#include <bits/stdc++.h>
// #include <atcoder/all>
using namespace std;
// using namespace atcoder;
#define rep(i, n) for (int i = 0; i < (n); i++)
#define rep1(i, n) for (int i = 1; i <= (n); i++)
#define rrep(i, n) for (int i = n - 1; i >= 0; i--)
#define rrep1(i, n) for (int i = n; i >= 1; i--)
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define eb emplace_back
#define fi first
#define se second
#define sz(x) (int)(x).size()
template <class T> using V = vector<T>;
template <class T> using VV = V<V<T>>;
typedef long long int ll;
typedef pair<ll, ll> P;
// typedef modint1000000007 mint;

void speedUpIO() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
}

template <class T> bool chmax(T &a, const T &b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}
template <class T> bool chmin(T &a, const T &b) {
    if (b < a) {
        a = b;
        return true;
    }
    return false;
}
/*--------------------------------------------------*/
const int INF = 1e9;
const ll LINF = 2e18;
const int MAX = 100010;

void solve() {
    ll k, n, m;
    cin >> k >> n >> m;
    V<ll> a(k);
    rep(i, k) cin >> a[i];
    V<ll> b(k);
    rep(i, k) b[i] = a[i] * m / n;
    ll d = m - accumulate(all(b), 0LL);
    V<P> bp(k);
    rep(i, k) bp[i] = P(m * a[i] % n, i);
    sort(rall(bp));
    rep(i, d) {
        int j = bp[i].se;
        b[j]++;
    }
    rep(i, k) {
        cout << b[i] << " ";
    }
    cout << "\n";
}

int main() {
    speedUpIO();
    int t = 1;
    // cin >> t;
    while (t--) {
        solve();
        // cout << solve() << "\n";
        // cout << (solve() ? "Yes" : "No") << "\n";
        // cout << fixed << setprecision(15) << solve() << "\n";
    }
    return 0;
}

//#pragma GCC optimize ("O2")
//#pragma GCC target ("avx2")
//#include<bits/stdc++.h>
//#include<atcoder/all>
//using namespace atcoder;

#include<cstdio>
#include<cstring>

using namespace std;
typedef long long ll;
#define rep(i, n) for(int i = 0; i < (n); i++)
#define rep1(i, n) for(int i = 1; i <= (n); i++)
#define co(x) cout << (x) << "\n"
#define cosp(x) cout << (x) << " "
#define ce(x) cerr << (x) << "\n"
#define cesp(x) cerr << (x) << " "
#define pb push_back
#define mp make_pair
#define chmin(x, y) x = min(x, y)
#define chmax(x, y) x = max(x, y)
#define Would
#define you
#define please

const int CM = 1 << 17, CL = 12;
char cn[CM + CL], * ci = cn + CM + CL, * owa = cn + CM, ct;
const ll ma0 = 1157442765409226768;
const ll ma1 = 1085102592571150095;
const ll ma2 = 71777214294589695;
const ll ma3 = 281470681808895;
const ll ma4 = 4294967295;
inline int getint() {
	if (ci - owa > 0) {
		memcpy(cn, owa, CL);
		ci -= CM;
		fread(cn + CL, 1, CM, stdin);
	}
	ll tmp = *(ll*)ci;
	if ((tmp & ma0) ^ ma0) {
		int dig = 68 - __builtin_ctzll((tmp & ma0) ^ ma0);
		tmp = tmp << dig & ma1;
		tmp = tmp * 10 + (tmp >> 8) & ma2;
		tmp = tmp * 100 + (tmp >> 16) & ma3;
		tmp = tmp * 10000 + (tmp >> 32) & ma4;
		ci += (72 - dig >> 3);
	}
	else {
		tmp = tmp & ma1;
		tmp = tmp * 10 + (tmp >> 8) & ma2;
		tmp = tmp * 100 + (tmp >> 16) & ma3;
		tmp = tmp * 10000 + (tmp >> 32) & ma4;
		ci += 8;
		if ((ct = *ci++) >= '0') {
			tmp = tmp * 10 + ct - '0';
			if (*ci++ == '0') {
				tmp = tmp * 10;
				ci++;
			}
		}
	}
	return tmp;
}
int tmp[200001];
void pakuri_sort(int N, int A[]) {
	const int b = 8;
	rep(k, 4) {
		int kazu[1 << b] = {}, kazu2[1 << b] = {};
		rep(i, N) kazu[A[i] >> k * b & ((1 << b) - 1)]++;
		rep(i, (1 << b) - 1) kazu[i + 1] += kazu[i];
		for (int i = N - 1; i >= 0; i--) tmp[--kazu[A[i] >> k * b & ((1 << b) - 1)]] = A[i];
		k++;
		rep(i, N) kazu2[tmp[i] >> k * b & ((1 << b) - 1)]++;
		rep(i, (1 << b) - 1) kazu2[i + 1] += kazu2[i];
		for (int i = N - 1; i >= 0; i--) A[--kazu2[tmp[i] >> k * b & ((1 << b) - 1)]] = tmp[i];
	}
}

int main() {
	//cin.tie(0);
	//ios::sync_with_stdio(false);


	int N = getint(), M = getint();

	int A[200010];
	rep1(i, M) A[i] = getint();
	A[0] = 0;
	A[M + 1] = N + 1;
	pakuri_sort(M, A + 1);

	int mae = 0;
	int saishou = 2e9;
	int t = 0;
	rep(i, M + 1) {
		int kari = A[i + 1] - A[i] - 1;
		if (kari) {
			if (kari < saishou) saishou = kari;
			tmp[t++] = kari;
		}
	}

	if (saishou > 1.5e9) {
		printf("0");
		return 0;
	}

	ll kotae = 0;
	rep(i, t) kotae += (tmp[i] + saishou - 1) / saishou;

	printf("%d\n", kotae);

	Would you please return 0;
}