#include <iostream>
#include <vector>
#include <deque>
#include <algorithm>
#include <numeric>
#include <string>
#include <cstring>
#include <list>
#include <unordered_set>
#include <tuple>
#include <cmath>
#include <limits>
#include <type_traits>
#include <iomanip>
#include <map>
#include <unordered_map>
#include <queue>
#include <stack>
#include <set>
#include <bitset>
#include <regex>
#include <random>
#include<bits/stdc++.h>
//#include<atcoder/all>


using namespace std;
//using namespace atcoder;

typedef long long ll;
#define rep(i,n)for(ll i=0;i<n;++i)
#define exout(x) printf("%.12f\n", x)
const double pi = acos(-1.0);
const ll MOD = 1000000007;
const ll INF = 1e18;
const ll MAX_N = 1010101;

//組み合わせの余りを求める
ll fac[MAX_N], finv[MAX_N], inv[MAX_N];
void COMinit() {
	fac[0] = fac[1] = 1;
	finv[0] = finv[1] = 1;
	inv[1] = 1;
	for (int i = 2; i < MAX_N; i++) {
		fac[i] = fac[i - 1] * i % MOD;
		inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD;
		finv[i] = finv[i - 1] * inv[i] % MOD;
	}
}

// 二項係数計算
long long COM(ll n, ll k) {
	if (n < k) return 0;
	if (n < 0 || k < 0) return 0;
	return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}

// mod.m での a の逆元 a^ { -1 } を計算する
long long modinv(long long a, long long m) {
	long long b = m, u = 1, v = 0;
	while (b) {
		long long t = a / b;
		a -= t * b; swap(a, b);
		u -= t * v; swap(u, v);
	}
	u %= m;
	if (u < 0) u += m;
	return u;
}

//最大公約数
ll gcd(ll x, ll y) {
	return y ? gcd(y, x % y) : x;
}

ll lcm(ll x, ll y) {
	if (x == 0 || y == 0)return 0;
	return (x / gcd(x, y) * y);
}

//union-find木について
ll par[101010];
ll rank2[101010];

void init(ll n) {
	rep(i, n) {
		par[i] = i;
		rank2[i] = 0;
	}
}

ll find(ll x) {
	if (par[x] == x) {
		return x;
	}
	else {
		return par[x] = find(par[x]);
	}
}

void unite(ll x, ll y) {
	x = find(x);
	y = find(y);
	if (x == y)return;
	if (rank2[x] < rank2[y]) {
		par[x] = y;
	}
	else {
		par[y] = x;
		if (rank2[x] == rank2[y]) {
			rank2[x]++;
		}
	}
}


ll dx[4] = { 1,-1,0,0 };
ll dy[4] = { 0,0,1,-1 };
ll move[201010];

//long longしか使わない
//素数は1より大きい
//lower_boundは指定したkey以上の要素の一番左のイテレータをかえす
//upper_boundは指定したkeyより大きい要素の一番左のイテレータをかえす
int main() {
	ll ans = INF;
	rep(i, 4) {
		ll a;
		cin >> a;
		ans = min(ans, a);
	}
	cout << ans << endl;
	return 0;
}
#include <iostream>
#include <math.h>


using namespace std;

const int COUNT_A = 100;

int a[4];
int n = 0;

int min(int a, int b) {

    if (a > b) {
        return b;
    }
    return a;
}

int main() {
    
    

    cin >> a[0] >> a[1] >> a[2] >> a[3];
    n = min(a[0], min(a[1], min(a[2], a[3])));
    printf("%d",n);

}