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{
"problem": "How many $3$-digit squares are palindromes?",
"level": "Level 3",
"type": "Number Theory",
"solution": "The last digit of a square must be either $1$, $4$, $5$, $6$, or $9$. Therefore, we only need to consider these squares. Only one square begins and ends with $1: 121$. Similarly, one square begins and ends with $4: 484$. No square begins and ends with $5$. One square begins and ends with $6: 676$. No square begins and ends with $9$. Therefore, there are $\\boxed{3}$ squares which are $3$-digit palindromes."
}