 3.1415926535897932384626433832795
#define MOD 1000000007

using namespace std;

//------------------------------------------------------------------------------
ll power(ll a,ll n)
{
          ll result=1;
          while(n>0)
          {
               if(n&1)
                    result=result*a;
               a=a*a;
               n=n>>1;
          }
          return result;
}
ll lcm(ll a,ll b)
{
          return ((a*b)/__gcd(a,b));
}
ll __ceil(ll a,ll b)
{
            return (a+b-1)/b;
}
bool ispow2(ll n)
{
          return (ceil(log2(n))==floor(log2(n)));
}
bool isprime(ll n)
{
          if(n==1)
               return false;
          else if(n==2)
               return true;
          else
          {
               for(ll i=2;i*i<=n;++i)
               {
                    if(n%i==0)
                         return false;
               }
               return true;
          }
}

ll ncr(ll n,ll r)
{
    if(r > n - r)
          r = n - r;
    ll ans = 1;
    ll i;

    for(i = 1; i <= r; i++)
     {
        ans *= n - r + i;
        ans /= i;
    }

    return ans;
}
void sieve(int n)
{
    // Create a boolean array "prime[0..n]" and initialize
    // all entries it as true. A value in prime[i] will
    // finally be false if i is Not a prime, else true.
    bool prime[n+1];
    memset(prime, true, sizeof(prime));
     prime[1]=false;
     prime[0]=false;
    for (int p=2; p*p<=n; p++)
    {
        // If prime[p] is not changed, then it is a prime
        if (prime[p] == true)
        {
            // Update all multiples of p greater than or
            // equal to the square of it
            // numbers which are multiple of p and are
            // less than p^2 are already been marked.
            for (int i=p*p; i<=n; i += p)
                prime[i] = false;
        }
    }

    // Print all prime numbers
    for (int p=2; p<=n; p++)
       if (prime[p])
          cout<<p<<" ";
}
//------------------------------------------------------------------------------


int32_t main()
{
          ios_base::sync_with_stdio(0);
          cin.tie(0);

          int t=1;
          //cin>>t;
          while(t--)
          {
                    int c;
                    cin>>c;
                    if(c>=0)
                         cout<<c;
                    else
                         cout<<0;
          }
          return 0;
}

#include <bits/stdc++.h>
using namespace std;

#define ms(s, n) memset(s, n, sizeof(s))
#define f(i, a, b) for (int i = (a); i <=(b); i++)
#define FORd(i, a, b) for (int i = (a) - 1; i >= (b); i--)
#define FORall(it, a) for (__typeof((a).begin()) it = (a).begin(); it != (a).end(); it++)
#define sz(a) int((a).size())
#define present(t, x) (t.find(x) != t.end())
#define all(a) (a).begin(), (a).end()
#define uni(a) (a).erase(unique(all(a)), (a).end())
#define pb push_back
#define pf push_front
#define mp make_pair
#define fi first
#define se second
#define prec(n) fixed<<setprecision(n)
#define bit(n, i) (((n) >> (i)) & 1)
#define bitcount(n) __builtin_popcountll(n)
#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int, int> pi;
typedef vector<ll> vi;
typedef vector<pi> vii;
const int MOD = (int) 1e9 + 7;
const int MOD2 = MOD + 2; //1007681537;
const int INF = (int) 1e9;
const ll LINF = (ll) 1e18;
const ld PI = acos((ld) - 1);
const ld EPS = 1e-9;
inline ll gcd(ll a, ll b) {ll r; while (b) {r = a % b; a = b; b = r;} return a;}
inline ll lcm(ll a, ll b) {return a / gcd(a, b) * b;}
inline ll fpow(ll n, ll k, int p = MOD) {ll r = 1; for (; k; k >>= 1) {if (k & 1) r = r * n % p; n = n * n % p;} return r;}
template<class T> inline int chkmin(T& a, const T& val) {return val < a ? a = val, 1 : 0;}
template<class T> inline int chkmax(T& a, const T& val) {return a < val ? a = val, 1 : 0;}
inline ll isqrt(ll k) {ll r = sqrt(k) + 1; while (r * r > k) r--; return r;}
inline ll icbrt(ll k) {ll r = cbrt(k) + 1; while (r * r * r > k) r--; return r;}
inline void addmod(int& a, int val, int p = MOD) {if ((a = (a + val)) >= p) a -= p;}
inline void submod(int& a, int val, int p = MOD) {if ((a = (a - val)) < 0) a += p;}
inline int mult(int a, int b, int p = MOD) {return (ll) a * b % p;}
inline int inv(int a, int p = MOD) {return fpow(a, p - 2, p);}
inline int sign(ld x) {return x < -EPS ? -1 : x > +EPS;}
inline int sign(ld x, ld y) {return sign(x - y);}
int modulo(int a, int b) { return (a % b + b) % b; }
#define db(x) cerr << #x << " = " << (x) << " ";
#define endln cerr << "\n";

int main()
{
	IOS;
#ifndef ONLINE_JUDGE
	freopen("input.txt", "r", stdin);
	freopen("output.txt", "w", stdout);
#endif
	ll n, ans;
	cin >> n;
	if (n >= 0) {
		ans = n;
	}
	else {
		ans = 0;
	}
	cout << ans << "\n";
	// read the stuff at the bottom
	return 0;
}
/* stuff you should look for
	* int overflow, array bounds
	* special cases (n=1?)
	* do smth instead of nothing and stay organized
	* WRITE STUFF DOWN
	* use int when constraints limits are tight
	* Time taken : global variable < pass by refernce < pass by value
	* It takes significant amt. of time in pass by value
	* Avoid Using endl
*/



























