#include <bits/stdc++.h>
#define FOR(i, a, b) for (int i = (a); i <= (b); i++)
#define rep(i, n) FOR(i, 0, n - 1)
using namespace std;
typedef long long ll;
template <class T>
inline bool dpmin(T& a, T b)
{
    if (a > b)
    {
        a = b;
        return 1;
    }
    return 0;
}
template <class T>
inline bool dpmax(T& a, T b)
{
    if (a < b)
    {
        a = b;
        return 1;
    }
    return 0;
}

void solve(long long N) {
    ll ans;

    if (1 <= N && N <= 100) {
        ans = 1;
    } else {
        for (ll c = 1; c <= 30; c++) {
            if (c * 100 + 1 <= N && N <= (c+1) * 100){
                ans = c + 1;
                break;
            }
        }
    }

    cout << ans << endl;
}

// Generated by 2.3.1 https://github.com/kyuridenamida/atcoder-tools  (tips: You use the
// default template now. You can remove this line by using your custom template)
int main()
{
    long long N;
    std::scanf("%lld", &N);
    solve(N);
    return 0;
}

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef pair<ll, ll> pll;
using Graph = vector<vector<ll>>;
#define all(x) (x).begin(), (x).end() //string の sort とかはこれ
#define rep(i, n) for (int(i) = 0; (i) < (n); (i)++)

const ll MOD = 1000000007;
const ll INF = 1e18;                    //1*10^18
const double PI = 3.141592653589793238; //18桁
const ll MAX = 1e6;
long long fac[MAX], finv[MAX], inv[MAX];

int ctoi(char c)
{
  if (c >= '0' && c <= '9')
  {
    return c - '0';
  }
  return 0;
}

ll gcd(ll x, ll y) { return (x % y) ? gcd(y, x % y) : y; }
//最大公約数
ll lcm(ll x, ll y) { return x / gcd(x, y) * y; }
//最小公倍数

ll powll(ll a, ll n)
{ //O(log n)
  ll res = 1;
  while (n > 0)
  {
    if (n & 1) //(n & 1)=(n % 2 !=0)
    {
      res = res * a;
    }
    a = a * a;
    n >>= 1; //(n & 1)=(n % 2 !=0)
  }
  return res;
}

ll modpow(ll a, ll n, ll mod) //O(log n)
{
  ll res = 1;
  while (n > 0)
  {
    if (n & 1) //(n & 1)=(n % 2 !=0)
    {
      res = res * a % mod;
    }
    a = a * a % mod;
    n >>= 1; //(n>>=1)=(n/2)
  }
  return res;
}

int ReturnDigit(ll num)
{
  string number = to_string(num);
  return number.length();
}

// テーブルを作る前処理
void COMinit() //MODは素数じゃないとだよ！！
{
  fac[0] = fac[1] = 1;
  finv[0] = finv[1] = 1;
  inv[1] = 1;
  for (int i = 2; i < MAX; i++)
  {
    fac[i] = fac[i - 1] * i % MOD;
    inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD;
    finv[i] = finv[i - 1] * inv[i] % MOD;
  }
}

// 二項係数計算
long long COM(int n, int k)
{
  if (n < k)
    return 0;
  if (n < 0 || k < 0)
    return 0;
  return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}

struct UnionFind
{
  vector<int> par; // par[i]:iの親の番号　(例) par[3] = 2 : 3の親が2

  UnionFind(int N) : par(N)
  { //最初は全てが根であるとして初期化
    for (int i = 0; i < N; i++)
      par[i] = i;
  }

  int root(int x)
  { // データxが属する木の根を再帰で得る：root(x) = {xの木の根}
    if (par[x] == x)
      return x;
    return par[x] = root(par[x]);
  }

  void unite(int x, int y)
  {                   // xとyの木を併合
    int rx = root(x); //xの根をrx
    int ry = root(y); //yの根をry
    if (rx == ry)
      return;     //xとyの根が同じ(=同じ木にある)時はそのまま
    par[rx] = ry; //xとyの根が同じでない(=同じ木にない)時：xの根rxをyの根ryにつける
  }

  bool same(int x, int y)
  { // 2つのデータx, yが属する木が同じならtrueを返す
    int rx = root(x);
    int ry = root(y);
    return rx == ry;
  }
};

int main()
{
  // COMinit();
  // srand((unsigned int)time(NULL));//--> rand()
  ll i, j, k, l, ans=0;
  ll n;
  cin >> n;

if(n%100==0)
{
    ans=n/100;
}else
{
    ans=n/100+1;
}
  cout << ans << endl;
}