#include <bits/stdc++.h>
#define rep(i,n) for (int i = 0; i < (n); ++i)
#define REP(i,m,n) for (int i = (m); i < (n); ++i)
#define rrep(i,n) for (int i = (n)-1; i >= 0; --i)
#define RREP(i,m,n) for (int i = (n)-1; i >= (m); ++i)
#define all(a) (a).begin(),(a).end()
#define rall(a) (a).rbegin(),(a).rend()
using namespace std;
using ll = long long int;
using vec = vector<int>;
using P = pair<int,int>;

const ll mod = 1e9+7;
struct mint {
  ll x; // typedef long long ll;
  mint(ll x=0):x((x%mod+mod)%mod){}
  mint operator-() const { return mint(-x);}
  mint& operator+=(const mint a) {
    if ((x += a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator-=(const mint a) {
    if ((x += mod-a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
  mint operator+(const mint a) const { return mint(*this) += a;}
  mint operator-(const mint a) const { return mint(*this) -= a;}
  mint operator*(const mint a) const { return mint(*this) *= a;}
  mint pow(ll t) const {
    if (!t) return 1;
    mint a = pow(t>>1);
    a *= a;
    if (t&1) a *= *this;
    return a;
  }

  // for prime mod
  mint inv() const { return pow(mod-2);}
  mint& operator/=(const mint a) { return *this *= a.inv();}
  mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}

const int MAX_N = 2e6+10;
struct combination {
  vector<mint> fact, ifact;
  combination(int n):fact(n+1),ifact(n+1) {
    assert(n < mod);
    fact[0] = 1;
    for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
    ifact[n] = fact[n].inv();
    for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
  }
  mint operator()(int n, int k) {
    if (k < 0 || k > n) return 0;
    return fact[n]*ifact[k]*ifact[n-k];
  }
} comb(MAX_N);

int main() {
  int n, m, k; cin >> n >> m >> k;

  if (n < k+1) {
    cout << comb(m+n, m) << endl;
  } else if (n <= m+k) {
    cout << comb(m+n, m) - comb(m+n, m+k+1) << endl;
  } else {
    cout << 0 << endl;
  }
}

#define _CRT_SECURE_NO_WARNINGS
#include<cstdio>
#include<vector>
#include<functional>
#include<algorithm>
#include<stdlib.h>
#include<string>
#include<string.h>
#define _USE_MATH_DEFINES
#include<math.h>
#include<deque>
#include<set>
#include<map>
#include<queue>
#include<list>
#include<iostream>
#include <bitset>
using namespace std;
typedef long long ll;
#define rep(i,a,b) for(auto i=a;i<b;i++)
#define rep2(i, a)for(auto i : a)
#define all(_x) _x.begin(), _x.end()
#define r_sort(_x) sort(_x, std::greater<int>())
#define vec_cnt(_a, _n) (upper_bound(all(_a), _n) - lower_bound(all(_a), _n))
#define vec_unique(_a) _a.erase(std::unique(all(_a)), _a.end());
#define vvec vector<vector<ll>>
#define INF (1ll << 60)
ll mod = 1000000007;
ll gcd(ll a, ll b) { return a % b == 0 ? b : gcd(b, a % b); }
ll lcm(ll a, ll b) { return (a / gcd(a, b)) * b; }
ll power(ll x, ll p) { ll a = 1; while (p > 0) { if (p & 1)a *= x; x *= x; p >>= 1; }return a; }
ll mpower(ll x, ll p) { ll a = 1; while (p > 0) { if (p & 1)a = a * x % mod;  x = x * x % mod; p >>= 1; }return a; }
ll co(ll n, ll k) { ll a = 1; rep(i, 1ll, k + 1) { a *= n - i + 1; a /= i; }return a; }
ll mc(ll n, ll m) { ll k = 1, l = 1; rep(i, n - m + 1, n + 1) k = k * i % mod; rep(i, 1, m + 1) l = l * i % mod; l = mpower(l, mod - 2); return k * l % mod; }
ll modinv(ll a) { ll b = mod, u = 1, v = 0; while (b) { ll t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); }u %= mod; if (u < 0) u += mod; return u; }

int main(void) {
	int n, k;
	cin >> n >> k;
	vector<vector<int>> a(n, vector<int>(n));
	int r = 0, l = 0;
	rep(i, 0, n)rep(j, 0, n)cin >> a[i][j], r = max(r, a[i][j]);
	while (r - l > 1) {
		int m = (r - l) / 2 + l;
		vector<vector<int>> s(n + 1, vector<int>(n + 1));
		rep(i, 0, n) {
			rep(j, 0, n) {
				if (a[i][j] > m)s[i + 1][j + 1] = 1;
				s[i + 1][j + 1] += s[i][j + 1] + s[i + 1][j] - s[i][j];
			}
		}
		bool ok = false;
		rep(x, 0, n - k + 1) {
			rep(y, 0, n - k + 1) {
				if (s[x + k][y + k] - s[x][y + k] - s[x + k][y] + s[x][y] < k * k / 2 + 1) {
					ok = true;
					break;
				}
			}
			if (ok)break;
		}
		if (ok)r = m;
		else l = m;
	}
	printf("%d\n", r);
	return 0;
}