{ | |
"problem": "How many $3$-digit squares are palindromes?", | |
"level": "Level 3", | |
"type": "Number Theory", | |
"solution": "The last digit of a square must be either $1$, $4$, $5$, $6$, or $9$. Therefore, we only need to consider these squares. Only one square begins and ends with $1: 121$. Similarly, one square begins and ends with $4: 484$. No square begins and ends with $5$. One square begins and ends with $6: 676$. No square begins and ends with $9$. Therefore, there are $\\boxed{3}$ squares which are $3$-digit palindromes." | |
} |