#include <bits/stdc++.h>
#include <math.h>
using namespace std;
typedef long long ll;
typedef vector<int> vint;
#define rep(i,n) for (int i = 0; i < (int)(n); ++i)
int main(){
  int n,m; cin >> n >> m;
  cout << n/m << endl;
}
#include<bits/stdc++.h>
#define for_int(i,a,b) for(int i=(a);i<=(b);++i)
#define rep_int(i,a,b) for(int i=(a);i>=(b);--i)
#define for_ll(i,a,b) for(ll i=(a);i<=(b);++i)
#define rep_ll(i,a,b) for(ll i=(a);i>=(b);--i)
#define Ios ios::sync_with_stdio(false),cin.tie(0)
#define ull unsigned long long
#define ll long long
#define db double
#define HPMAX 1005
#define KMP_MAX 1005
#define prime_MAX 1000005
#define quick_pow_mod 1000000007
#define PII pair<int,int>
const int factor_N = 10000005;
const int tree_arr_N = 1000005;
using namespace std;
/*
	1.注意边界情况
	2.优先考虑时间复杂度
!!! 3.求最大值时，答案应至多初始化为INT_MIN；求最小值时，答案应至少初始化为INT_MAX
	4.遇事不决先暴力
	5.代码要写简洁
	6.计数题要开long long
*/
//快读
int read() {
	char c = getchar();
	int x = 0, f = 1;
	for (; !isdigit(c); c = getchar())
		if (c == '-') f = -1;
	for (; isdigit(c); c = getchar()) x = x * 10 + c - 48;
	return x * f;
}
int n, m;
int main() {
	Ios;
	cin >> n >> m;
	cout << n / m << endl;
	return 0;
}
